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In mathematics, the '''Lebesgue covering dimension''' or '''topological dimension''' of a [[topological space]] is one of several different ways of defining the [[dimension]] of the space in a
[[topological invariant|topologically invariant]] way.
 
==Definition==
An [[open cover]] of a topological space ''X'' is a family of [[open set]]s whose union is ''X''. The ''ply'' of a cover is the smallest number ''n'' (if it exists) such that each point of the space belongs to at most ''n'' sets in the cover. A [[refinement (topology)|refinement]] of a cover ''C'' is another cover, each of whose sets is a subset of a set in ''C''; its ply may be smaller than, or possibly larger than, the ply of ''C''.
The covering dimension of a topological space ''X'' is defined to be the minimum value of ''n'', such that every finite open cover ''C'' of ''X'' has a refinement with ply at most ''n''&nbsp;+&nbsp;1. If no such minimal ''n'' exists, the space is said to be of infinite covering dimension.
 
As a special case,
a topological space is [[zero-dimensional space|zero-dimensional]] with respect to the covering dimension if every open cover of the space has a refinement consisting of [[disjoint set|disjoint open sets]] so that any point in the space is contained in exactly one open set of this refinement.
 
==Examples==
Any given open cover of the [[unit circle]] will have a refinement consisting of a collection of [[open (topology)|open]] arcs. The circle has dimension one, by this definition, because any such cover can be further refined to the stage where a given point ''x'' of the circle is contained in ''at most'' two open arcs. That is, whatever collection of arcs we begin with, some can be discarded or shrunk, such that the remainder still covers the circle but with simple overlaps.
 
Similarly, any open cover of the [[unit disk]] in the two-dimensional [[plane (mathematics)|plane]] can be refined so that any point of the disk is contained in no more than three open sets, while two are in general not sufficient. The covering dimension of the disk is thus two.
 
More generally, the ''n''-dimensional [[Euclidean space]] <math>\mathbb{E}^n</math> has covering dimension ''n''.
 
 
A non-technical illustration of these examples below.
{| |-
| [[Image:Refinement_on_a_circle.png|thumb|Below is a refinement of a cover (above) of a circular line (black). Notice how in the refinement no point on the line is contained in more than two sets. Note also how the sets link to each other to form a "chain".]]
|| [[Image:Refinement_on_a_planar_shape.png|thumb|Below left is a refinement of a cover (above) of a planar shape (dark) so that all points in the shape are contained in at most three sets. Below right is an attempt to refine the cover so that no point would be contained in more than two sets. This fails in the intersection of set borders. Thus, a planar shape isn't "webby" or cannot be covered with "chains", but is in a sense thicker; i.e., its topological dimension must be higher than one.]]
|}
 
==Properties==
*[[Homeomorphic]] spaces have the same covering dimension. That is, the covering dimension is a [[topological invariant]].
*The Lebesgue covering dimension coincides with the [[affine dimension]] of a finite [[simplicial complex]]; this is the '''Lebesgue covering theorem'''.
*The covering dimension of a [[normal space]] is less than or equal to the large [[inductive dimension]].
*Covering dimension of a normal space ''X'' is <math>\le n</math> if and only if for any closed subset ''A'' of ''X'', if <math> f:A\rightarrow S^n </math> is continuous, then there is an extension of <math> f </math> to <math> g:X\rightarrow S^n </math>. Here, <math> S^n </math> is the ''n'' dimensional [[sphere]].
*(Ostrand's theorem on colored dimension.) A [[normal space]] <math>X</math> satisfies the inequality <math>0 \le \dim X \le n</math> if and only if for every locally finite open cover <math>\mathcal U= \{U_\alpha\}_{\alpha\in\mathcal A}</math> of the space <math>X</math> there exists an open cover <math>\mathcal V</math> of the space <math>X</math> which can be represented as the union of <math>n+1</math> families <math>\mathcal V_1, \mathcal V_2,\dots,\mathcal V_{n+1}</math>, where <math>\mathcal V_i=\{V_{i,\alpha}\}_{\alpha\in\mathcal A}</math>, such that each <math>\mathcal V_i</math> contains disjoint sets and <math>V_{i,\alpha}\subset U_\alpha</math> for each <math>i</math> and <math>\alpha</math>.
 
==History==
The first formal definition of covering dimension was given by [[Eduard Čech]]. It was based on an earlier result of [[Henri Lebesgue]].
 
==See also==
* [[Dimension theory]]
* [[Metacompact space]]
* [[Point-finite collection]]
 
==References==
===Historical references===
* {{aut|[[Karl Menger]]}}, ''General Spaces and Cartesian Spaces'', (1926) Communications to the Amsterdam Academy of Sciences. English translation reprinted in ''Classics on Fractals'', Gerald A.Edgar, editor, Addison-Wesley (1993) ISBN 0-201-58701-7
* {{aut|[[Karl Menger]]}}, ''Dimensionstheorie'', (1928) B.G Teubner Publishers, Leipzig.
* A. R. Pears, ''Dimension Theory of General Spaces'', (1975) Cambridge University Press. ISBN 0-521-20515-8
 
===Modern references===
* V.V. Fedorchuk, ''The Fundamentals of Dimension Theory'', appearing in ''Encyclopaedia of Mathematical Sciences, Volume 17, General Topology I'', (1993) A. V. Arkhangel'skii and L. S. Pontryagin (Eds.), Springer-Verlag, Berlin ISBN 3-540-18178-4.
 
==External links==
* {{springer|title=Lebesgue dimension|id=p/l057830}}
 
{{DEFAULTSORT:Lebesgue Covering Dimension}}
[[Category:Dimension theory]]

Latest revision as of 23:24, 20 August 2014

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