Single displacement reaction: Difference between revisions

From formulasearchengine
Jump to navigation Jump to search
en>Denisarona
m Reverted 1 edit by 207.219.43.34 (talk) to last revision by Nruddz. (TW)
No edit summary
Line 1: Line 1:
{{for|preliminary discussion|Cartan connection applications}}
Production Manager (Forestry ) Ensley from Matachewan, has hobbies which include acting, new launch property singapore and rc model cars. Has enrolled in a global contiki tour. Is quite ecstatic particularly about traveling to Bagrati Cathedral and Gelati Monastery.<br><br>Also visit my site :: [http://noblecow.com/members/bruce8995/activity/95504/ The Skywoods vacancy]
In [[Riemannian geometry]], we can introduce a [[coordinate system]] over the [[Riemannian manifold]] (at least, over a [[Chart (topology)|chart]]), giving ''n'' coordinates
 
:<math>x_{i}\;\text{,}\qquad i = 1, \dots, n</math>
 
for an n-dimensional manifold. Locally, at least, this gives a basis for the 1-forms, dx<sup>i</sup> where d is the [[exterior derivative]]. The [[dual basis]] for the [[tangent space]] T is '''e'''<sub>i</sub>.
 
Now, let's choose an [[orthonormal basis]] for the [[fiber bundle|fibers]] of T. The rest is index manipulation.
 
==Example==
 
Take a [[3-sphere]] with the [[radius]] ''R'' and give it [[polar coordinate]]s &alpha;, &theta;, &phi;.
 
:e('''e'''<sub>&alpha;</sub>)/R,
:e('''e'''<sub>&theta;</sub>)/R sin(&alpha;) and
:e('''e'''<sub>&phi;</sub>)/R sin(&alpha;) sin(&theta;)
 
form an orthonormal basis of T.
 
Call these '''e'''<sub>1</sub>, '''e'''<sub>2</sub> and '''e'''<sub>3</sub>. Given the metric &eta;, we can ignore the [[Covariance|covariant]] and [[contravariant]] distinction for T.
 
Then, the dreibein (triad),
 
:<math>e_1 = R\, d\alpha</math>
:<math>e_2 = R\, \sin{(\alpha)} d\theta</math>
:<math>e_3 = R\, \sin{(\alpha)} \sin{(\theta)} d\phi</math>.
 
So,
 
:<math>de_1=0</math>
:<math>de_2=R \cos{(\alpha)} d\alpha \wedge d\theta</math>
:<math>de_3=R (\cos{(\alpha)} \sin{(\theta)} d\alpha \wedge d\phi + \sin{(\alpha)} \cos{(\theta)} d\theta \wedge d\phi)</math>.
 
from the relation
 
:<math>d_\mathbf{A} e = de + A \wedge e = 0</math>,
 
we get
 
:<math>A_{12} = -\cos{(\alpha)} \, d\theta</math>
:<math>A_{13} = -\cos{(\alpha)} \, \sin{(\theta)} d\phi</math>
:<math>A_{23} = -\cos{(\theta)} \, d\phi</math>.
 
(d<sub>'''A'''</sub>&eta;=0 tells us A is antisymmetric)
 
So, <math>\mathbf{F} = d\mathbf{A} + \mathbf{A} \wedge \mathbf{A}</math>,
 
:<math>F_{12}=\sin{(\alpha)} d\alpha\wedge d\theta</math>
:<math>F_{13}=\sin{(\alpha)} \sin{(\theta)} d\alpha\wedge d\phi</math>
:<math>F_{23}=\sin^2{(\alpha)} \sin{(\theta)} d\theta\wedge d\phi</math>
 
{{tensors}}
{{differential-geometry-stub}}
 
[[Category:Differential geometry]]
[[Category:Mathematical notation]]

Revision as of 20:07, 23 February 2014

Production Manager (Forestry ) Ensley from Matachewan, has hobbies which include acting, new launch property singapore and rc model cars. Has enrolled in a global contiki tour. Is quite ecstatic particularly about traveling to Bagrati Cathedral and Gelati Monastery.

Also visit my site :: The Skywoods vacancy