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{{about|Gauss's law concerning the electric field|analogous laws concerning different fields|Gauss's law for magnetism|and|Gauss's law for gravity|Gauss's theorem, a mathematical theorem relevant to all of these laws|Divergence theorem}}
== just two back ==
{{Electromagnetism|cTopic=Electrostatics}}


In [[physics]], '''Gauss's law''', also known as '''Gauss's flux theorem''', is a law relating the distribution of [[electric charge]] to the resulting [[electric field]].   
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The law was formulated by [[Carl Friedrich Gauss]] in 1835, but was not published until 1867.<ref>{{cite book | author=Bellone, Enrico | title=A World on Paper: Studies on the Second Scientific Revolution | year=1980}}</ref> It is one of the four [[Maxwell's equations]] which form the basis of [[classical electrodynamics]], the other three being [[Gauss's law for magnetism]], [[Faraday's law of induction]], and [[Ampère's circuital law|Ampère's law with Maxwell's correction]]. Gauss's law can be used to derive [[Coulomb's law]],<ref>{{cite book|last1=Halliday|first1=David|last2=Resnick|first2=Robert|title=Fundamentals of Physics|publisher=John Wiley & Sons, Inc|year=1970|pages=452–53}}</ref> and vice versa.
== naturally do not want this big cake falls Xiao Yan hands. ==


==Qualitative description of the law==
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In words, Gauss's law states that:
== this inner courtyard ==


:''The net outward normal [[electric flux]] through any [[closed surface]] is proportional to the total [[electric charge]] enclosed within that closed surface''.<ref>{{cite book | author=Serway, Raymond A. | title=Physics for Scientists and Engineers with Modern Physics, 4th edition | year=1996 | pages=687}}</ref>
'Really is skilled are bold ah, this inner courtyard, really horrible' Xiao Yan swallowed, in the heart muttered.<br><br>'Well, bold? which I think they are burned.' 'medicine' old snorted.<br><br>'how? ah I see seems to be nothing.' Xiao Yan surprised Road.<br><br>'Hey, now they have relied on the blockade of cage space is indeed nothing, but this is only a stopgap measure, even with [http://www.ispsc.edu.ph/nav/japandi/casio-rakuten-13.html カシオ腕時計 メンズ] that space cage, there could not have been the fall of heart inflammation blockade in the tower.'<br><br>'medicine' old hehe smiles: 'Fire can [http://www.ispsc.edu.ph/nav/japandi/casio-rakuten-1.html カシオ 腕時計 チタン] not be blocked sparse, which fall singular heart inflammation fire between heaven and earth, but by the birth of a truly destructive force within the hospital so blocked, it is like is built on a volcano barriers in general, you have seen the [http://www.ispsc.edu.ph/nav/japandi/casio-rakuten-0.html カシオ 腕時計 バンド] volcano can block up? Now [http://www.ispsc.edu.ph/nav/japandi/casio-rakuten-14.html casio 腕時計 デジタル] repressed, only in the storage power, until the outbreak of this [http://www.ispsc.edu.ph/nav/japandi/casio-rakuten-14.html カシオ 時計 電波 ソーラー] day Lianqi burning towers, the
 
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Gauss's law has a close mathematical similarity with a number of laws in other areas of physics, such as [[Gauss's law for magnetism]] and [[Gauss's law for gravity]]. In fact, any "[[inverse-square law]]" can be formulated in a way similar to Gauss's law: For example, Gauss's law itself is essentially equivalent to the inverse-square [[Coulomb's law]], and Gauss's law for gravity is essentially equivalent to the inverse-square [[Newton's law of gravity]].
<ul>
 
 
Gauss's law is something of an electrical analogue of [[Ampère's law]], which deals with magnetism.
  <li>[http://whxsme.com/forum/home.php?mod=space&uid=459066 http://whxsme.com/forum/home.php?mod=space&uid=459066]</li>
 
