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		<id>https://en.formulasearchengine.com/w/index.php?title=Compactly_generated_group&amp;diff=5745</id>
		<title>Compactly generated group</title>
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		<summary type="html">&lt;p&gt;173.48.162.80: some formatting, note distinction from compactly generated space&lt;/p&gt;
&lt;hr /&gt;
&lt;div&gt;In [[number theory]], &#039;&#039;&#039;quadratic Gauss sums&#039;&#039;&#039; are certain finite sums of roots of unity. A quadratic Gauss sum can be interpreted as a linear combination of the values of the complex [[exponential function]] with coefficients given by a quadratic character; for a general character, one obtains a more general [[Gauss sum]]. These objects are named after [[Carl Friedrich Gauss]], who studied them extensively and applied them to [[quadratic reciprocity|quadratic]], [[cubic reciprocity|cubic]], and [[biquadratic reciprocity|biquadratic]] reciprocity laws.&lt;br /&gt;
&lt;br /&gt;
== Definition ==&lt;br /&gt;
&lt;br /&gt;
Let &#039;&#039;p&#039;&#039; be an odd [[prime number]] and &#039;&#039;a&#039;&#039; an integer. Then the &#039;&#039;&#039;Gauss sum&#039;&#039;&#039; mod &#039;&#039;p&#039;&#039;, &#039;&#039;g&#039;&#039;(&#039;&#039;a&#039;&#039;;&#039;&#039;p&#039;&#039;), is the following sum of the &#039;&#039;p&#039;&#039;th [[root of unity|roots of unity]]:&lt;br /&gt;
&lt;br /&gt;
: &amp;lt;math&amp;gt; g(a;p) =\sum_{n=0}^{p-1}e^{2{\pi}ian^2/p}=\sum_{n=0}^{p-1}\zeta_p^{an^2}, &lt;br /&gt;
\quad \zeta_p=e^{2{\pi}i/p}. &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
If &#039;&#039;a&#039;&#039; is not divisible by &#039;&#039;p&#039;&#039;, an alternative expression for the Gauss sum (with the same value) is&lt;br /&gt;
&lt;br /&gt;
: &amp;lt;math&amp;gt;G(a,\chi)=\sum_{n=1}^{p-1}\left(\frac{n}{p}\right)e^{2{\pi}ian/p}. &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Here &amp;lt;math&amp;gt;\chi(n)=\left(\frac{n}{p}\right)&amp;lt;/math&amp;gt; is the [[Legendre symbol]], which is a quadratic character mod &#039;&#039;p&#039;&#039;. An analogous formula with a general character &#039;&#039;&amp;amp;chi;&#039;&#039; in place of the Legendre symbol defines the [[Gauss sum]] &#039;&#039;G&#039;&#039;(&#039;&#039;&amp;amp;chi;&#039;&#039;).&lt;br /&gt;
&lt;br /&gt;
=== Properties ===&lt;br /&gt;
&lt;br /&gt;
* The value of the Gauss sum is an [[algebraic integer]] in the &#039;&#039;p&#039;&#039;th [[cyclotomic field]] &#039;&#039;&#039;Q&#039;&#039;&#039;(&#039;&#039;&amp;amp;zeta;&#039;&#039;&amp;lt;sub&amp;gt;&#039;&#039;p&#039;&#039;&amp;lt;/sub&amp;gt;).&lt;br /&gt;
&lt;br /&gt;
* The evaluation of the Gauss sum can be reduced to the case &#039;&#039;a&#039;&#039; = 1:&lt;br /&gt;
&lt;br /&gt;
: &amp;lt;math&amp;gt; g(a;p)=\left(\frac{a}{p}\right)g(1;p). &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
* The exact value of the Gauss sum, computed by Gauss, is given by the formula&lt;br /&gt;
&lt;br /&gt;
