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: ''This page is about Lagrange reversion. For inversion, see [[Lagrange inversion theorem]].''
 
In [[mathematics]], the '''Lagrange reversion theorem''' gives [[Series (mathematics)|series]] or [[formal power series]] expansions of certain [[implicitly defined function]]s; indeed, of compositions with such functions.
 
Let ''v'' be a function of ''x'' and ''y'' in terms of another function ''f'' such that
:<math>v=x+yf(v)</math>
Then for any function ''g'',
:<math>g(v)=g(x)+\sum_{k=1}^\infty\frac{y^k}{k!}\left(\frac\partial{\partial x}\right)^{k-1}\left(f(x)^kg'(x)\right)</math>
for small ''y''. If ''g'' is the identity
:<math>v=x+\sum_{k=1}^\infty\frac{y^k}{k!}\left(\frac\partial{\partial x}\right)^{k-1}\left(f(x)^k\right)</math>
 
In 1770, [[Joseph Louis Lagrange]] (1736–1813) published his power series solution of the implicit equation for ''v'' mentioned above. However, his solution used cumbersome series expansions of logarithms.<ref>Lagrange, Joseph Louis (1770) "Nouvelle méthode pour résoudre les équations littérales par le moyen des séries," ''Mémoires de l'Académie Royale des Sciences et Belles-Lettres de Berlin'', vol. 24, pages 251–326. (Available on-line at: http://gdz.sub.uni-goettingen.de/no_cache/dms/load/img/?IDDOC=41070 .)</ref><ref>Lagrange, Joseph Louis, ''Oeuvres'', [Paris, 1869], Vol. 2, page 25; Vol. 3, pages 3–73.</ref> In 1780, [[Pierre-Simon Laplace]] (1749–1827) published a simpler proof of the theorem, which was based on relations between partial derivatives with respect to the variable x and the parameter y.<ref>Laplace, Pierre Simon de (1777) "Mémoire sur l'usage du calcul aux différences partielles dans la théories des suites," ''Mémoires de l'Académie Royale des Sciences de Paris,'' vol. , pages 99–122.</ref><ref>Laplace, Pierre Simon de, ''Oeuvres'' [Paris, 1843], Vol. 9, pages 313–335.</ref><ref>Laplace's proof is presented in:
*Goursat, Édouard, ''A Course in Mathematical Analysis'' (translated by E.R. Hedrick and O. Dunkel) [N.Y., N.Y.: Dover, 1959], Vol. I, pages 404–405.</ref> [[Charles Hermite]] (1822–1901) presented the most straightforward proof of the theorem by using contour integration.<ref>Hermite, Charles (1865) "Sur quelques développements en série de fonctions de plusieurs variables," ''Comptes Rendus de l'Académie des Sciences des Paris'', vol. 60, pages 1–26.</ref><ref>Hermite, Charles, ''Oeuvres'' [Paris, 1908], Vol. 2, pages 319–346.</ref><ref>Hermite's proof is presented in:
*Goursat, Édouard, ''A Course in Mathematical Analysis'' (translated by E. R. Hedrick and O. Dunkel) [N.Y., N.Y.: Dover, 1959], Vol. II, Part 1, pages 106–107.
*Whittaker, E.T. and G.N. Watson, ''A Course of Modern Analysis'', 4th ed. [Cambridge, England: Cambridge University Press, 1962] pages 132–133.</ref>
 
Lagrange's reversion theorem is used to obtain numerical solutions to [[Kepler's equation]].
 
==Simple proof==
We start by writing:
 
:<math> g(v) = \int \delta(y f(z) - z + x) g(z) (1-y f'(z)) \, dz</math>
 
Writing the delta-function as an integral we have:
 
:<math>
\begin{align}
g(v) & = \int \int \exp(ik[y f(z) - z + x]) g(z) (1-y f'(z)) \, \frac{dk}{2\pi} \, dz \\[10pt]
& =\sum_{n=0}^\infty \int \int \frac{(ik y f(z))^n}{n!} g(z) (1-y f'(z)) e^{ik(x-z)}\, \frac{dk}{2\pi} \, dz \\[10pt]
& =\sum_{n=0}^\infty \left(\frac{\partial}{\partial x}\right)^n\int \int \frac{(y f(z))^n}{n!} g(z) (1-y f'(z)) e^{ik(x-z)} \, \frac{dk}{2\pi} \, dz
\end{align}
</math>
 
The integral over ''k'' then gives <math>\delta(x-z)</math> and we have:
 
:<math>
\begin{align}
g(v) & = \sum_{n=0}^\infty \left(\frac{\partial}{\partial x}\right)^n \left[ \frac{(y f(x))^n}{n!} g(x) (1-y f'(x))\right] \\[10pt]
& =\sum_{n=0}^\infty \left(\frac{\partial}{\partial x}\right)^n \left[
\frac{y^n f(x)^n g(x)}{n!} - \frac{y^{n+1}}{(n+1)!}\left\{ (g(x) f(x)^{n+1})' - g'(x) f(x)^{n+1}\right\} \right]
\end{align}
</math>
 
