Template:List of mesons

From formulasearchengine
Jump to navigation Jump to search

In the mathematics of coding theory, the Griesmer bound, named after James Hugo Griesmer, is a bound on the length of binary codes of dimension k and minimum distance d. There is also a very similar version for non-binary codes.

Statement of the bound

For a binary linear code, the Griesmer bound says:

n≥∑i=0k−1⌈d2i⌉.

Proof

Let N(k,d) denote the minimum length of a binary code of dimension k and distance d. Let C be such a code. We want to show that N(k,d)≥∑i=0k−1⌈d2i⌉.

Let G be a generator matrix of C. We can always suppose that the first row of G is of the form r = (1, ..., 1, 0, ..., 0) with weight d.

G=[1…10…0∗∗∗G′]

The matrix G' generates a code C', which is called the residual code of C. C' has obviously dimension k′=k−1 and length n′=N(k,d)−d. C' has a distance d', but we don't know it. Let u∈C′ s.t. w(u)=d′. There exists a vector v∈(F2)d s.t. the concatenation (v|u)∈C. Then w(v)+w(u)=w(v|u)≥d. On the other hand, also (v|u)+r∈C, since r∈C and C is linear, so w((v|u)+r)≥d. But

w((v|u)+r)=w(((1,1,...,1)+v)|u)=d−w(v)+w(u),

so this becomes d−w(v)+w(u)≥d. By summing this with w(v)+w(u)≥d, we obtain d+2w(u)≥2d. But w(u)=d′, so we get d′≥d/2. This implies n′≥N(k−1,d/2), therefore n′≥⌈N(k−1,d/2)⌉ (due to the integrality of n'), so that N(k,d)≥⌈N(k−1,d/2)⌉+d. By induction over k we will eventually get N(k,d)≥∑i=0k−1⌈d2i⌉ (note that at any step the dimension decreases by 1 and the distance is halved, and we use the identity ⌈⌈a/2k−1⌉2⌉=⌈a2k⌉ for any integer a and positive integer k).

The bound for the general case

For a linear code over Fq, the Griesmer bound becomes:

n≥∑i=0k−1⌈dqi⌉.

The proof is similar to the binary case and so it is omitted.

See also

References

  • J. H. Griesmer, "A bound for error-correcting codes," IBM Journal of Res. and Dev., vol. 4, no. 5, pp. 532-542, 1960.