:: &amp;lt;math&amp;gt; g(1;p) =\sum_{n=0}^{p-1}e^{2{\pi}in^2/p}=&lt;br /&gt;
\begin{cases} &lt;br /&gt;
\sqrt{p} &amp;amp; p\equiv 1\mod 4 \\ i\sqrt{p} &amp;amp; p\equiv 3\mod 4 &lt;br /&gt;
\end{cases}.&amp;lt;/math&amp;gt;&lt;br /&gt;
: The fact that &amp;lt;math&amp;gt;g(a;p)^2=\left(\frac{-1}{p}\right)p&amp;lt;/math&amp;gt;   was easy to prove and led to one of Gauss&#039;s [[proofs of quadratic reciprocity]]. However, the determination of the &#039;&#039;sign&#039;&#039; of the Gauss sum turned out to be considerably more difficult: Gauss could only establish it after several years&#039; work. Later, [[Peter Gustav Lejeune Dirichlet]], [[Leopold Kronecker]], [[Issai Schur]] and other mathematicians found different proofs.&lt;br /&gt;
&lt;br /&gt;
== Generalized quadratic Gauss sums ==&lt;br /&gt;
&lt;br /&gt;
Let &#039;&#039;a&#039;&#039;,&#039;&#039;b&#039;&#039;,&#039;&#039;c&#039;&#039; be [[natural numbers]]. The &#039;&#039;&#039;generalized Gauss sum&#039;&#039;&#039; &#039;&#039;G&#039;&#039;(&#039;&#039;a&#039;&#039;,&#039;&#039;b&#039;&#039;,&#039;&#039;c&#039;&#039;) is defined by&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;G(a,b,c)=\sum_{n=0}^{c-1} e\left(\frac{a n^2+bn}{c}\right),&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
where &#039;&#039;e&#039;&#039;(&#039;&#039;x&#039;&#039;) is the exponential function exp(2πi&#039;&#039;x&#039;&#039;). The classical Gauss sum is the sum &amp;lt;math&amp;gt;G(a,c)=G(a,0,c)&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
=== Properties ===&lt;br /&gt;
&lt;br /&gt;
*The Gauss sum &#039;&#039;G&#039;&#039;(&#039;&#039;a&#039;&#039;,&#039;&#039;b&#039;&#039;,&#039;&#039;c&#039;&#039;) depends only on the [[residue class]] of &#039;&#039;a&#039;&#039;,&#039;&#039;b&#039;&#039; modulo &#039;&#039;c&#039;&#039;.&lt;br /&gt;
&lt;br /&gt;
*Gauss sums are [[multiplicative function|multiplicative]], i.e. given natural numbers &#039;&#039;a&#039;&#039;, &#039;&#039;b&#039;&#039;, &#039;&#039;c&#039;&#039; and &#039;&#039;d&#039;&#039; with [[greatest common divisor|gcd]](&#039;&#039;c&#039;&#039;,&#039;&#039;d&#039;&#039;) =1 one has&lt;br /&gt;
&lt;br /&gt;
:&#039;&#039;G&#039;&#039;(&#039;&#039;a&#039;&#039;,&#039;&#039;b&#039;&#039;,&#039;&#039;cd&#039;&#039;)=&#039;&#039;G&#039;&#039;(&#039;&#039;ac&#039;&#039;,&#039;&#039;b&#039;&#039;,&#039;&#039;d&#039;&#039;)&#039;&#039;G&#039;&#039;(&#039;&#039;ad&#039;&#039;,&#039;&#039;b&#039;&#039;,&#039;&#039;c&#039;&#039;).&lt;br /&gt;
&lt;br /&gt;
This is a direct consequence of the [[Chinese remainder theorem]].&lt;br /&gt;
&lt;br /&gt;
*One has &#039;&#039;G&#039;&#039;(&#039;&#039;a&#039;&#039;,&#039;&#039;b&#039;&#039;,&#039;&#039;c&#039;&#039;)=&#039;&#039;0&#039;&#039; if gcd(&#039;&#039;a&#039;&#039;,&#039;&#039;c&#039;&#039;)&amp;gt;1 except if gcd(&#039;&#039;a&#039;&#039;,&#039;&#039;c&#039;&#039;) divides &#039;&#039;b&#039;&#039; in which case one has&lt;br /&gt;
:&amp;lt;math&amp;gt;&lt;br /&gt;
