|
|
Line 1: |
Line 1: |
| In [[mathematics]], in the realm of [[group theory]], a [[countable]] [[group (mathematics)|group]] is said to be '''SQ-universal''' if every countable group can be embedded in one of its [[quotient]] groups. SQ-universality can be thought of as a measure of largeness or complexity of a group.
| | I am Oscar and I completely dig that title. Supervising is my profession. California is exactly where her home is but she requirements to transfer because of her family. One of over the counter std test ([http://yenisehir.de/index.php?do=/profile-7188/info/ click through the next web page]) things she loves most is to study comics and she'll be beginning something else along with it. |
| | |
| ==History==
| |
| Many classic results of combinatorial group theory, going back to 1949, are now interpreted as saying that a particular group or class of groups is (are) SQ-universal. However the first explicit use of the term seems to be in an address given by [[Peter M Neumann|Peter Neumann]] to [http://www.maths.qmul.ac.uk/~pjc/lac/ The London Algebra Colloquium] entitled "SQ-universal groups" on 23 May 1968.
| |
| | |
| ==Examples of SQ-universal groups==
| |
| In 1949 [[Graham Higman]], [[Bernhard Neumann]] and [[Hanna Neumann]] proved that every countable group can be embedded in a two-generator group.<ref>G. Higman, B.H. Neumann and H. Neumann, 'Embedding theorems for groups', J. London Math. Soc. 24 (1949), 247-254</ref> Using the contemporary language of SQ-universality, this result says that ''F''<sub>2</sub>, the [[free group]] (non-[[abelian group|abelian]]) on two [[generating set of a group|generators]], is SQ-universal. This is the first known example of an SQ-universal group. Many more examples are now known:
| |
| | |
| *Adding two [[generator (mathematics)|generator]]s and one arbitrary [[relator]] to a [[nontrivial]] [[torsion (algebra)|torsion-free]] group, always results in an SQ-universal group.<ref>Anton A. Klyachko, 'The SQ-universality of one-relator relative presentation', Arxiv preprint math.GR/0603468, 2006</ref>
| |
| *Any non-elementary group that is [[Hyperbolic group|hyperbolic]] with respect to a collection of proper subgroups is SQ-universal.<ref>G. Arzhantseva, A. Minasyan, D. Osin, 'The SQ-universality and residual properties of relatively hyperbolic groups', J. of Algebra 315 (2007), No. 1, pp. 165-177</ref>
| |
| *Many [[HNN extension]]s, [[free product]]s and [[free products with amalgamation]].<ref>Benjamin Fine, Marvin Tretkoff, 'On the SQ-Universality of HNN Groups', Proceedings of the American Mathematical Society, Vol. 73, No. 3 (Mar., 1979), pp. 283-290</ref><ref>P.M. Neumann: The SQ-universality of some finitely presented groups. J. Austral. Math. Soc. 16, 1-6 (1973)</ref><ref>K. I. Lossov, 'SQ-universality of free products with amalgamated finite subgroups', Siberian Mathematical Journal Volume 27, Number 6 / November, 1986</ref>
| |
| *The four-generator [[Coxeter group]] with [[presentation of a group|presentation]]:<ref>Muhammad A. Albar, 'On a four-generator Coxeter Group', Internat. J. Math & Math. Sci Vol 24, No 12 (2000), 821-823</ref>
| |
| :<math>P=\left\langle a,b,c,d\,|\, a^{2}=b^{2}=c^{2}=d^{2}=(ab)^{3}=(bc)^{3}=(ac)^{3}=(ad)^{3}=(cd)^{3}=(bd)^{3}=1\right\rangle</math>
| |
| *Charles F. Miller III's example of a finitely presented SQ-universal group all of whose non-trivial quotients have [[undecidable problem|unsolvable]] [[word problem for groups|word problem]].<ref>C. F. Miller. Decision problems for groups -- survey and reflections. In Algorithms and Classification in Combinatorial Group Theory, pages 1--60. Springer, 1991.</ref>
| |
| | |
| In addition much stronger versions of the Higmann-Neumann-Neumann theorem are now known. Ould Houcine has proved:
| |
| | |
| : For every countable group ''G'' there exists a 2-generator SQ-universal group ''H'' such that ''G'' can be embedded in every non-trivial quotient of ''H''.<ref>A.O. Houcine, 'Satisfaction of existential theories in finitely presented groups and some embedding theorems', Annals of Pure and Applied Logic, Volume 142, Issues 1-3 , October 2006, Pages 351-365</ref>
| |
| | |
| ==Some elementary properties of SQ-universal groups==
| |
| A free group on [[countable|countably]] many generators ''h''<sub>1</sub>, ''h''<sub>2</sub>, ..., ''h<sub>n</sub>'', ... , say, must be embeddable in a quotient of an SQ-universal group ''G''. If <math>h^*_1,h^*_2, \dots ,h^*_n \dots \in G</math> are chosen such that <math>h^*_n \mapsto h_n</math> for all ''n'', then they must freely generate a free subgroup of ''G''. Hence:
| |
| | |
| :Every SQ-universal group has as a subgroup, a free group on countably many generators.
