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In [[mathematics]], '''Friedrichs' inequality''' is a [[theorem]] of [[functional analysis]], due to [[Kurt O. Friedrichs|Kurt Friedrichs]]. It places a bound on the [[Lp space|''L<sup>p</sup>'' norm]] of a function using ''L<sup>p</sup>'' bounds on the [[weak derivative]]s of the function and the [[geometry]] of the [[Domain (mathematics)|domain]], and can be used to show that certain [[norm (mathematics)|norms]] on [[Sobolev space]]s are equivalent.


==Statement of the inequality==


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Let &Omega; be a [[bounded set|bounded subset]] of [[Euclidean space]] '''R'''<sup>''n''</sup> with [[diameter]] ''d''. Suppose that ''u'' : &Omega; &rarr; '''R''' lies in the Sobolev space <math>W_{0}^{k, p} (\Omega)</math> (i.e. ''u'' lies in ''W''<sup>''k'',''p''</sup>(&Omega;) and the [[Sobolev space#Traces|trace]] of ''u'' is zero). Then


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:<math>\| u \|_{L^{p} (\Omega)} \leq d^{k} \left( \sum_{| \alpha | = k} \| \mathrm{D}^{\alpha} u \|_{L^{p} (\Omega)}^{p} \right)^{1/p}.</math>


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In the above
* <math>\| \cdot \|_{L^{p} (\Omega)}</math> denotes the [[Lp space|''L<sup>p</sup>'' norm]];
* ''&alpha;'' = (''&alpha;''<sub>1</sub>, ..., ''&alpha;''<sub>''n''</sub>) is a [[multi-index]] with norm |''&alpha;''| = ''&alpha;''<sub>1</sub> + ... + ''&alpha;''<sub>''n''</sub>;
* D<sup>&alpha;</sup>''u'' is the mixed [[partial derivative]]
::<math>\mathrm{D}^{\alpha} u = \frac{\partial^{| \alpha |} u}{\partial_{x_{1}}^{\alpha_{1}} \cdots \partial_{x_{n}}^{\alpha_{n}} }.</math>
 
==See also==
*[[Poincaré inequality]]
 
[[Category:Sobolev spaces]]
[[Category:Inequalities]]
 
 
{{mathanalysis-stub}}

Latest revision as of 02:17, 16 March 2013

In mathematics, Friedrichs' inequality is a theorem of functional analysis, due to Kurt Friedrichs. It places a bound on the Lp norm of a function using Lp bounds on the weak derivatives of the function and the geometry of the domain, and can be used to show that certain norms on Sobolev spaces are equivalent.

Statement of the inequality

Let Ω be a bounded subset of Euclidean space Rn with diameter d. Suppose that u : Ω → R lies in the Sobolev space W0k,p(Ω) (i.e. u lies in Wk,p(Ω) and the trace of u is zero). Then

uLp(Ω)dk(|α|=kDαuLp(Ω)p)1/p.

In the above

Dαu=|α|ux1α1xnαn.

See also


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