G(a,b,c)= \gcd(a,c) \cdot G\left(\frac{a}{\gcd(a,c)},\frac{b}{\gcd(a,c)},\frac{c}{\gcd(a,c)}\right)&lt;br /&gt;
&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Thus in the evaluation of quadratic Gauss sums one may always assume gcd(&#039;&#039;a&#039;&#039;,&#039;&#039;c&#039;&#039;)=&#039;&#039;1&#039;&#039;.&lt;br /&gt;
&lt;br /&gt;
*Let &#039;&#039;a&#039;&#039;,&#039;&#039;b&#039;&#039; and &#039;&#039;c&#039;&#039; be integers with &amp;lt;math&amp;gt;ac\neq 0&amp;lt;/math&amp;gt; and &#039;&#039;ac+b&#039;&#039; even. One has the following analogue of the [[quadratic reciprocity]] law for (even more general) Gauss sums&lt;br /&gt;
:&amp;lt;math&amp;gt;&lt;br /&gt;
\sum_{n=0}^{|c|-1} e^{\pi i (a n^2+bn)/c} = |c/a|^{1/2} e^{\pi i (|ac|-b^2)/(4ac)} \sum_{n=0}^{|a|-1} e^{-\pi i (c n^2+b n)/a}. &lt;br /&gt;
&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
*Define &amp;lt;math&amp;gt; \varepsilon_m = \begin{cases} 1 &amp;amp; m\equiv 1\mod 4 \\ i &amp;amp; m\equiv 3\mod 4 \end{cases}&amp;lt;/math&amp;gt; for every odd integer &#039;&#039;m&#039;&#039;.&lt;br /&gt;
&lt;br /&gt;
The values of Gauss sums with &#039;&#039;b=0&#039;&#039; and gcd(&#039;&#039;a&#039;&#039;,&#039;&#039;c&#039;&#039;)=&#039;&#039;1&#039;&#039; are explicitly given by&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;&lt;br /&gt;
G(a,c) = G(a,0,c) = \begin{cases} 0 &amp;amp; c\equiv 2\mod 4 \\ \varepsilon_c \sqrt{c} \left(\frac{a}{c}\right) &amp;amp; c\ \text{odd} \\&lt;br /&gt;
(1+i) \varepsilon_a^{-1} \sqrt{c} \left(\frac{c}{a}\right) &amp;amp; a\ \text{odd}, 4\mid c.\end{cases}&lt;br /&gt;
&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Here &amp;lt;math&amp;gt; \left(\frac{a}{c}\right)&amp;lt;/math&amp;gt; is the [[Jacobi symbol]]. This is the famous formula of [[Carl Friedrich Gauß]].&lt;br /&gt;
&lt;br /&gt;
* For &#039;&#039;b&#039;&#039;&amp;gt;&#039;&#039;0&#039;&#039; the Gauss sums can easily be computed by [[completing the square]] in most cases. This fails however in some cases (for example &#039;&#039;c&#039;&#039; even and &#039;&#039;b&#039;&#039; odd) which can be computed relatively easy by other means. For example if &#039;&#039;c&#039;&#039; is odd and gcd(&#039;&#039;a&#039;&#039;,&#039;&#039;c&#039;&#039;)=&#039;&#039;1&#039;&#039; one has&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;&lt;br /&gt;
G(a,b,c) =  \varepsilon_c \sqrt{c} \cdot \left(\frac{a}{c}\right) e^{-2\pi i \psi(a) b^2/c} &lt;br /&gt;
&amp;lt;/math&amp;gt;  &lt;br /&gt;
&lt;br /&gt;
where &amp;lt;math&amp;gt;\psi(a) &amp;lt;/math&amp;gt; is some number with &amp;lt;math&amp;gt;4\psi(a)a \equiv 1\ \text{mod}\ c &amp;lt;/math&amp;gt;. As another example, if &#039;&#039;4&#039;&#039; divides &#039;&#039;c&#039;&#039; and &#039;&#039;b&#039;&#039; is odd and as always gcd(&#039;&#039;a&#039;&#039;,&#039;&#039;c&#039;&#039;)=&#039;&#039;1&#039;&#039; then &#039;&#039;G&#039;&#039;(&#039;&#039;a&#039;&#039;,&#039;&#039;b&#039;&#039;,&#039;&#039;c&#039;&#039;)=&#039;&#039;0&#039;&#039;. This can, for example, be proven as follows: Because