 
The law can be expressed mathematically using [[vector calculus]] in [[integral calculus|integral]] form and [[differential calculus|differential]] form, both are equivalent since they are related by the [[divergence theorem]], also called Gauss's theorem. Each of these forms in turn can also be expressed two ways: In terms of a relation between the [[electric field]] '''E''' and the total electric charge, or in terms of the [[electric displacement field]] '''D''' and the [[free charge|''free'' electric charge]].<ref>{{cite book|author=I.S. Grant, W.R. Phillips|title=Electromagnetism|edition=2nd|publisher=Manchester Physics, John Wiley & Sons|year=2008|isbn=978-0-471-92712-9}}</ref>
  <li>[http://www.hz-qigan.com/plus/feedback.php?aid=582 http://www.hz-qigan.com/plus/feedback.php?aid=582]</li>
 
 
==Equation involving E field==
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Gauss's law can be stated using either the [[electric field]] '''E''' or the [[electric displacement field]] '''D'''. This section shows some of the forms with '''E'''; the form with '''D''' is below, as are other forms with '''E'''.
</ul>
 
===Integral form===
 
Gauss's law may be expressed as:<ref>{{cite book|author=I.S. Grant, W.R. Phillips|title=Electromagnetism|edition=2nd|publisher=Manchester Physics, John Wiley & Sons|year=2008|isbn=978-0-471-92712-9}}</ref>
 
:<math>\Phi_E = \frac{Q}{\mathcal{E}_0}</math>
 
where Φ<sub>''E''</sub> is the [[electric flux]] through a closed surface ''S'' enclosing any volume ''V'', ''Q'' is the total [[electric charge|charge]] enclosed within ''S'', and ''ε''<sub>0</sub> is the [[electric constant]]. The electric flux Φ<sub>''E''</sub> is defined as a [[surface integral]] of the [[electric field]]:
 
:{{oiint|preintegral=<math>\Phi_E = </math>|intsubscpt=<math>{\scriptstyle S}</math>|integrand=<math>\mathbf{E} \cdot \mathrm{d}\mathbf{A} </math>}}
 
where '''E''' is the electric field, d'''A''' is a vector representing an [[infinitesimal]] element of [[area]],{{#tag:ref|More specifically, the infinitesimal area is thought of as [[Plane (mathematics)|planar]] and with area d''A''. The vector d'''A''' is [[Normal (geometry)|normal]] to this area element and has [[magnitude (vector)|magnitude]] d''A''.<ref>{{cite book|last=Matthews|first=Paul|title=Vector Calculus|publisher=Springer|year=1998|isbn=3-540-76180-2}}</ref>|group="note"}} and · represents the [[dot product]] of two vectors.
 
Since the flux is defined as an ''integral'' of the electric field, this expression of Gauss's law is called the ''integral form''.
 
====Applying the integral form====
{{Main|Gaussian surface}}
{{hatnote|See also [[Capacitance#Gauss's law|Capacitance (Gauss's law)]]}}
 
If the electric field is known everywhere, Gauss's law makes it quite easy, in principle, to find the distribution of electric charge: The charge in any given region can be deduced by integrating the electric field to find the flux.
 
However, much more often, it is the reverse problem that needs to be solved: The electric charge distribution is known, and the electric field needs to be computed. This is much more difficult, since if you know the total flux through a given surface, that gives almost no information about the electric field, which (for all you know) could go in and out of the surface in arbitrarily complicated patterns.
 
An exception is if there is some [[symmetry]] in the situation, which mandates that the electric field passes through the surface in a uniform way. Then, if the total flux is known, the field itself can be deduced at every point. Common examples of symmetries which lend themselves to Gauss's law include cylindrical symmetry, planar symmetry, and spherical symmetry. See the article [[Gaussian surface]] for examples where these symmetries are exploited to compute electric fields.
 
===Differential form===
 
By the [[divergence theorem]] Gauss's law can alternatively be written in the ''differential form'':
:<math>\nabla \cdot \mathbf{E} = \frac{\rho}{\mathcal{E}_0}</math>
 
where {{nowrap|∇ · '''E'''}} is the [[divergence]] of the electric field, ε<sub>0</sub> is the [[electric constant]], and ''ρ'' is the total electric [[charge density]].
 
===Equivalence of integral and differential forms===
{{Main|Divergence theorem}}
 
The integral and differential forms are mathematically equivalent, by the [[divergence theorem]]. Here is the argument more specifically.
 