| |
| | |
| Since every countable group can be embedded in a countable [[simple group]], it is often sufficient to consider embeddings of simple groups. This observation allows us to easily prove some elementary results about SQ-universal groups, for instance:
| |
| | |
| :If ''G'' is an SQ-universal group and ''N'' is a [[normal subgroup]] of ''G'' (i.e. <math>N\triangleleft G</math>) then either ''N'' is SQ-universal or the [[quotient group]] ''G''/''N'' is SQ-universal.
| |
| | |
| To prove this suppose ''N'' is not SQ-universal, then there is a countable group ''K'' that cannot be embedded into a quotient group of ''N''. Let ''H'' be any countable group, then the [[direct product of groups|direct product]] ''H'' × ''K'' is also countable and hence can be embedded in a countable simple group ''S''. Now, by hypotheseis, ''G'' is SQ-universal so ''S'' can be embedded in a quotient group, ''G''/''M'', say, of ''G''. The second [[isomorphism theorem]] tells us:
| |
| | |
| :<math>MN/M \cong N/(M \cap N)</math>
| |
| | |
| Now <math>MN/M\triangleleft G/M</math> and ''S'' is a simple subgroup of ''G''/''M'' so either:
| |
| | |
| :<math>MN/M \cap S \cong 1</math>
| |
| | |
| or:
| |
| | |
| :<math>S\subseteq MN/M \cong N/(M \cap N)</math>.
| |
| | |
| The latter cannot be true because it implies ''K'' ⊆ ''H'' × ''K'' ⊆ ''S'' ⊆ ''N''/(''M'' ∩ ''N'') contrary to our choice of ''K''. It follows that ''S'' can be embedded in (''G''/''M'')/(''MN''/''M''), which by the third [[isomorphism theorem]] is isomorphic to ''G''/''MN'', which is in turn isomorphic to (''G''/''N'')/(''MN''/''N''). Thus ''S'' has been embedded into a quotient group of ''G''/''N'', and since ''H'' ⊆ ''S'' was an arbitrary countable group, it follows that ''G''/''N'' is SQ-universal.
| |
| | |
| Since every [[subgroup]] ''H'' of [[finite index]] in a group ''G'' contains a normal subgroup ''N'' also of finite index in ''G'',<ref>Lawson, Mark V. (1998) ''Inverse semigroups: the theory of partial symmetries'', World Scientific. ISBN 981-02-3316-7, {{Google books quote|id=2805q4tFiCkC|page=52|text=every subgroup of finite index contains a normal subgroup of finite index|p. 52}}</ref> it easily follows that:
| |
| | |
| :If a group ''G'' is SQ-universal then so is any finite index subgroup ''H'' of ''G''. The converse of this statement is also true.<ref>P.M. Neumann: The SQ-universality of some finitely presented groups. J. Austral. Math. Soc. 16, 1-6 (1973)</ref>
| |
| | |
| ==Variants and generalizations of SQ-universality==
| |
| Several variants of SQ-universality occur in the literature. The reader should be warned that terminology in this area is not yet completely stable and should read this section with this caveat in mind.
| |
| | |
| Let <math>\mathcal{P}</math> be a class of groups. (For the purposes of this section, groups are defined ''up to [[isomorphism]]'') A group ''G'' is called '''SQ-universal in the class <math>\mathcal{P}</math>''' if <math>G\in \mathcal{P}</math> and every countable group in <math>\mathcal{P}</math> is isomorphic to a subgroup of a quotient of ''G''. The following result can be proved:
| |
| | |
| : Let ''n'', ''m'' ∈ '''Z''' where ''m'' is odd, <math>n>10^{78}</math> and ''m'' > 1, and let ''B''(''m'', ''n'') be the free m-generator [[Burnside group]], then every non-[[cyclic group|cyclic]] subgroup of ''B''(''m'', ''n'') is SQ-universal in the class of groups of exponent ''n''.
