Special classes of semigroups: Difference between revisions
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{{Orphan|date=September 2013}} | |||
When calculating the unstable fraction of the [[radioactivity]] in the original [[isotope]] [[Atomic nucleus|nucleus]], there is a simple equation which can help you find the fraction of unstable nuclei still [[radioactive]] after a given period of half-lives. | |||
== Equation == | |||
<math>p=1/2^n</math> | |||
when <math>p</math> is the fraction of unstable nucleus, and <math>n</math> the number of half lives. | |||
'''''Example:''''' | |||
'' '''Q:''' The Half Life of [[Cobalt-60]] is 5 years. After 225 years, what fraction of the [[Cobalt-60]] is still unstable?'' | |||
'''''A:''' (225÷5=45 will find you the number of half lives.)'' | |||
''<math>p=1/2^n</math>'' | |||
''<math>p=1/2^{45}</math>'' | |||
{{DEFAULTSORT:Radioactive Instability in the Nucleus - Formula}} | |||
[[Category:Radioactivity]] |
Revision as of 08:17, 26 January 2014
When calculating the unstable fraction of the radioactivity in the original isotope nucleus, there is a simple equation which can help you find the fraction of unstable nuclei still radioactive after a given period of half-lives.
Equation
when is the fraction of unstable nucleus, and the number of half lives.
Example:
Q: The Half Life of Cobalt-60 is 5 years. After 225 years, what fraction of the Cobalt-60 is still unstable?
A: (225÷5=45 will find you the number of half lives.)