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| | In [[mathematics]], '''Hadamard's lemma''', named after [[Jacques Hadamard]], is essentially a first-order form of [[Taylor's theorem]], in which we can express a smooth, real-valued function exactly in a convenient manner. |
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| | ==Statement== |
| | Let ƒ be a smooth, real-valued function defined on an open, [[star-convex]] neighborhood ''U'' of a point ''a'' in ''n''-dimensional Euclidean space. Then ƒ(''x'') can be expressed, for all ''x'' in ''U'', in the form: |
| | |
| | :<math>f(x)=f(a)+\sum_{i=1}^n (x_i-a_i) g_i(x),</math> |
| | |
| | where each ''g<sub>i</sub>'' is a smooth function on ''U'', ''a'' = (''a''<sub>1</sub>,...,''a''<sub>''n''</sub>), and ''x'' = (''x''<sub>1</sub>,...,''x''<sub>''n''</sub>). |
| | |
| | ==Proof== |
| | Let ''x'' be in ''U''. Let ''h'' be the map from [0,1] to the real numbers defined by |
| | |
| | :<math>h(t)=f(a+t(x-a)).\,</math> |
| | |
| | Then since |
| | |
| | :<math>h'(t)=\sum_{i=1}^n \frac{\partial f}{\partial x_i}(a+t(x-a)) (x_i-a_i),</math> |
| | |
| | we have |
| | |
| | :<math>h(1)-h(0)=\int_0^1 h'(t)\,dt |
| | =\int_0^1 \sum_{i=1}^n \frac{\partial f}{\partial x_i}(a+t(x-a)) (x_i-a_i)\, dt |
| | =\sum_{i=1}^n (x_i-a_i)\int_0^1 \frac{\partial f}{\partial x_i}(a+t(x-a))\, dt. </math> |
| | |
| | But additionally, ''h''(1) − ''h''(0) = ''f''(''x'') − ''f''(''a''), so if we let |
| | |
| | :<math>g_i(x)=\int_0^1 \frac{\partial f}{\partial x_i}(a+t(x-a))\, dt,</math> |
| | |
| | we have proven the theorem. |
| | |
| | ==References== |
| | *{{cite book |author=Nestruev, Jet |title=Smooth manifolds and observables |publisher=Springer |location=Berlin |year=2002 |pages= |isbn=0-387-95543-7 |oclc= |doi=}} |
| | |
| | [[Category:Real analysis]] |
| | [[Category:Theorems in analysis]] |
In mathematics, Hadamard's lemma, named after Jacques Hadamard, is essentially a first-order form of Taylor's theorem, in which we can express a smooth, real-valued function exactly in a convenient manner.
Statement
Let ƒ be a smooth, real-valued function defined on an open, star-convex neighborhood U of a point a in n-dimensional Euclidean space. Then ƒ(x) can be expressed, for all x in U, in the form:
where each gi is a smooth function on U, a = (a1,...,an), and x = (x1,...,xn).
Proof
Let x be in U. Let h be the map from [0,1] to the real numbers defined by
Then since
we have
But additionally, h(1) − h(0) = f(x) − f(a), so if we let
we have proven the theorem.
References
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