Hitting time

Some finned elements

In the study of heat transfer, a fin is a surface that extends from an object to increase the rate of heat transfer to or from the environment by increasing convection. The amount of conduction, convection, or radiation of an object determines the amount of heat it transfers. Increasing the temperature difference between the object and the environment, increasing the convection heat transfer coefficient, or increasing the surface area of the object increases the heat transfer. Sometimes it is not economical or it is not feasible to change the first two options. Adding a fin to an object, however, increases the surface area and can sometimes be an economical solution to heat transfer problems.

General case

To create a tractable equation for the heat transfer of a fin, many assumptions need to be made:

1. Steady state
2. Constant material properties (independent of temperature)
3. No internal heat generation
4. One-dimensional conduction
5. Uniform cross-sectional area
6. Uniform convection across the surface area

With these assumptions, conservation of energy can be used to create an energy balance for a differential cross section of the fin:

${\dot {Q}}(x+dx)={\dot {Q}}(x)+d{\dot {Q}}_{conv}.$

Fourier’s law states that

${\dot {Q}}(x)=-kA_{c}\left({\frac {dT}{dx}}\right),$

where $A_{c}$ is the cross-sectional area of the differential element. Furthermore, the convective heat flux can be determined via the definition of the heat transfer coefficient h,

$q''=h\left(T-T_{\infty }\right),$

where $T_{\infty }$ is the temperature of the surroundings. The differential convective heat flux can then be determined from the perimeter of the fin cross-section P,

$d{\dot {Q}}_{conv}=Ph\left(T-T_{\infty }\right)dx.$

The equation of energy conservation can now be expressed in terms of temperature,

$-kA_{c}\left.\left({\frac {dT}{dx}}\right)\right\vert _{x+dx}=-kA_{c}\left.\left({\frac {dT}{dx}}\right)\right\vert _{x}+Ph\left(T-T_{\infty }\right)dx.$

Rearranging this equation and using the definition of the derivative yields the following differential equation for temperature,

$k{\frac {d}{dx}}\left(A_{c}{\frac {dT}{dx}}\right)+Ph\left(T-T_{\infty }\right)=0$;

the derivative on the left can be expanded to the most general form of the fin equation,

$kA_{c}{\frac {d^{2}T}{dx^{2}}}+k{\frac {dA_{c}}{dx}}{\frac {dT}{dx}}+Ph\left(T-T_{\infty }\right)=0.$

Note that the cross-sectional area, perimeter, and temperature can all be functions of x.

Uniform cross-sectional area

If the fin has a constant cross-section along its length, the area and perimeter are constant and the differential equation for temperature is greatly simplified to

${\frac {d^{2}T}{dx^{2}}}={\frac {hP}{kA_{c}}}\left(T-T_{\infty }\right).$

The solution to the simplified equation is

$\theta (x)=C_{1}e^{mx}+C_{2}e^{-mx},$

where $m^{2}={\frac {hP}{kA_{c}}}$ and $\theta (x)=T(x)-T_{\infty }$. The constants $C_{1}$ and $C_{2}$ can now be found by applying the proper boundary conditions.

Solutions

The base of the fin is typically set to a constant reference temperature, $\theta (x=0)=T_{b}-T_{\infty }$. There are four commonly possible fin tip ($x=L$) conditions, however: the tip can be exposed to convective heat transfer, insulated, held at a constant temperature, or so far away from the base as to reach the ambient temperature.

For the first case, the second boundary condition is that there is free convection at the tip. Therefore,

$hA_{c}\left(T(L)-T_{\infty }\right)=-kA_{c}\left.\left({\frac {dT}{dx}}\right)\right\vert _{x=L},$

which simplifies to

$h\theta (L)=-k\left.{\frac {d\theta }{dx}}\right\vert _{x=L}.$

The two boundary conditions can now be combined to produce

$h\left(C_{1}e^{mL}+C_{2}e^{-mL}\right)=km\left(C_{2}e^{-mL}-C_{1}e^{mL}\right).$

This equation can be solved for the constants $C_{1}$ and $C_{2}$ to find the temperature distribution, which is in the table below.

