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A '''spherical pendulum''' is a [[generalization]] of the [[pendulum]].
It consists of a [[mass]] moving without [[friction]] on a [[sphere]].  The only [[force]]s acting on the mass are the [[reaction (physics)|reaction]] from the sphere and [[gravity]].
 
It is convenient to use [[spherical coordinates]] and describe the position of the mass in terms of <math>(r,\theta,\phi)</math>, where ''r'' is fixed.
 
The [[Lagrangian]] is <ref>{{cite book
  | last = Landau
  | first = Lev Davidovich
  | authorlink =
  | coauthors = Evgenii Mikhailovich Lifshitz
  | title = Course of Theoretical Physics: Volume 1 Mechanics
  | publisher = Butterworth-Heinenann
  | year = 1976
  | location =
  | pages = 33–34
  | url =
  | doi =
  | id =
  | isbn = 0750628960}}</ref>
 
:<math>
L=\frac{1}{2}
mr^2\left(
  \dot{\theta}^2+\sin^2\theta\ \dot{\phi}^2
\right)
+ mgr\cos\theta.
</math>
 
The [[Euler-Lagrange equations]] give :
 
:<math>
\frac{d}{dt}
\left(mr^2\dot{\theta}
\right)
-mr^2\sin\theta\cos\theta\dot{\phi}^2+
mgr\sin\theta =0
</math>
and
:<math>
\frac{d}{dt}
\left(
  mr^2\sin^2\theta
  \,
  \dot{\phi}
\right)
=0
</math>
showing that [[angular momentum]] is conserved.
 
And the Hamiltonian is
 
:<math>H=P_\theta\dot \theta + P_\phi\dot \phi-L</math>
 
where
 
:<math>P_\theta=\frac{\partial L}{\partial \dot \theta}=mr^2\dot \theta</math>
 
and
 
:<math>P_\phi=\frac{\partial L}{\partial \dot \phi} = mr^2\dot \phi \sin^2 \theta</math>
 
==See also==
*[[Conical pendulum|Conical Pendulum]]
*[[Newton's laws of motion#The three laws in detail|Newton's three laws of motion]]
*[[Pendulum]]
*[[Pendulum (mathematics)]]
 
==References==
{{reflist}}
 
[[Category:Pendulums]]

Latest revision as of 19:42, 29 September 2012

A spherical pendulum is a generalization of the pendulum. It consists of a mass moving without friction on a sphere. The only forces acting on the mass are the reaction from the sphere and gravity.

It is convenient to use spherical coordinates and describe the position of the mass in terms of (r,θ,ϕ), where r is fixed.

The Lagrangian is [1]

L=12mr2(θ˙2+sin2θϕ˙2)+mgrcosθ.

The Euler-Lagrange equations give :

ddt(mr2θ˙)mr2sinθcosθϕ˙2+mgrsinθ=0

and

ddt(mr2sin2θϕ˙)=0

showing that angular momentum is conserved.

And the Hamiltonian is

H=Pθθ˙+Pϕϕ˙L

where

Pθ=Lθ˙=mr2θ˙

and

Pϕ=Lϕ˙=mr2ϕ˙sin2θ

See also

References

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