Babuška–Lax–Milgram theorem: Difference between revisions

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In [[functional analysis]], a branch of mathematics, the '''Shilov boundary''' is the smallest  [[closed set|closed]] subset of the [[structure space]] of a [[commutative]] [[Banach algebra]] where an analog of the [[maximum modulus principle]] holds. It is named after its discoverer, [[Georgii Evgen'evich Shilov]].
 
== Precise definition and existence ==
Let <math>\mathcal A</math> be a [[commutative]] [[Banach algebra]] and let <math>\Delta \mathcal A</math> be its [[structure space]] equipped with the [[relative topology|relative]] [[weak topology|weak*-topology]] of the [[continuous dual space|dual]] <math>{\mathcal A}^*</math>. A closed (in this topology) subset <math>F</math> of <math>\Delta {\mathcal A}</math> is called a '''boundary''' of <math>{\mathcal A}</math> if <math>\max_{f \in \Delta {\mathcal A}} |x(f)|=\max_{f \in F} |x(f)|</math> for all <math>x \in \mathcal A</math>.
The set <math>S=\bigcap\{F:F \text{ is a boundary of } {\mathcal A}\}</math> is called the '''Shilov boundary'''. It has been proved by Shilov<ref>Theorem 4.15.4 in [[Einar Hille]], [[Ralph S. Phillips]]: [http://www.ams.org/online_bks/coll31/coll31-chIV.pdf Functional analysis and semigroups]. -- AMS, Providence 1957.</ref> that <math>S</math> is a boundary of <math>{\mathcal A}</math>.
 
Thus one may also say that Shilov boundary is the unique set <math>S \subset \Delta \mathcal A</math> which satisfies
#<math>S</math> is a boundary of <math>\mathcal A</math>, and
#whenever <math>F</math> is a boundary of <math>\mathcal A</math>, then <math>S \subset F</math>.
 
== Examples ==
*Let <math>\mathbb D=\{z \in \mathbb C:|z|<1\}</math> be the [[open unit disc]] in the [[complex plane]] and let
<math>{\mathcal A}={\mathcal H}(\mathbb D)\cap {\mathcal C}(\bar{\mathbb D})</math> be the [[disc algebra]], i.e. the functions [[holomorphic]] in <math>\mathbb D</math> and [[continuous function|continuous]] in the [[closure (topology)|closure]] of <math>\mathbb D</math> with [[supremum norm]] and usual algebraic operations. Then <math>\Delta {\mathcal A}=\bar{\mathbb D}</math> and <math>S=\{|z|=1\}</math>.
 
== References ==
*{{Springer|id=B/b110310|title=Bergman-Shilov boundary}}
 
==Notes==
{{Reflist}}
 
== See also ==
*[[James boundary]]
 
[[Category:Banach algebras]]

Revision as of 06:04, 28 December 2013

In functional analysis, a branch of mathematics, the Shilov boundary is the smallest closed subset of the structure space of a commutative Banach algebra where an analog of the maximum modulus principle holds. It is named after its discoverer, Georgii Evgen'evich Shilov.

Precise definition and existence

Let 𝒜 be a commutative Banach algebra and let Δ𝒜 be its structure space equipped with the relative weak*-topology of the dual 𝒜*. A closed (in this topology) subset F of Δ𝒜 is called a boundary of 𝒜 if maxfΔ𝒜|x(f)|=maxfF|x(f)| for all x𝒜. The set S={F:F is a boundary of 𝒜} is called the Shilov boundary. It has been proved by Shilov[1] that S is a boundary of 𝒜.

Thus one may also say that Shilov boundary is the unique set SΔ𝒜 which satisfies

  1. S is a boundary of 𝒜, and
  2. whenever F is a boundary of 𝒜, then SF.

Examples

𝒜=(𝔻)𝒞(𝔻¯) be the disc algebra, i.e. the functions holomorphic in 𝔻 and continuous in the closure of 𝔻 with supremum norm and usual algebraic operations. Then Δ𝒜=𝔻¯ and S={|z|=1}.

References

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Notes

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See also

  1. Theorem 4.15.4 in Einar Hille, Ralph S. Phillips: Functional analysis and semigroups. -- AMS, Providence 1957.