A similar approach can be used to find the constants of integration for the remaining cases. For the second case, the tip is assumed to be insulated, or in other words to have a heat flux of zero. Therefore,

$\left.{\frac {d\theta }{dx}}\right\vert _{x=L}=0.$

For the third case, the temperature at the tip is held constant. Therefore the boundary condition is:

$\theta (L)=\theta _{L}$

For the fourth and final case, the fin is assumed to be infinitely long. Therefore the boundary condition is:

$\lim _{L\rightarrow \infty }\theta _{L}=0\,$

Finally, we can use the temperature distribution and Fourier's Law at the base of the fin to determine the overall rate of heat transfer,

${\dot {Q}}_{\text{total}}={\sqrt {hPkA_{c}}}(C_{2}-C_{1}).$

The results of the solution process are summarized in the table below.

Temperature distribution and heat transfer rate for fins of uniform cross sectional area

Case	Tip condition (x=L)	Temperature distribution	Fin heat transfer rate
A	Convection heat transfer	${\frac {\theta }{\theta _{b}}}={\frac {\cosh {m(L-x)}+\left({\frac {h}{mk}}\right)\sinh {m(L-x)}}{\cosh {mL}+\left({\frac {h}{mk}}\right)\sinh {mL}}}$	${\sqrt {hPkA_{c}}}\theta _{b}{\frac {\sinh {mL}+(h/mk)\cosh {mL}}{\cosh {mL}+(h/mk)\sinh {mL}}}$
B	Adiabatic	${\frac {\theta }{\theta _{b}}}={\frac {\cosh {m(L-x)}}{\cosh {mL}}}$	${\sqrt {hPkA_{c}}}\theta _{b}\tanh {mL}$
C	Constant Temperature	${\frac {\theta }{\theta _{b}}}={\frac {{\frac {\theta _{L}}{\theta _{b}}}\sinh {mx}+\sinh {m(L-x)}}{\sinh {mL}}}$	${\sqrt {hPkA_{c}}}\theta _{b}{\frac {\cosh {mL}-{\frac {\theta _{L}}{\theta _{b}}}}{\sinh {mL}}}$
D	Infinite Fin Length	${\frac {\theta }{\theta _{b}}}=e^{-mx}$	${\sqrt {hPkA_{c}}}\theta _{b}$

Fin performance

Fin performance can be described in three different ways. The first is fin effectiveness. It is the ratio of the fin heat transfer rate (${\dot {Q}}_{f}$) to the heat transfer rate of the object if it had no fin. The formula for this is

$\epsilon _{f}={\frac {{\dot {Q}}_{f}}{hA_{c,b}\theta _{b}}},$

where $A_{c,b}$ is the fin cross-sectional area at the base. Fin performance can also be characterized by fin efficiency. This is the ratio of the fin heat transfer rate to the heat transfer rate of the fin if the entire fin were at the base temperature,

$\eta _{f}={\frac {{\dot {Q}}_{f}}{hA_{f}\theta _{b}}}.$

$A_{f}$ in this equation is equal to the surface area of the fin. The fin efficiency will always be less than one, as assuming the temperature throughout the fin is at the base temperature would increase the heat transfer rate.

The third way fin performance can be described is with overall surface efficiency,

$\eta _{o}={\frac {{\dot {Q}}_{t}}{hA_{t}\theta _{b}}},$

where $A_{t}$ is the total area and ${\dot {Q}}_{t}$ is the sum of the heat transfer rates of all the fins. This is the efficiency for an array of fins.

• 
  Aluminium heat sink with low efficiency cooling fins
• 
  Aluminium heat sink with high efficiency cooling fins.

Fin uses

Fins are most commonly used in heat exchanging devices such as radiators in cars, computer CPU heatsinks, and heat exchangers in power plants. They are also used in newer technology such as hydrogen fuel cells. Nature has also taken advantage of the phenomena of fins. The ears of jackrabbits and Fennec Foxes act as fins to release heat from the blood that flows through them.

Footnotes

43 year old Petroleum Engineer Harry from Deep River, usually spends time with hobbies and interests like renting movies, property developers in singapore new condominium and vehicle racing. Constantly enjoys going to destinations like Camino Real de Tierra Adentro.

References

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