:{| class="toccolours collapsible collapsed" width="80%" style="text-align:left"
!Outline of proof
|-
|The integral form of Gauss's law is:
:<math>\oint_S \mathbf{E} \cdot \mathrm{d}\mathbf{A} = \frac{Q}{\mathcal{E}_0}</math>
for any closed surface ''S'' containing charge ''Q''. By the divergence theorem, this equation is equivalent to:
:<math>\iiint\limits_V \nabla \cdot \mathbf{E} \ \mathrm{d}V = \frac{Q}{\mathcal{E}_0}</math>
for any volume ''V'' containing charge ''Q''. By the relation between charge and charge density, this equation is equivalent to:
:<math>\iiint\limits_V \nabla \cdot \mathbf{E} \ \mathrm{d}V = \iiint\limits_V \frac{\rho}{\mathcal{E}_0} \ \mathrm{d}V</math>
for any volume ''V''. In order for this equation to be ''simultaneously true'' for ''every'' possible volume ''V'', it is necessary (and sufficient) for the integrands to be equal everywhere. Therefore, this equation is equivalent to:
:<math>\nabla \cdot \mathbf{E} = \frac{\rho}{\mathcal{E}_0}.</math>
Thus the integral and differential forms are equivalent.
|}
 
==Equation involving D field==
{{see also|Maxwell's equations}}
 
===Free, bound, and total charge===
{{Main|Electric polarization}}
 
The electric charge that arises in the simplest textbook situations would be classified as "free charge"—for example, the charge which is transferred in [[static electricity]], or the charge on a [[capacitor]] plate. In contrast, "bound charge" arises only in the context of [[dielectric]] (polarizable) materials. (All materials are polarizable to some extent.) When such materials are placed in an external electric field, the electrons remain bound to their respective atoms, but shift a microscopic distance in response to the field, so that they're more on one side of the atom than the other. All these microscopic displacements add up to give a macroscopic net charge distribution, and this constitutes the "bound charge".
 
Although microscopically, all charge is fundamentally the same, there are often practical reasons for wanting to treat bound charge differently from free charge. The result is that the more "fundamental" Gauss's law, in terms of '''E''' (above), is sometimes put into the equivalent form below, which is in terms of '''D''' and the free charge only.
 
===Integral form===
 
This formulation of Gauss's law states analogously to the total charge form:
 
:<math>\Phi_D = Q_\text{free}\!</math>
 
where Φ<sub>''D''</sub> is the [[electric displacement field|'''D'''-field]] [[electric flux|flux]] through a surface ''S'' which encloses a volume ''V'', and ''Q''<sub>free</sub> is the free charge contained in ''V''. The flux Φ<sub>''D''</sub> is defined analogously to the flux Φ<sub>''E''</sub> of the electric field '''E''' through ''S'':
 
:{{oiint|preintegral=<math>\Phi_{D} = </math>|intsubscpt=<math>{\scriptstyle S}</math>|integrand=<math>\mathbf{D} \cdot \mathrm{d}\mathbf{A} </math>}}
 
===Differential form===
 
The differential form of Gauss's law, involving free charge only, states:
:<math>\mathbf{\nabla} \cdot \mathbf{D} = \rho_\text{free}</math>
 
where {{nowrap|∇ · '''D'''}} is the [[divergence]] of the electric displacement field, and ''ρ''<sub>free</sub> is the free electric charge density.
 
==Equivalence of total and free charge statements==
 
:{| class="toccolours collapsible collapsed" width="80%" style="text-align:left"
!Proof that the formulations of Gauss's law in terms of free charge are equivalent to the formulations involving total charge.
|-
|In this proof, we will show that the equation
:<math>\nabla\cdot \mathbf{E} = \rho/\mathcal{E}_0</math>
is equivalent to the equation
:<math>\nabla\cdot\mathbf{D} = \rho_{\mathrm{free}}</math>
Note that we're only dealing with the differential forms, not the integral forms, but that is sufficient since the differential and integral forms are equivalent in each case, by the divergence theorem.
 