of the multiplicative property of Gauss sums we only have to show that &amp;lt;math&amp;gt; G(a,b,2^n)=0 &amp;lt;/math&amp;gt; if &#039;&#039;n&#039;&#039;&amp;gt;&#039;&#039;1&#039;&#039; and &#039;&#039;a,b&#039;&#039; are odd with gcd(&#039;&#039;a&#039;&#039;,&#039;&#039;c&#039;&#039;)=1. If &#039;&#039;b&#039;&#039; is odd then &amp;lt;math&amp;gt; a n^2+bn&amp;lt;/math&amp;gt; is even for all &amp;lt;math&amp;gt; 0\leq n &amp;lt; c-1 &amp;lt;/math&amp;gt;. By [[Hensel&#039;s lemma]], for every &#039;&#039;q&#039;&#039;,  the equation &amp;lt;math&amp;gt; an^2+bn+q=0 &amp;lt;/math&amp;gt; has at most two solutions in &amp;lt;math&amp;gt; \mathbb{Z}/2^n \mathbb{Z} &amp;lt;/math&amp;gt;. Because of a counting argument &amp;lt;math&amp;gt; an^2+bn&amp;lt;/math&amp;gt; runs through all even residue classes modulo &#039;&#039;c&#039;&#039; exactly two times. The [[geometric sum]] formula then shows that &amp;lt;math&amp;gt; G(a,b,2^n)=0 &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
*If &#039;&#039;c&#039;&#039; is odd and [[Square-free integer|squarefree]] and gcd(&#039;&#039;a&#039;&#039;,&#039;&#039;c&#039;&#039;)=&#039;&#039;1&#039;&#039; then&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;&lt;br /&gt;
G(a,0,c) = \sum_{n=0}^{c-1} \left(\frac{n}{c}\right) e^{2\pi i a n/c}.&lt;br /&gt;
&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
If &#039;&#039;c&#039;&#039; is not squarefree then the right side vanishes while the left side does not. Often the right sum is also called a quadratic Gauss sum.&lt;br /&gt;
&lt;br /&gt;
*Another useful formula is&lt;br /&gt;
&lt;br /&gt;
:&#039;&#039;G&#039;&#039;(&#039;&#039;n&#039;&#039;,&#039;&#039;p&amp;lt;sup&amp;gt;k&amp;lt;/sup&amp;gt;&#039;&#039;)=&#039;&#039;pG&#039;&#039;(&#039;&#039;n&#039;&#039;,&#039;&#039;p&#039;&#039;&amp;lt;sup&amp;gt;&#039;&#039;k&#039;&#039;-2&amp;lt;/sup&amp;gt;)&lt;br /&gt;
&lt;br /&gt;
if &#039;&#039;k&#039;&#039;≥2 and &#039;&#039;p&#039;&#039; is an odd prime number or if &#039;&#039;k&#039;&#039;≥4 and &#039;&#039;p&#039;&#039;=2.&lt;br /&gt;
&lt;br /&gt;
==See also==&lt;br /&gt;
&lt;br /&gt;
*[[Gaussian period]]&lt;br /&gt;
*[[Kummer sum]]&lt;br /&gt;
*[[Landsberg-Schaar relation]]&lt;br /&gt;
&lt;br /&gt;
==References==&lt;br /&gt;
&lt;br /&gt;
*{{cite book | author = Ireland and Rosen | title = A Classical Introduction to Modern Number Theory | publisher = Springer-Verlag | year = 1990 | isbn=0-387-97329-X }}&lt;br /&gt;
*{{cite book | author = Bruce C. Berndt, Ronald J. Evans and Kenneth S. Williams | title = Gauss and Jacobi Sums | publisher = Wiley and Sons, Inc. | year = 1998 | isbn=0-471-12807-4 }}&lt;br /&gt;
&lt;br /&gt;
*{{cite book | author = Henryk Iwaniec, Emmanuel Kowalski | title = Analytic number theory | publisher = American Mathematical Society | year = 2004 | isbn=0-8218-3633-1}}&lt;br /&gt;
&lt;br /&gt;
[[Category:Cyclotomic fields]]&lt;/div&gt;</summary>
		<author><name>173.48.162.80</name></author>
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