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{{merge|Geographical distance#Ellipsoidal-surface formulae|target=Ellipsoidal geodesic|date=July 2013}}
{{for|the mathematical background to this problem|Geodesics on an ellipsoid}}
'''Vincenty's formulae''' are two related [[iterative method]]s used in [[geodesy]] to calculate the distance between two points on the surface of a spheroid, developed by [[Thaddeus Vincenty]] (1975a) They are based on the assumption that the [[figure of the Earth]] is an [[oblate spheroid]], and hence are more accurate than methods such as [[great-circle distance]] which assume a [[spherical]] Earth.


The first (direct) method computes the location of a point which is a given distance and [[azimuth]] (direction) from another point. The second (inverse) method computes the [[geographical distance]] and azimuth between two given points. They have been widely used in geodesy because they are accurate to within 0.5 mm (0.020″) on the [[Earth ellipsoid]].


== Background ==
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Vincenty's goal was to express existing algorithms for [[geodesics on an ellipsoid]]
in a form that minimized the program length
(see the first sentence of his paper). His unpublished report (1975b)
mentions the use of a [[Wang Laboratories#Calculators|Wang]]
720 desk calculator which had only a few
kilobytes of memory.  To obtain good accuracy for long lines, the
solution uses the classical solution of Legendre (1806), Bessel (1825),
and Helmert (1880) based on the auxiliary sphere.  (Vincenty relied on
formulation of this method given by Rainsford, 1955.)  Legendre showed
that an ellipsoidal geodesic can be exactly mapped to a great circle on
the auxiliary sphere by mapping the geographic latitude to reduced
latitude and setting the azimuth of the great circle equal to that of
the geodesic.  The longitude on the ellipsoid and the distance along the
geodesic are then given in terms of the longitude on the sphere and the
arc length along the great circle by simple integrals. Bessel and
Helmert gave rapidly converging series for these integrals which allow
the geodesic to be computed with arbitrary accuracy.
 
In order to minimize the program size, Vincenty took these series,
re-expanded them using the first term of each series as the small
parameter, and truncated them to order ''&fnof;''<sup>3</sup>.  This resulted in
compact expressions for the longitude and distance integrals.
The expressions were put in [[Horner scheme|Horner]]
(or ''nested'') form, since this
allows polynomials to be evaluated using only a single temporary
register.  Finally, simple iterative techniques were used
to solve the implicit equations in the direct and inverse methods; even
though these are slow (and in the case of the inverse method it sometimes does
not converge), they result in the least increase in code size.
 
== Notation ==
Define the following notation:
{|
|-
| ''a'' || length of semi-[[major axis]] of the ellipsoid (radius at equator); || (6378137.0 metres in [[WGS-84]])
|-
| ''&fnof;'' || [[flattening]] of the ellipsoid; || (1/298.257223563 in [[WGS-84]])
|-
| ''b'' = (1&nbsp;-&nbsp;''&fnof;'')&nbsp;''a''|| length of semi-[[minor axis]] of the ellipsoid (radius at the poles);
|-
| ''φ''<sub>1</sub>,&nbsp;''φ''<sub>2</sub> || [[latitude]] of the points;
|-
| ''U''<sub>1</sub>&nbsp;=&nbsp;arctan[(1&nbsp;−&nbsp;''ƒ'')&nbsp;tan&nbsp;''φ''<sub>1</sub>], <br/> ''U''<sub>2</sub>&nbsp;=&nbsp;arctan[(1&nbsp;−&nbsp;''ƒ'') tan ''φ''<sub>2</sub>] || [[Latitude#Reduced_latitude|reduced latitude]] (latitude on the auxiliary sphere)
|-
| ''L'' = ''L''<sub>2</sub>&nbsp;-&nbsp;''L''<sub>1</sub> || difference in [[longitude]] of two points;
|-
| ''λ''<sub>1</sub>, ''λ''<sub>2</sub> || longitude of the points on the auxiliary sphere;
|-
| ''α''<sub>1</sub>,&nbsp;''α''<sub>2</sub> || forward [[azimuth]]s at the points;
|-
| ''α'' || [[azimuth]] at the equator;
|-
| ''s'' || ellipsoidal distance between the two points;
|-
| ''σ'' || arc length between points on the auxiliary sphere;
|}
 
