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| #REDIRECT [[Deformation (mechanics)#Normal strain]]
| | The title of the author is Numbers but it's not the most masucline name out there. Managing individuals is what I do and the wage has been truly satisfying. California is our birth location. To do aerobics is a thing that I'm completely addicted to.<br><br>Here is my web page ... [http://www.Pponline.co.uk/user/miriamlinswkucrd www.Pponline.co.uk] |
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| {{Unreferenced|date=December 2009}}
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| {{Mergeto|Deformation (mechanics)|discuss=Talk:Deformation (mechanics)#Merging articles|date=September 2008}}
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| As with [[stress (mechanics)|stress]]es, strains may also be classified as 'normal strain' and '[[shear strain]]' (i.e. acting perpendicular to or along the face of an element respectively). For an [[isotropic]] material that obeys [[Hooke's law]], a [[normal stress]] will cause a normal strain. [[Deformation (mechanics)|Strains]] are relative [[displacement field (mechanics)|displacements]] - they are the actual displacement divided by the length before the strain was applied. [[Rigid body motion]]s don't produce strains. '''Normal strains''' produce ''dilations'', however they merely [[Deformation (mechanics)#Stretch|stretch]] the body along the axis of application (negating [[poisson's ratio]] and the effects it causes). As such, a normal strain will cause the following effects:
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| * Any line [[Parallel (geometry)|parallel]] to the strain axis will increase by an amount proportional to its length and the amount of strain. (See below).
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| * Any line [[perpendicular]] to the strain axis will have no length change (negating [[Poisson's effect]].)
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| * Any line not perpendicular nor parallel will have a length increase based upon [[vector algebra]].
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| * Normal Strains will become Shear strains for a rotation of the [[frame of reference]]. See [[Mohr's circle]] for strain.
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| Normal strain,
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| :<math>\epsilon = \frac{\text{extension}}{\text{original length}}</math>
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| The 'stretch' of an element over its original element length is thus:
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| :<math>\epsilon = \frac{\Delta u}{\Delta x} = \frac{du}{dx} = u'(x)</math>
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| ==See also==
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| * [[Shear strain]]
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| {{DEFAULTSORT:Normal Strain}}
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| [[Category:Continuum mechanics]]
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Latest revision as of 11:27, 6 June 2014
The title of the author is Numbers but it's not the most masucline name out there. Managing individuals is what I do and the wage has been truly satisfying. California is our birth location. To do aerobics is a thing that I'm completely addicted to.
Here is my web page ... www.Pponline.co.uk