Rearranging the sum and cancelling then gives the result:
 
:<math>g(v)=g(x)+\sum_{k=1}^\infty\frac{y^k}{k!}\left(\frac\partial{\partial x}\right)^{k-1}\left(f(x)^kg'(x)\right)</math>
 
==References==
{{reflist}}
 
==External links==
*[http://mathworld.wolfram.com/LagrangeInversionTheorem.html Lagrange Inversion &#91;Reversion&#93; Theorem] on [[MathWorld]]
*[http://www.quantlet.com/mdstat/scripts/xfg/html/xfghtmlnode8.html Cornish–Fisher expansion], an application of the theorem
*[http://info.ifpan.edu.pl/firststep/aw-works/fsII/mul/mueller.html Article] on [[equation of time]] contains an application to Kepler's equation.
 
{{DEFAULTSORT:Lagrange Reversion Theorem}}
[[Category:Theorems in analysis]]
[[Category:Inverse functions]]
 
[[fr:Théorème d'inversion de Lagrange]]

Revision as of 10:31, 26 January 2014

This page is about Lagrange reversion. For inversion, see Lagrange inversion theorem.

In mathematics, the Lagrange reversion theorem gives series or formal power series expansions of certain implicitly defined functions; indeed, of compositions with such functions.

Let v be a function of x and y in terms of another function f such that

v=x+yf(v)

Then for any function g,

g(v)=g(x)+k=1ykk!(x)k1(f(x)kg(x))

for small y. If g is the identity

v=x+k=1ykk!(x)k1(f(x)k)

In 1770, Joseph Louis Lagrange (1736–1813) published his power series solution of the implicit equation for v mentioned above. However, his solution used cumbersome series expansions of logarithms.[1][2] In 1780, Pierre-Simon Laplace (1749–1827) published a simpler proof of the theorem, which was based on relations between partial derivatives with respect to the variable x and the parameter y.[3][4][5] Charles Hermite (1822–1901) presented the most straightforward proof of the theorem by using contour integration.[6][7][8]

Lagrange's reversion theorem is used to obtain numerical solutions to Kepler's equation.

Simple proof

We start by writing:

g(v)=δ(yf(z)z+x)g(z)(1yf(z))dz

Writing the delta-function as an integral we have:

g(v)=exp(ik[yf(z)z+x])g(z)(1yf(z))dk2πdz=n=0(ikyf(z))nn!g(z)(1yf(z))eik(xz)dk2πdz=n=0(x)n(yf(z))nn!g(z)(1yf(z))eik(xz)dk2πdz

The integral over k then gives δ(xz) and we have:

g(v)=n=0(x)n[(yf(x))nn!g(x)(1yf(x))]=n=0(x)n[ynf(x)ng(x)n!yn+1(n+1)!{(g(x)f(x)n+1)g(x)f(x)n+1}]

Rearranging the sum and cancelling then gives the result:

g(v)=g(x)+k=1ykk!(x)k1(f(x)kg(x))

References

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External links

fr:Théorème d'inversion de Lagrange

  1. Lagrange, Joseph Louis (1770) "Nouvelle méthode pour résoudre les équations littérales par le moyen des séries," Mémoires de l'Académie Royale des Sciences et Belles-Lettres de Berlin, vol. 24, pages 251–326. (Available on-line at: http://gdz.sub.uni-goettingen.de/no_cache/dms/load/img/?IDDOC=41070 .)
  2. Lagrange, Joseph Louis, Oeuvres, [Paris, 1869], Vol. 2, page 25; Vol. 3, pages 3–73.
  3. Laplace, Pierre Simon de (1777) "Mémoire sur l'usage du calcul aux différences partielles dans la théories des suites," Mémoires de l'Académie Royale des Sciences de Paris, vol. , pages 99–122.
  4. Laplace, Pierre Simon de, Oeuvres [Paris, 1843], Vol. 9, pages 313–335.
  5. Laplace's proof is presented in:
    • Goursat, Édouard, A Course in Mathematical Analysis (translated by E.R. Hedrick and O. Dunkel) [N.Y., N.Y.: Dover, 1959], Vol. I, pages 404–405.
  6. Hermite, Charles (1865) "Sur quelques développements en série de fonctions de plusieurs variables," Comptes Rendus de l'Académie des Sciences des Paris, vol. 60, pages 1–26.
  7. Hermite, Charles, Oeuvres [Paris, 1908], Vol. 2, pages 319–346.
  8. Hermite's proof is presented in:
    • Goursat, Édouard, A Course in Mathematical Analysis (translated by E. R. Hedrick and O. Dunkel) [N.Y., N.Y.: Dover, 1959], Vol. II, Part 1, pages 106–107.
    • Whittaker, E.T. and G.N. Watson, A Course of Modern Analysis, 4th ed. [Cambridge, England: Cambridge University Press, 1962] pages 132–133.