== Inverse problem==
Given the coordinates of the two points (''φ''<sub>1</sub>,&nbsp;''L''<sub>1</sub>) and (''φ''<sub>2</sub>,&nbsp;''L''<sub>2</sub>), the inverse problem finds the azimuths ''α''<sub>1</sub>, ''α''<sub>2</sub> and the ellipsoidal distance ''s''.
 
Calculate ''U''<sub>1</sub>, ''U''<sub>2</sub> and ''L'', and set initial value of ''λ'' = ''L''. Then iteratively evaluate the following equations until ''λ'' converges:
 
::<math>\sin \sigma = \sqrt{ (\cos U_2 \sin \lambda)^2 + (\cos U_1 \sin U_2 - \sin U_1 \cos U_2 \cos \lambda)^2}</math>
 
::<math>\cos \sigma = \sin U_1 \sin U_2 + \cos U_1 \cos U_2 \cos \lambda \,</math>
 
::<math>\sigma = \arctan\frac{\sin\sigma}{\cos\sigma}\,</math><ref>''σ'' isn't evaluated directly from sin&nbsp;''σ'' or cos&nbsp;''σ'' to preserve numerical accuracy near the poles and equator</ref><ref name="atan">The arctan quantity should be evaluated using a two argument [[atan2]] type function.</ref>
 
::<math>\sin \alpha = \frac{\cos U_1 \cos U_2 \sin \lambda}{\sin \sigma} \,</math><ref name="opposite">If sin ''&sigma;
= 0'' the value of sin ''α'' is indeterminate. It represents an end point equal to, or
diametrically opposite the start point.</ref>
 
::<math>\cos^2 \alpha = 1 - \sin^2 \alpha \,</math>
 
::<math>\cos (2 \sigma_m) = \cos \sigma - \frac{2 \sin U_1\sin U_2}{\cos^2 \alpha} \,</math><ref name="equator">Start
and end point are on the equator. In this case ''C = 0'' so the value of <math>\cos (2 \sigma_m) </math> is not used.
The limiting value is <math>\cos (2 \sigma_m) = -1</math>.</ref>
 
::<math>C = \frac{f}{16} \cos^2 \alpha \big[4 + f(4-3 \cos^2 \alpha) \big] \,</math>
 
::<math>\lambda = L + (1-C) f \sin \alpha \left\{ \sigma + C \sin \sigma \left[\cos (2 \sigma_m) + C \cos \sigma (-1 + 2 \cos^2 (2 \sigma_m)) \right]\right\} \, </math>
 
When ''λ'' has converged to the desired degree of accuracy (10<sup>−12</sup> corresponds to approximately 0.06mm), evaluate the following:
 
:<math>u^2 = \cos^2 \alpha \frac{a^2 - b^2}{b^2} \,</math>
 
:<math>A = 1 + \frac{u^2}{16384} \left\{ 4096 + u^2 \left[ -768 +u^2 (320 - 175u^2) \right] \right\}</math>
:<math>B = \frac{u^2}{1024} \left\{ 256 + u^2 \left[ -128 + u^2 (74-47 u^2) \right] \right\} </math>
 
:<math> \Delta \sigma = B \sin \sigma \Big\{ \cos(2 \sigma_m) + \tfrac{1}{4} B \big[ \cos \sigma \big(-1+2 \cos^2(2 \sigma_m) \big) - \tfrac{1}{6} B \cos(2 \sigma_m)  (-3+4 \sin^2 \sigma) \big(-3+4 \cos^2 (2 \sigma_m)\big)  \big] \Big\} </math>
 