| |
| | |
| Let <math>\mathcal{P}</math> be a class of groups. A group ''G'' is called '''SQ-universal for the class <math>\mathcal{P}</math>''' if every group in <math>\mathcal{P}</math> is isomorphic to a subgroup of a quotient of ''G''. Note that there is no requirement that <math>G\in \mathcal{P}</math> nor that any groups be countable.
| |
| | |
| The standard definition of SQ-universality is equivalent to SQ-universality both ''in'' and ''for'' the class of countable groups.
| |
| | |
| Given a countable group ''G'', call an SQ-universal group ''H'' '''''G''-stable''', if every non-trivial factor group of ''H'' contains a copy of ''G''. Let <math>\mathcal{G}</math> be the class of finitely presented SQ-universal groups that are ''G''-stable for some ''G'' then Houcine's version of the HNN theorem that can be re-stated as:
| |
| | |
| : The free group on two generators is SQ-universal ''for'' <math>\mathcal{G}</math>.
| |
| | |
| However there are uncountably many finitely generated groups, and a countable group can only have countably many finitely generated subgroups. It is easy to see from this that:
| |
| | |
| : No group can be SQ-universal ''in'' <math>\mathcal{G}</math>.
| |
| | |
| An [[Infinity|infinite]] class <math>\mathcal{P}</math> of groups is '''wrappable''' if given any groups <math>F,G\in \mathcal{P}</math> there exists a simple group ''S'' and a group <math>H\in \mathcal{P}</math> such that ''F'' and ''G'' can be embedded in ''S'' and ''S'' can be embedded in ''H''. The it is easy to prove:
| |
| | |
| :If <math>\mathcal{P}</math> is a wrappable class of groups, ''G'' is an SQ-universal for <math>\mathcal{P}</math> and <math>N\triangleleft G</math> then either ''N'' is SQ-universal for <math>\mathcal{P}</math> or ''G''/''N'' is SQ-universal for <math>\mathcal{P}</math>.
| |
| | |
| :If <math>\mathcal{P}</math> is a wrappable class of groups and ''H'' is of finite index in ''G'' then ''G'' is SQ-universal for the class <math>\mathcal{P}</math> if and only if ''H'' is SQ-universal for <math>\mathcal{P}</math>.
| |
| | |
| The motivation for the definition of wrappable class comes from results such as the [[Boone-Higman theorem]], which states that a countable group ''G'' has soluble word problem if and only if it can be embedded in a simple group ''S'' that can be embedded in a finitely presented group ''F''. Houcine has shown that the group ''F'' can be constructed so that it too has soluble word problem. This together with the fact that taking the direct product of two groups preserves solubility of the word problem shows that:
| |
| | |
| :The class of all [[finitely-presented group|finitely presented]] groups with soluble [[word problem (mathematics)|word problem]] is wrappable.
| |
| | |
| Other examples of wrappable classes of groups are:
| |
| | |
| *The class of [[finite group]]s.
| |
| *The class of torsion free groups.
| |
| *The class of countable torsion free groups.
| |
| *The class of all groups of a given infinite [[cardinality]].
| |
| | |
| The fact that a class <math>\mathcal{P}</math> is wrappable does not imply that any groups are SQ-universal for <math>\mathcal{P}</math>. It is clear, for instance, that some sort of cardinality restriction for the members of <math>\mathcal{P}</math> is required.
