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The '''[[row space]] and [[column space]]''' of an ''m''-by-''n'' [[matrix (mathematics)|matrix]] are the [[linear subspace]]s generated by row vectors and column vectors, respectively, of the matrix. Its [[Hamel dimension|dimension]] is equal to the [[Rank (linear algebra)|rank]] of the matrix and is at most min(''m'',&#8239;''n'').<ref>http://www.cliffsnotes.com/WileyCDA/CliffsReviewTopic/Row-Space-and-Column-Space-of-a-Matrix.topicArticleId-20807,articleId-20793.html</ref>


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The rest of article will consider matrices of [[real number]]s: row and column spaces are subspace of '''R'''<sup>''n''</sup> and '''R'''<sup>''m''</sup> [[real coordinate space|real spaces]] respectively. But row and column spaces can be constructed from matrices with components in any [[field (mathematics)|field]] and even a [[ring (mathematics)|ring]].
 
==Overview==
Let A be a ''m''-by-''n'' matrix. Then
# rank(A) = dim(rowsp(A)) = dim(colsp(A)),
# rank(A) = number of pivots in any echelon form of A,
# rank(A) = the maximum number of linearly independent rows or columns of A.
 
If one considers the matrix as a [[linear transformation]] from '''R'''<sup>''n''</sup> to '''R'''<sup>''m''</sup>, then the column space of the matrix equals the [[image (mathematics)|image]] of this linear transformation.
 
The column space of a matrix A is the set of all linear combinations of the columns in A. If A = ['''a'''<sub>1</sub>, ...., '''a'''<sub>n</sub>], then colsp(A) = span {'''a'''<sub>1</sub>, ...., '''a'''<sub>n</sub>}.
 
The concept of '''row space''' generalises to matrices to '''C''', the field of [[complex number]]s, or to any [[field (mathematics)|field]].
 
Intuitively, given a matrix '''A''', the action of the matrix '''A''' on a vector '''x''' will return a linear combination of the columns of '''A''' weighted by the coordinates of '''x''' as coefficients. Another way to look at this is that it will (1) first project '''x''' into the '''row space''' of A, (2) perform an invertible transformation, and (3) place the resulting vector '''y''' in the '''column space''' of '''A'''. Thus the result ''' y =A x''' must reside in the '''column space''' of A. See the [[singular value decomposition]] for more details on this second interpretation.
 
==Example==
Given a matrix J:
:<math>
  J =
  \begin{bmatrix}
    2 & 4 & 1 & 3 & 2\\
    -1 & -2 & 1 & 0 & 5\\
    1 & 6 & 2 & 2 & 2\\
    3 & 6 & 2 & 5 & 1
  \end{bmatrix}
</math>
the rows are
'''r'''<sub>1</sub> = (2,4,1,3,2),
'''r'''<sub>2</sub> = (−1,−2,1,0,5),
'''r'''<sub>3</sub> = (1,6,2,2,2),
'''r'''<sub>4</sub> = (3,6,2,5,1).
Consequently the row space of J is the subspace of '''R'''<sup>5</sup> [[linear span|spanned]] by { '''r'''<sub>1</sub>, '''r'''<sub>2</sub>, '''r'''<sub>3</sub>, '''r'''<sub>4</sub> }. 
Since these four row vectors are [[Linear independence|linearly independent]], the row space is 4-dimensional. Moreover in this case it can be seen that they are all [[orthogonality|orthogonal]] to the vector '''n''' = (6,−1,4,−4,0), so it can be deduced that the row space consists of all vectors in '''R'''<sup>5</sup> that are orthogonal to '''n'''.
 
==See also==
*[[Row space]]
*[[Column space]]
*[[null space]]
 
==External links==
{{wikibooks|Linear Algebra/Column and Row Spaces}}
*[http://mfile.akamai.com/7870/rm/mitstorage.download.akamai.com/7870/18/18.06/videolectures/strang-1806-lec06-20sep1999-80k.rm Lecture on column space and nullspace by Gilbert Strang of MIT]
*[http://wps.prenhall.com/am_leon_linearalg_7/53/13727/3514210.cw/content/index.html Row Space and Column Space]
 
==Notes==
{{reflist}}
 
[[Category:Abstract algebra]]
[[Category:Linear algebra]]

Revision as of 21:58, 31 January 2014

The row space and column space of an m-by-n matrix are the linear subspaces generated by row vectors and column vectors, respectively, of the matrix. Its dimension is equal to the rank of the matrix and is at most min(m, n).[1]

The rest of article will consider matrices of real numbers: row and column spaces are subspace of Rn and Rm real spaces respectively. But row and column spaces can be constructed from matrices with components in any field and even a ring.

Overview

Let A be a m-by-n matrix. Then

  1. rank(A) = dim(rowsp(A)) = dim(colsp(A)),
  2. rank(A) = number of pivots in any echelon form of A,
  3. rank(A) = the maximum number of linearly independent rows or columns of A.

If one considers the matrix as a linear transformation from Rn to Rm, then the column space of the matrix equals the image of this linear transformation.

The column space of a matrix A is the set of all linear combinations of the columns in A. If A = [a1, ...., an], then colsp(A) = span {a1, ...., an}.

The concept of row space generalises to matrices to C, the field of complex numbers, or to any field.

Intuitively, given a matrix A, the action of the matrix A on a vector x will return a linear combination of the columns of A weighted by the coordinates of x as coefficients. Another way to look at this is that it will (1) first project x into the row space of A, (2) perform an invertible transformation, and (3) place the resulting vector y in the column space of A. Thus the result y =A x must reside in the column space of A. See the singular value decomposition for more details on this second interpretation.

Example

Given a matrix J:

J=[24132121051622236251]

the rows are r1 = (2,4,1,3,2), r2 = (−1,−2,1,0,5), r3 = (1,6,2,2,2), r4 = (3,6,2,5,1). Consequently the row space of J is the subspace of R5 spanned by { r1, r2, r3, r4 }. Since these four row vectors are linearly independent, the row space is 4-dimensional. Moreover in this case it can be seen that they are all orthogonal to the vector n = (6,−1,4,−4,0), so it can be deduced that the row space consists of all vectors in R5 that are orthogonal to n.

See also

External links

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