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: ''For other inequalities named after Wirtinger, see [[Wirtinger's inequality]].''
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In [[mathematics]], historically '''Wirtinger's inequality''' for real functions was an [[inequality (mathematics)|inequality]] used in [[Fourier analysis]]. It was named after [[Wilhelm Wirtinger]]. It was used in 1904  to prove the [[isoperimetric inequality]].  A variety of closely related results are today known as Wirtinger's inequality.
 
==Theorem==
===First version===
Let <math>f : \mathbb{R} \to \mathbb{R}</math> be a [[periodic function]] of period 2π, which is continuous and has a continuous derivative throughout '''R''', and such that
 
:<math>\int_0^{2\pi}f(x) \, dx = 0.</math>
 
Then
 
:<math>\int_0^{2\pi}f'^2(x) \, dx \ge \int_0^{2\pi}f^2(x) \, dx</math>
 
with equality [[if and only if]] ''f''(''x'') = ''a'' sin(''x'') + ''b'' cos(''x'') for some ''a'' and ''b'' (or equivalently ''f''(''x'') = ''c'' sin (''x'' + ''d'') for some ''c'' and ''d'').
 
This version of the Wirtinger inequality is the one-dimensional [[Poincaré inequality]], with optimal constant.
 
===Second version===
The following related inequality is also called Wirtinger's inequality {{harv|Dym|McKean|1985}}:
 
:<math>\pi^{2}\int_0^a |f|^2 \le a^2 \int_0^a|f'|^2</math>
 
whenever ''f'' is a C<sup>1</sup> function such that ''f''(0)&nbsp;=&nbsp;''f''(''a'')&nbsp;=&nbsp;0. In this form, Wirtinger's inequality is seen as the one-dimensional version of [[Friedrichs' inequality]].
 
===Proof===
The proof of the two versions are similar. Here is a proof of the first version of the inequality. Since [[Dirichlet's conditions]] are met, we can write
 
:<math>f(x)=\frac{1}{2}a_0+\sum_{n\ge 1}\left(a_n\frac{\sin nx}{\sqrt{\pi}}+b_n\frac{\cos nx}{\sqrt{\pi}}\right),</math>
 
and moreover ''a''<sub>0</sub> = 0 since the integral of ''f'' vanishes. By [[Parseval's identity]],
 
:<math>\int_0^{2\pi}f^2(x)dx=\sum_{n=1}^\infty(a_n^2+b_n^2)</math>
 
and
 
:<math>\int_0^{2\pi}f'^2(x) \, dx = \sum_{n=1}^\infty n^2(a_n^2+b_n^2)</math>
 
and since the summands are all ≥ 0, we get the desired inequality, with equality if and only if ''a<sub>n</sub>'' = ''b<sub>n</sub>'' = 0 for all ''n'' ≥ 2.
 
==References==
*{{citation|first1=H|last1=Dym|authorlink1=Harry Dym|first2=H|last2=McKean|title=Fourier series and integrals|publisher=Academic press|year=1985|isbn=978-0-12-226451-1}}
*[[Vadim Komkov|Komkov, Vadim]] (1983) Euler's buckling formula and Wirtinger's inequality. Internat. J. Math. Ed. Sci. Tech. 14, no. 6, 661—668.
 
{{PlanetMath attribution|id=5393|title=Wirtinger's inequality}}
 
[[Category:Fourier analysis]]
[[Category:Inequalities]]
[[Category:Theorems in analysis]]

Latest revision as of 05:49, 13 January 2015

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