Carathéodory's theorem (conformal mapping): Difference between revisions

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{{about|the theorem of real analysis|the separation thereom in descriptive set theory|Lusin's separation theorem}}
 
In the [[mathematics|mathematical]] field of [[real analysis]], '''Lusin's theorem''' (or '''Luzin's theorem''', named for [[Nikolai Luzin]]) states that every [[measurable function]] is a [[continuous function]] on nearly all its domain. In the [[Littlewood's second principle|informal formulation]] of [[J. E. Littlewood]], "every measurable function is nearly continuous".
 
==Classical statement==
 
For an interval [''a'',&nbsp;''b''], let
 
:<math>f:[a,b]\rightarrow \mathbb{C}</math>
 
be a measurable function.  Then, for every ''&epsilon;''&nbsp;>&nbsp;0, there exists a compact ''E''&nbsp;&sub;&nbsp;[''a'',&nbsp;''b''] such that ''f'' restricted to ''E'' is continuous and
 
:<math>\mu ( E ) > b - a - \varepsilon.\,</math>
 
Note that ''E'' inherits the [[subspace topology]] from [''a'',&nbsp;''b'']; continuity of ''f'' restricted to ''E'' is defined using this topology.
 
==General form==
Let <math>(X,\Sigma,\mu)</math> be a [[Radon measure]] space and ''Y'' be a [[second-countable]] topological space, let
 
:<math>f: X \rightarrow Y</math>
 
be a measurable function. Given ε > 0, for every <math>A\in\Sigma</math> of finite measure there is a closed set ''E'' with ''µ(A \ E) < ε'' such that ''f'' restricted to ''E'' is continuous. If ''A'' is [[locally compact]], we can choose ''E'' to be compact and even find a continuous function <math>f_\varepsilon: X \rightarrow Y</math> with compact support that coincides with ''f'' on ''E''.
 
Informally, measurable functions into spaces with countable base can be approximated by continuous functions on arbitrarily large portion of their domain.
 
==A proof of Lusin's theorem==
 
Since ''f'' is measurable, there exists a sequence of [[step function]]s, ''f''<sub>''n''</sub> converging to f pointwise [[almost everywhere]]. Each ''f''<sub>''n''</sub> is bounded on a set of finite measure, hence [[integrable]]. By [[Egorov's theorem]], may take a closed set E, such that the measure of ''A \ E'' is arbitrarily small, and such that ''f''<sub>''n''</sub> converges to ''f'' [[Uniform convergence|''uniformly'']]. Thus ''f'' is in [[Lp space#Dense subspaces|L<sup>1</sup>]](''A''). Since continuous functions are [[dense set|dense]] in [[Lp space#Dense subspaces|L<sup>1</sup>]], we may approximate ''f'' with a [[continuous function]] defined on A.
 
== References ==
 
* N. Lusin.  Sur les propriétés des fonctions mesurables, ''Comptes Rendus Acad. Sci. Paris'' 154 (1912), 1688-1690.
 
* G. Folland. Real Analysis: Modern Techniques and Their Applications, 2nd ed. Chapter 2
 
* W. Zygmunt. Scorza-Dragoni property (in Polish), UMCS, Lublin, 1990
 
[[Category:Theorems in real analysis]]
[[Category:Theorems in measure theory]]
[[Category:Articles containing proofs]]

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In the mathematical field of real analysis, Lusin's theorem (or Luzin's theorem, named for Nikolai Luzin) states that every measurable function is a continuous function on nearly all its domain. In the informal formulation of J. E. Littlewood, "every measurable function is nearly continuous".

Classical statement

For an interval [ab], let

f:[a,b]

be a measurable function. Then, for every ε > 0, there exists a compact E ⊂ [ab] such that f restricted to E is continuous and

μ(E)>baε.

Note that E inherits the subspace topology from [ab]; continuity of f restricted to E is defined using this topology.

General form

Let (X,Σ,μ) be a Radon measure space and Y be a second-countable topological space, let

f:XY

be a measurable function. Given ε > 0, for every AΣ of finite measure there is a closed set E with µ(A \ E) < ε such that f restricted to E is continuous. If A is locally compact, we can choose E to be compact and even find a continuous function fε:XY with compact support that coincides with f on E.

Informally, measurable functions into spaces with countable base can be approximated by continuous functions on arbitrarily large portion of their domain.

A proof of Lusin's theorem

Since f is measurable, there exists a sequence of step functions, fn converging to f pointwise almost everywhere. Each fn is bounded on a set of finite measure, hence integrable. By Egorov's theorem, may take a closed set E, such that the measure of A \ E is arbitrarily small, and such that fn converges to f uniformly. Thus f is in L1(A). Since continuous functions are dense in L1, we may approximate f with a continuous function defined on A.

References

  • N. Lusin. Sur les propriétés des fonctions mesurables, Comptes Rendus Acad. Sci. Paris 154 (1912), 1688-1690.
  • G. Folland. Real Analysis: Modern Techniques and Their Applications, 2nd ed. Chapter 2
  • W. Zygmunt. Scorza-Dragoni property (in Polish), UMCS, Lublin, 1990