:<math> s = b A(\sigma - \Delta \sigma) \,</math>
 
:<math> \alpha_1 = \arctan \left( \frac{\cos U_2 \sin \lambda}{\cos U_1  \sin U_2 - \sin U_1 \cos U_2 \cos \lambda} \right) </math><ref name="atan"/>
 
:<math> \alpha_2 = \arctan \left( \frac{\cos U_1 \sin \lambda}{-\sin U_1 \cos U_2 + \cos U_1 \sin U_2 \cos \lambda} \right) </math><ref name="atan"/>
 
Between two nearly antipodal points, the iterative formula may fail to converge; this will occur when the first guess at ''λ'' as computed by the equation above is greater than ''π'' in absolute value.
 
==Direct Problem==
Given an initial point (''φ''<sub>1</sub>, ''L''<sub>1</sub>)
and initial azimuth, ''α''<sub>1</sub>, and a distance, ''s'', along
the geodesic the problem is to find the end point
(''φ''<sub>2</sub>, ''L''<sub>2</sub>) and azimuth,
''α''<sub>2</sub>.
 
Start by calculating the following:
 
:<math> \tan U_1 = (1 - f)\tan \phi_1 \, </math>
 
:<math> \sigma_1 = \arctan \left ( \frac{ \tan U_1}{ \cos \alpha_1} \right ) \, </math><ref name="atan"/>
 
:<math> \sin \alpha = \cos U_1 \sin \alpha_1; \,\,\,\, \cos^2 \alpha = (1 - \sin \alpha)(1 + \sin \alpha) </math>
 
:<math> u^2 = \cos^2 \alpha \frac{a^2 - b^2}{b^2} \, </math>
 
:<math> A = 1 + \frac{u^2}{16384} \left\{ 4096 + u^2 \left[ -768 +u^2 (320 - 175u^2) \right] \right\} </math>
 
:<math> B = \frac{u^2}{1024} \left\{ 256 + u^2 \left[ -128 + u^2 (74-47 u^2) \right] \right\} </math>
 
Then, using an initial value <math> \sigma = \tfrac{s}{bA} </math>, iterate the following equations until
there is no significant change in ''σ'':
 
::<math> 2 \sigma_m = 2 \sigma_1 + \sigma \, </math>
 
::<math> \Delta \sigma = B \sin \sigma \Big\{ \cos(2 \sigma_m) + \tfrac{1}{4} B \big[ \cos \sigma \big(-1+2 \cos^2(2 \sigma_m) \big) - \tfrac{1}{6} B \cos(2 \sigma_m) (-3+4 \sin^2 \sigma) \big(-3+4 \cos^2 (2 \sigma_m)\big) \big] \Big\} </math>
 
::<math> \sigma = \frac{s}{bA} + \Delta \sigma \, </math>
 
Once ''σ'' is obtained to sufficient accuracy evaluate:
 
:<math> \phi_2 = \arctan \left( \frac{\sin U_1 \cos \sigma + \cos U_1 \sin \sigma \cos \alpha_1}{(1 - f) \sqrt{\sin^2 \alpha + (\sin U_1 \sin \sigma - \cos U_1 \cos \sigma \cos \alpha_1 )^2 } } \right) \, </math><ref name="atan"/>
 
:<math> \lambda = \arctan \left( \frac{\sin \sigma \sin \alpha_1}{\cos U_1 \cos \sigma - \sin U_1 \sin \sigma \cos \alpha_1} \right) \, </math><ref name="atan"/>
 
:<math> C = \frac{f}{16} \cos^2 \alpha \big[4 + f(4-3 \cos^2 \alpha) \big] \, </math>
 
:<math> L = \lambda - (1-C) f \sin \alpha \left\{ \sigma + C \sin \sigma \left[\cos (2 \sigma_m) + C \cos \sigma (-1 + 2 \cos^2 (2 \sigma_m)) \right]\right\} \, </math>
 
:<math> \alpha_2 = \arctan \left( \frac{\sin \alpha}{-\sin U_1 \sin \sigma + \cos U_1 \cos \sigma \cos \alpha_1} \right) \, </math><ref name="atan"/>
 
If the initial point is at the North or South pole then the first equation is indeterminate.
If the initial azimuth is due East or West then the second equation is indeterminate.  
If a double valued ''atan2'' type function is used then these values are usually handled correctly.
 