We introduce the [[polarization density]] '''P''', which has the following relation to '''E''' and '''D''':
:<math>\mathbf{D}=\mathcal{E}_0 \mathbf{E} + \mathbf{P}</math>
and the following relation to the bound charge:
:<math>\rho_{\mathrm{bound}} = -\nabla\cdot \mathbf{P}</math>
Now, consider the three equations:
:<math>\rho_{\mathrm{bound}} = \nabla\cdot (-\mathbf{P})</math>
:<math>\rho_{\mathrm{free}} = \nabla\cdot \mathbf{D}</math>
:<math>\rho = \nabla \cdot(\mathcal{E}_0\mathbf{E})</math>
The key insight is that the sum of the first two equations is the third equation. This completes the proof: The first equation is true by definition, and therefore the second equation is true [[if and only if]] the third equation is true. So the second and third equations are equivalent, which is what we wanted to prove.
|}
 
==Equation for linear materials==
 
In [[homogeneous]], [[isotropic]], [[Dispersion (optics)|nondispersive]], [[linear material]]s, there is a simple relationship between '''E''' and&nbsp;'''D''':
 
:<math>\mathbf{D} = \mathcal{E} \mathbf{E} </math>
 
where ''ε'' is the [[permittivity]] of the material. For the case of [[vacuum]] (aka [[free space]]), ''ε'' = ''ε''<sub>0</sub>. Under these circumstances, Gauss's law modifies to
 
:<math>\Phi_E = \frac{Q_\text{free}}{\mathcal{E}}</math>
 
for the integral form, and
 
:<math>\mathbf{\nabla} \cdot \mathbf{E} = \frac{\rho_\text{free}}{\mathcal{E}}</math>
 
for the differential form.
 
==Relation to Coulomb's law==
 
===Deriving Gauss's law from Coulomb's law===
 
Gauss's law can be derived from [[Coulomb's law]].
 
:{| class="toccolours collapsible collapsed" width="80%" style="text-align:left"
!Outline of proof
|-
|[[Coulomb's law]] states that the electric field due to a stationary [[point charge]] is:
 
:<math>\mathbf{E}(\mathbf{r}) = \frac{q}{4\pi \mathcal{E}_0} \frac{\mathbf{e_r}}{r^2}</math>
where
:'''e<sub>r</sub>''' is the radial [[unit vector]],
:''r'' is the radius, |'''r'''|,
:<math>\mathcal{E}_0</math> is the [[electric constant]],
:''q'' is the charge of the particle, which is assumed to be located at the [[origin (mathematics)|origin]].
 
Using the expression from Coulomb's law, we get the total field at '''r''' by using an integral to sum the field at '''r''' due to the infinitesimal charge at each other point '''s''' in space, to give
 
:<math>\mathbf{E}(\mathbf{r}) = \frac{1}{4\pi\mathcal{E}_0} \int \frac{\rho(\mathbf{s})(\mathbf{r}-\mathbf{s})}{|\mathbf{r}-\mathbf{s}|^3} \,  d^3 \mathbf{s}</math>
 
where <math>\rho</math> is the charge density. If we take the divergence of both sides of this equation with respect to '''r''', and use the known theorem<ref>See, for example, {{cite book | author=Griffiths, David J. | title=Introduction to Electrodynamics (3rd ed.) | publisher=Prentice Hall | year=1998 | isbn=0-13-805326-X | page=50}}</ref>
 
:<math>\nabla \cdot \left(\frac{\mathbf{r}}{|\mathbf{r}|^3}\right) = 4\pi \delta(\mathbf{r})</math>
 
where δ('''r''') is the [[Dirac delta function]], the result is
 
:<math>\nabla\cdot\mathbf{E}(\mathbf{r}) = \frac{1}{\mathcal{E}_0} \int \rho(\mathbf{s})\ \delta(\mathbf{r}-\mathbf{s})\, d^3 \mathbf{s}</math>
 
Using the "[[Dirac delta function#Translation|sifting<!--Note: This is not a typo, the word is really 'sifting' not 'shifting'--> property]]" of the Dirac delta function, we arrive at
 
:<math>\nabla\cdot\mathbf{E}(\mathbf{r}) = \frac{\rho(\mathbf{r})}{\mathcal{E}_0},</math>
 
which is the differential form of Gauss's law, as desired.
|}
 
Note that since Coulomb's law only applies to ''stationary'' charges, there is no reason to expect Gauss's law to hold for moving charges ''based on this derivation alone''. In fact, Gauss's law ''does'' hold for moving charges, and in this respect Gauss's law is more general than Coulomb's law.
 
