Consistency (suspension)

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In algebra, Zariski's lemma, introduced by Oscar Zariski, states that if K is a finitely generated algebra over a field k and if K is a field, then K is a finite field extension of k.

An important application of the lemma is a proof of the weak form of Hilbert's nullstellensatz:[1] if I is a proper ideal of k[t1,...,tn] (k algebraically closed field), then I has a zero; i.e., there is a point x in kn such that f(x)=0 for all f in I.[2]

The lemma may also be understood from the following perspective. In general, a ring R is a Jacobson ring if and only if every finitely generated R-algebra that is a field is finite over R.[3] Thus, the lemma follows from the fact that a field is a Jacobson ring.

Proof

Two direct proofs, one of which is due to Zariski, are given in Atiyah–MacDonald.[4][5] The lemma is also a consequence of the Noether normalization lemma. Indeed, by the normalization lemma, K is a finite module over the polynomial ring k[x1,,xd] where x1,,xd are algebraically independent over k. But since K has Krull dimension zero, the polynomial ring must have dimension zero; i.e., d=0.

In fact, the lemma is a special case of the general formula dimA=tr.degkA for a finitely generated k-algebra A that is an integral domain, which is also a consequence of the normalization lemma.

Notes

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References

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  2. Proof: it is enough to consider a maximal ideal m. Let A=k[t1,...,tn] and ϕ:AA/m be the natural surjection. By the lemma, A/m=k and then for any fm,
    f(ϕ(t1),,ϕ(tn))=ϕ(f(t1,,tn))=0;
    that is to say, x=(ϕ(t1),,ϕ(tn)) is a zero of m.
  3. Template:Harvnb
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