| |
| | |
| If we replace the phrase "isomorphic to a subgroup of a quotient of" with "isomorphic to a subgroup of" in the definition of "SQ-universal", we obtain the stronger concept of '''S-universal''' (respectively '''S-universal for/in <math>\mathcal{P}</math>'''). The Higman Embedding Theorem can be used to prove that there is a finitely presented group that contains a copy of every finitely presented group. If <math>\mathcal{W}</math> is the class of all finitely presented groups with soluble word problem, then it is known that there is no uniform [[algorithm]] to solve the word problem for groups in <math>\mathcal{W}</math>. It follows, although the proof is not a straightforward as one might expect, that no group in <math>\mathcal{W}</math> can contain a copy of every group in <math>\mathcal{W}</math>. But it is clear that any SQ-universal group is ''a fortiori'' SQ-universal for <math>\mathcal{W}</math>. If we let <math>\mathcal{F}</math> be the class of finitely presented groups, and ''F''<sub>2</sub> be the free group on two generators, we can sum this up as:
| |
| | |
| *''F''<sub>2</sub> is SQ-universal in <math>\mathcal{F}</math> and <math>\mathcal{W}</math>.
| |
| *There exists a group that is S-universal in <math>\mathcal{F}</math>.
| |
| *No group is S-universal in <math>\mathcal{W}</math>.
| |
| | |
| The following questions are open (the second implies the first):
| |
| | |
| *Is there a countable group that is not SQ-universal but is SQ-universal ''for'' <math>\mathcal{W}</math>?
| |
| *Is there a countable group that is not SQ-universal but is SQ-universal ''in'' <math>\mathcal{W}</math>?
| |
| | |
| While it is quite difficult to prove that ''F''<sub>2</sub> is SQ-universal, the fact that it is SQ-universal ''for the class of finite groups'' follows easily from these two facts:
| |
| | |
| * Every [[symmetric group]] on a finite set can be generated by two elements
| |
| * Every finite group can be embedded inside a symmetric group—the natural one being the [[Cayley group]], which is the symmetric group acting on this group as the finite set.
| |
| | |
| ==SQ-universality in other categories==
| |
| If <math>\mathcal{C}</math> is a category and <math>\mathcal{P}</math> is a class of [[Object (category theory)|object]]s of <math>\mathcal{C}</math>, then the definition of ''SQ-universal for <math>\mathcal{P}</math>'' clearly makes sense. If <math>\mathcal{C}</math> is a [[concrete category]], then the definition of ''SQ-universal in <math>\mathcal{P}</math>'' also makes sense. As in the group theoretic case, we use the term SQ-universal for an object that is SQ-universal both ''for'' and ''in'' the class of countable objects of <math>\mathcal{C}</math>.
| |
| | |
| Many embedding theorems can be restated in terms of SQ-universality. Shirshov's Theorem that a [[Lie algebra]] of finite or countable dimension can be embedded into a 2-generator Lie algebra is equivalent to the statement that the 2-generator free Lie algebra is SQ-universal (in the category of Lie algebras). This can be proved by proving a version of the Higman, Neumann, Neumann theorem for Lie algebras.<ref>A.I. Lichtman and M. Shirvani, 'HNN-extensions of Lie algebras', Proc. American Math. Soc. Vol 125, Number 12, December 1997, 3501-3508</ref> However versions of the HNN theorem can be proved for categories where there is no clear idea of a free object. For instance it can be proved that every [[separable space|separable]] [[topological group]] is isomorphic to a topological subgroup of a group having two topological generators (that is, having a [[dense set|dense]] 2-generator subgroup).<ref>Sidney A. Morris and Vladimir Pestov, 'A topological generalization of the Higman-Neumann-Neumann Theorem', Research Report RP-97-222 (May 1997), School of Mathematical and Computing Sciences, Victoria University of Wellington. See also J. Group Theory '''1''', No.2, 181-187 (1998).</ref>
| |
| | |
| A similar concept holds for [[free lattice]]s. The free lattice in three generators is countably infinite. It has, as a sublattice, the free lattice in four generators, and, by induction, as a sublattice, the free lattice in a countable number of generators.<ref>L.A. Skornjakov, ''Elements of Lattice Theory'' (1977) Adam Hilger Ltd. ''(see pp.77-78)''</ref>
| |
| | |
| ==References==
| |
| <references/>
| |
| * {{cite book |last1=Lawson |first1=M.V. |authorlink1= |last2= |first2= |authorlink2= |title=Inverse semigroups: the theory of partial symmetries |url= |edition= |series= |volume= |year=1998 |publisher=World Scientific |location= |isbn=978-981-02-3316-7 |id= }}
| |
| | |
| {{Use dmy dates|date=September 2010}}
| |
| | |
| {{DEFAULTSORT:Sq Universal Group}}
| |
| [[Category:Properties of groups]]
| |
| [[Category:Combinatorial group theory]]
| |