===Deriving Coulomb's law from Gauss's law===
 
Strictly speaking, Coulomb's law cannot be derived from Gauss's law alone, since Gauss's law does not give any information regarding the [[Curl (mathematics)|curl]] of '''E''' (see [[Helmholtz decomposition]] and [[Faraday's law of induction|Faraday's law]]). However, Coulomb's law ''can'' be proven from Gauss's law if it is assumed, in addition, that the electric field from a [[point charge]] is spherically-symmetric (this assumption, like Coulomb's law itself, is exactly true if the charge is stationary, and approximately true if the charge is in motion).
 
:{| class="toccolours collapsible collapsed" width="80%" style="text-align:left"
!Outline of proof
|-
|Taking ''S'' in the integral form of Gauss's law to be a spherical surface of radius ''r'', centered at the point charge ''Q'', we have
 
:<math>\oint_{S}\mathbf{E}\cdot d\mathbf{A} = \frac{Q}{\mathcal{E}_0} </math>
 
By the assumption of spherical symmetry, the integrand is a constant which can be taken out of the integral. The result is
 
: <math>4\pi r^2\hat{\mathbf{r}}\cdot\mathbf{E}(\mathbf{r}) = \frac{Q}{\mathcal{E}_0}</math>
 
where <math>\hat{\mathbf{r}}</math> is a [[unit vector]] pointing radially away from the charge. Again by spherical symmetry, '''E''' points in the radial direction, and so we get
 
: <math>\mathbf{E}(\mathbf{r}) = \frac{Q}{4\pi \mathcal{E}_0} \frac{\hat{\mathbf{r}}}{r^2}</math>
 
which is essentially equivalent to Coulomb's law. Thus the [[inverse-square law]] dependence of the electric field in Coulomb's law follows from Gauss's law.
|}
 
==See also==
{{Wikipedia books|Maxwell's equations}}
* [[Method of image charges]]
* [[Uniqueness theorem for Poisson's equation]]
 
==Notes==
{{Reflist|group=note}}
 
==References==
{{Reflist}}<!--added under references heading by script-assisted edit-->
Jackson, John David (1999). Classical Electrodynamics, 3rd ed., New York: Wiley. ISBN 0-471-30932-X.
 
==External links==
* [http://ocw.mit.edu/OcwWeb/Physics/8-02Electricity-and-MagnetismSpring2002/VideoAndCaptions/ MIT Video Lecture Series (30 x 50 minute lectures)- Electricity and Magnetism] Taught by Professor [[Walter Lewin]].
*[http://www.lightandmatter.com/html_books/0sn/ch10/ch10.html#Section10.6 section on Gauss's law in an online textbook]
*[http://www.physnet.org/modules/pdf_modules/m132.pdf <small>MISN-0-132</small> ''Gauss's Law for Spherical Symmetry''] ([[Portable Document Format|PDF file]]) by Peter Signell for [http://www.physnet.org Project PHYSNET].
*[http://www.physnet.org/modules/pdf_modules/m133.pdf <small>MISN-0-133</small> ''Gauss's Law Applied to Cylindrical and Planar Charge Distributions] (PDF file) by Peter Signell for [http://www.physnet.org Project PHYSNET].
 
[[Category:Electrostatics]]
[[Category:Vector calculus]]
[[Category:Maxwell's equations]]

Revision as of 02:52, 20 February 2014

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naturally do not want this big cake falls Xiao Yan hands.

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voice down, two forceful momentum of the body is the storm surge from the gold and silver out of the old couple finally come together, enveloped the casio 腕時計 スタンダード entire auction!

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'Really is skilled are bold ah, this inner courtyard, really horrible' Xiao Yan swallowed, in the heart muttered.

'Well, bold? which I think they are burned.' 'medicine' old snorted.

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