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In [[complex analysis]] and [[numerical analysis]], '''König's theorem''',<ref>{{cite book|last=Householder|first=Alston Scott|year=1970|title=The Numerical Treatment of a Single Nonlinear Equation|publisher=McGraw-Hill|lccn=79-103908|page=115}}</ref> named after the Hungarian mathematician [[Gyula Kőnig]], gives a way to estimate simple poles or simple roots of a function. In particular, it has numerous applications in [[Root-finding algorithm|root finding algorithms]] like [[Newton's method]] and its generalization [[Householder's method]].
 
== Statement ==
Given a [[meromorphic function]] defined on <math>|x|<R</math>:
:<math>f(x) = \sum_{n=0}^\infty c_nx^n, \qquad c_0\neq 0.</math>
Suppose it only has one simple pole <math>x=r</math> in this disk. If <math>0<\sigma<1</math> such that <math>|r|<\sigma R</math>, then
:<math>\frac{c_n}{c_{n+1}} = r + o(\sigma^{n+1}).</math>
In particular, we have
:<math>\lim_{n\rightarrow \infty} \frac{c_n}{c_{n+1}} = r.</math>
 
== Intuition ==
Near ''x=r'' we expect the function to be dominated by the pole:
:<math>f(x)\approx\frac{C}{x-r}=-\frac{C}{r}\,\frac{1}{1-x/r}=-\frac{C}{r}\sum_{n=0}^{\infty}\left[\frac{x}{r}\right]^n.</math>
Matching the coefficients we see that <math>\frac{c_n}{c_{n+1}}\approx r</math>.
 
== References ==
{{reflist}}
 
{{DEFAULTSORT:Konig's theorem (complex analysis)}}
[[Category:Theorems in complex analysis]]

Revision as of 23:40, 13 January 2014

In complex analysis and numerical analysis, König's theorem,[1] named after the Hungarian mathematician Gyula Kőnig, gives a way to estimate simple poles or simple roots of a function. In particular, it has numerous applications in root finding algorithms like Newton's method and its generalization Householder's method.

Statement

Given a meromorphic function defined on |x|<R:

f(x)=n=0cnxn,c00.

Suppose it only has one simple pole x=r in this disk. If 0<σ<1 such that |r|<σR, then

cncn+1=r+o(σn+1).

In particular, we have

limncncn+1=r.

Intuition

Near x=r we expect the function to be dominated by the pole:

f(x)Cxr=Cr11x/r=Crn=0[xr]n.

Matching the coefficients we see that cncn+1r.

References

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