Special classes of semigroups: Difference between revisions

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{{Orphan|date=September 2013}}
 
When calculating the unstable fraction of the [[radioactivity]] in the original [[isotope]] [[Atomic nucleus|nucleus]], there is a simple equation which can help you find the fraction of unstable nuclei still [[radioactive]] after a given period of half-lives.
 
== Equation ==
 
<math>p=1/2^n</math>
 
when <math>p</math> is the fraction of unstable nucleus, and <math>n</math> the number of half lives.
 
'''''Example:'''''
 
'' '''Q:''' The Half Life of [[Cobalt-60]] is 5 years. After 225 years, what fraction of the [[Cobalt-60]] is still unstable?''
 
'''''A:''' (225÷5=45 will find you the number of half lives.)''
''<math>p=1/2^n</math>''
''<math>p=1/2^{45}</math>''
 
{{DEFAULTSORT:Radioactive Instability in the Nucleus - Formula}}
[[Category:Radioactivity]]

Revision as of 08:17, 26 January 2014

Template:Orphan

When calculating the unstable fraction of the radioactivity in the original isotope nucleus, there is a simple equation which can help you find the fraction of unstable nuclei still radioactive after a given period of half-lives.

Equation

p=1/2n

when p is the fraction of unstable nucleus, and n the number of half lives.

Example:

Q: The Half Life of Cobalt-60 is 5 years. After 225 years, what fraction of the Cobalt-60 is still unstable?

A: (225÷5=45 will find you the number of half lives.)

p=1/2n

p=1/245