==Vincenty's modification==
 
In his letter to Survey Review in 1976, Vincenty suggested replacing his series expressions for ''A'' and ''B'' with simpler formulas using Helmert's expansion parameter ''k''<sub>1</sub>:
 
<math>A = \frac {1 + \frac {1}{4} (k_1)^2}{1 - k_1}</math><br><br>
 
<math>B = k_1(1 - \tfrac {3}{8}(k_1)^2)</math><br><br>
 
where{{pad|4em}}<math> k_1 = \frac { \sqrt {(1 + u^2)} - 1}{ \sqrt {(1 + u^2)} + 1}</math>
 
==Nearly antipodal points==
 
As noted above, the iterative solution to the inverse problem fails to converge or converges slowly for nearly antipodal points. An example of slow convergence is (''φ''<sub>1</sub>,&nbsp;''L''<sub>1</sub>) = (0°,&nbsp;0°) and (''φ''<sub>2</sub>,&nbsp;''L''<sub>2</sub>) = (0.5°,&nbsp;179.5°) for the WGS84 ellipsoid. This requires about 130 iterations to give a result accurate to 1&nbsp;mm. Depending on how the inverse method is implemented, the algorithm might return the correct result (19936288.579&nbsp;m), an incorrect result, or an error indicator. An example of an incorrect result is provided by the [http://www.ngs.noaa.gov/TOOLS/Inv_Fwd/Inv_Fwd.html NGS online utility] which returns a distance which is about 5&nbsp;km too long. Vincenty suggested a method of accelerating the convergence in such cases (Rapp, 1973).
 
An example of a failure of the inverse method to converge is (''φ''<sub>1</sub>,&nbsp;''L''<sub>1</sub>) = (0°,&nbsp;0°) and (''φ''<sub>2</sub>,&nbsp;''L''<sub>2</sub>) = (0.5°,&nbsp;179.7°) for the WGS84 ellipsoid. In an unpublished report, Vincenty (1975b) gave an alternative iterative scheme to handle such cases.  This converges to the correct result 19944127.421&nbsp;m after about 60 iterations; however, in other cases many thousands of iterations are required.
 
Newton's method has been successfully used to give rapid convergence for all pairs of input points (Karney, 2013).
 
==See also==
*[[Geographical distance]]
*[[Great-circle distance]]
*[[Meridian arc]]
*[[Geodesics on an ellipsoid]]
*[[Thaddeus Vincenty]]
*[[Geodesy]]
 
==Notes==
{{reflist}}
 
==References==
* {{cite journal
|first=F. W. |last=Bessel |authorlink=Friedrich Bessel
|title=The calculation of longitude and latitude from geodesic measurements (1825)
|journal=Astron. Nachr.
|year=2010
|volume=331 |issue=8 |pages=852&ndash;861
|doi=10.1002/asna.201011352
|arxiv=0908.1824 |postscript=.  English translation of Astron. Nachr. '''4''', 241&ndash;254 (1825).
}}
* {{cite book
|first=F. R. |last=Helmert |authorlink=Helmert
|title=Mathematical and Physical Theories of Higher Geodesy, Part 1 (1880)
|publisher=Aeronautical Chart and Information Center
|year=1964
|location=St. Louis
|url=http://geographiclib.sf.net/geodesic-papers/helmert80-en.html
|accessdate=2011-07-30
|postscript=.  English translation of ''Die Mathematischen und Physikalischen Theorieen der Höheren Geodäsie'', Vol. 1 (Teubner, Leipzig, 1880).
}}
* {{cite doi
|10.1007/s00190-012-0578-z
|comment = Karney 2013
|noedit
}}
* {{cite journal
|first=A. M. |last=Legendre |authorlink=Adrien-Marie Legendre
|title=Analyse des triangles tracės sur la surface d'un sphėroïde
|journal=Mém. de l'Inst. Nat. de France
|year=1806
|issue=1st sem. |pages=130&ndash;161
|url=http://books.google.com/books?id=-d0EAAAAQAAJ&pg=PA130-IA4
|accessdate=2011-07-30
}}
* {{cite doi
|10.1007/BF02527187
|comment = Rainsford 1955
|noedit
}}
* {{cite techreport
|first=R. H. |last=Rapp
|title=Geometric Geodesy, Part II
|institution=Ohio State University
|date=March 1993
|url=http://hdl.handle.net/1811/24409
|accessdate=2011-08-01
}}
* {{cite journal
|first=T. |last=Vincenty |authorlink=Thaddeus Vincenty
|title=Direct and Inverse Solutions of Geodesics on the Ellipsoid with application of nested equations
|journal=Survey Review
|volume=XXIII (misprinted as XXII) |issue=176 |date=April 1975a |pages=88&ndash;93
|url=http://www.ngs.noaa.gov/PUBS_LIB/inverse.pdf |accessdate=2009-07-11
}}
* {{cite journal
|first=T. |last=Vincenty |authorlink=Thaddeus Vincenty
|title=Correspondence
|journal=Survey Review
|volume=XXIII |issue=180 |date=April 1976 |pages=294
}}
* {{cite techreport
|first=T. |last=Vincenty |authorlink=Thaddeus Vincenty
|title=Geodetic inverse solution between antipodal points
|institution=DMAAC Geodetic Survey Squadron
|date=August 1975b
|url=http://geographiclib.sf.net/geodesic-papers/vincenty75b.pdf
|accessdate=2011-07-28
}}
* {{cite book
|publisher=Intergovernmental committee on survey and mapping (ICSM)
|date=February 2006
|isbn=0-9579951-0-5
|title=Geocentric Datum of Australia (GDA) Reference Manual
|url=http://www.icsm.gov.au/gda/gdatm/index.html
|format=PDF
|accessdate=2009-07-11
}}
 
==External links==
* Online calculators from [[Geoscience Australia]]:
** [http://www.ga.gov.au/geodesy/datums/vincenty_direct.jsp Vincenty Direct] (destination point)
** [http://www.ga.gov.au/geodesy/datums/vincenty_inverse.jsp Vincenty Inverse] (distance between points)
* Calculators from the [[U.S. National Geodetic Survey]]:
** [http://www.ngs.noaa.gov/TOOLS/Inv_Fwd/Inv_Fwd.html Online and downloadable PC-executable calculation utilities], including forward (direct) and inverse problems, in both two and three dimensions (accessed 2011-08-01).
* Online calculators with JavaScript source code by Chris Veness (Creative Commons Attribution license):
** [http://www.movable-type.co.uk/scripts/latlong-vincenty-direct.html Vincenty Direct] (destination point)
** [http://www.movable-type.co.uk/scripts/latlong-vincenty.html Vincenty Inverse] (distance between points)
* [http://geographiclib.sourceforge.net GeographicLib] provides a utility GeodSolve (with MIT/X11 licensed source code) for solving direct and inverse geodesic problems.  Compared to Vincenty, this is about 1000 times more accurate (error = 15&nbsp;nm) and the inverse solution is complete. Here is an [http://geographiclib.sourceforge.net/cgi-bin/GeodSolve online version of GeodSolve].
 
{{DEFAULTSORT:Vincenty's Formulae}}
[[Category:Geodesy]]
[[Category:Articles with example pseudocode]]

Latest revision as of 21:10, 20 February 2014


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