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{{Infobox stable isotope
|isotope_name = Hydrogen-2
|isotope_filename = hydrogen-2.svg
|alternate_names = deuterium
|mass_number = 2
|symbol = H or D
|num_neutrons = 1
|num_protons = 1
|abundance = 0.0156% (Earth)
|mass = 2.01410178
|spin = 1<sup>+</sup>
|excess_energy = 13135.720
|error1 = 0.001
|binding_energy = 2224.52
|error2 = 0.20
}}
 
'''Deuterium''' (symbol '''{{Element|deuterium}}''' or '''{{SimpleNuclide|hydrogen|2}}''', also known as '''heavy hydrogen''') is one of two [[stable isotopes]] of [[hydrogen]]. It has a [[natural abundance]] in Earth's [[oceans]] of about one [[atom]] in {{val|fmt=commas|6420}} of hydrogen. Thus deuterium accounts for approximately 0.0156% (or on a mass basis: 0.0312%) of all the naturally occurring hydrogen in the oceans, while the most common isotope ([[Hydrogen|hydrogen-1]] or protium) accounts for more than 99.98%. The abundance of deuterium changes slightly from one kind of natural water to another (see [[Vienna Standard Mean Ocean Water|VSMOW]]).
 
The [[atomic nucleus|nucleus]] of deuterium, called a '''deuteron''', contains one [[proton]] and one [[neutron]], whereas the far more common hydrogen isotope, [[Hydrogen atom#Isotopes|protium]], has no neutron in the nucleus. The deuterium isotope's name is formed from the Greek ''deuteros'' meaning "second", to denote the two particles composing the nucleus.<ref name="diplogen" /> Deuterium was discovered and named in 1931 by [[Harold Urey]], earning him a Nobel Prize in 1934. This followed the discovery of the neutron in 1932, which made the nuclear structure of deuterium obvious. Soon after deuterium's discovery, Urey and others produced samples of "[[heavy water]]" in which the deuterium has been highly concentrated with respect to the protium.
 
Because deuterium is destroyed in the interiors of stars faster than it is produced, and because other natural processes are thought to produce only an insignificant amount of deuterium, it is presently thought that nearly all deuterium found in nature was produced in the [[Big Bang]] 13.8 billion years ago, and that the basic or primordial ratio of hydrogen-1 (protium) to deuterium (about 26 atoms of deuterium per million hydrogen atoms) has its origin from that time. This is the ratio found in the gas giant planets, such as Jupiter. However, different astronomical bodies are found to have different ratios of deuterium to hydrogen-1, and this is thought to be as a result of natural isotope separation processes that occur from solar heating of ices in comets. Like the water-cycle in Earth's weather, such heating processes may enrich deuterium with respect to protium. In fact, the discovery of deuterium/protium ratios in a number of comets very similar to the mean ratio in Earth's oceans (156 atoms of deuterium per million hydrogens) has led to theories that much of Earth's ocean water has a cometary origin.<ref name="nature2">{{cite journal|doi=10.1038/nature10519|journal=Nature|volume= 478|pages=218–220|year=2011|title=Ocean-like water in the Jupiter-family comet 103P/Hartley 2|last1=Hartogh|first1=Paul|last2=Lis|first2=Dariusz C.|last3=Bockelée-Morvan|first3=Dominique|last4=De Val-Borro|first4=Miguel|last5=Biver|first5=Nicolas|last6=Küppers|first6=Michael|last7=Emprechtinger|first7=Martin|last8=Bergin|first8=Edwin A.|last9=Crovisier|first9=Jacques|issue=7368|pmid=21976024|bibcode = 2011Natur.478..218H }}</ref><ref name="Hersant"/> <!--News reports of Hubble measurements of "6 atoms of D per 10,000" in Jupiter are wrong; the correct figure is 6 parts D per 100,000 by weight, which is 30 parts per million atom-fraction, close to the Galileo result of 26 parts per million, atom-fraction-->
 
Deuterium/protium ratios thus continue to be an active topic of research in both astronomy and climatology.
 
==Differences between deuterium and common hydrogen (protium)==
 
===Chemical symbol===
[[File:Deuterium discharge tube.jpg|thumb|right|Deuterium discharge tube]]
 
Deuterium is frequently represented by the [[chemical symbol]] D. Since it is an isotope of [[hydrogen]] with [[mass number]] 2, it is also represented by {{SimpleNuclide|Hydrogen|2}}. [[IUPAC]] allows both D and {{SimpleNuclide|Hydrogen|2}}, although {{SimpleNuclide|Hydrogen|2}} is preferred.<ref>
{{cite web
|url=http://www.iupac.org/reports/provisional/abstract04/connelly_310804.html
|title=&sect; IR-3.3.2 Provisional Recommendations
|work=Nomenclature of Inorganic Chemistry
|publisher=Chemical Nomenclature and Structure Representation Division, [[IUPAC]]
|accessdate=2007-10-03
}}</ref> A distinct chemical symbol is used for convenience because of the isotope's common use in various scientific processes. Also, its large mass difference with [[hydrogen-1|protium]] ({{SimpleNuclide|Hydrogen|1}}) (deuterium has a mass of {{val|fmt=commas|2.014102|ul=u}}, compared to the [[mean]] hydrogen [[atomic weight]] of {{val|fmt=commas|1.007947|u=u}}, and protium's mass of {{val|fmt=commas|1.007825|u=u}}) confers non-negligible chemical dissimilarities with protium-containing compounds, whereas the isotope weight ratios within other chemical elements are largely insignificant in this regard.
 
=== Spectroscopy ===
In [[quantum mechanics]] the energy levels of electrons in atoms depend on the [[reduced mass]] of the system of electron and nucleus. For the [[hydrogen atom]], the role of reduced mass is most simply seen in the [[Bohr model]] of the atom, where the reduced mass appears in a simple  calculation of the [[Rydberg constant]] and Rydberg equation, but the reduced mass also appears in the [[Schrödinger equation]], and the [[Dirac equation]] for calculating atomic energy levels.
 
The reduced mass of the system in these equations is close to the mass of a single electron, but differs from it by a small amount about equal to the ratio of mass of the electron to the atomic nucleus. For hydrogen, this amount is about 1837/1836, or 1.000545, and for deuterium it is even smaller: 3671/3670, or 1.0002725. The energies of spectroscopic lines for deuterium and light-hydrogen (hydrogen-1) therefore differ by the ratios of these two numbers, which is 1.000272. The wavelengths of all deuterium spectroscopic lines are shorter than the corresponding lines of light hydrogen, by a factor of 1.000272. In astronomical observation, this corresponds to a blue Doppler shift of 0.000272 times the speed of light, or 81.6&nbsp;km/s.<ref>{{citation |url=http://arxiv.org/pdf/astro-ph/0002141.pdf |title=Detection of deuterium Balmer lines in the Orion Nebula |last1=Hébrard |first1=G. |last2=Péquignot |first2=D. |last3=Vidal-Madjar |first3=A. |last4=Walsh |first4=J. R. |last5=Ferlet |first5=R. |date=7 Feb 2000}}</ref>
 
=== Deuterium and Big Bang nucleosynthesis ===
{{Main|Big Bang nucleosynthesis}}
Deuterium is thought to have played an important role in setting the number and ratios of the elements that were formed in the Big Bang. Combining thermodynamics and the changes brought about by cosmic expansion, one can calculate the fraction of protons and neutrons based on the temperature at the point that the universe cooled enough to allow formation of nuclei. This calculation indicates seven protons for every neutron at the beginning of nucleogenesis, a ratio that would remain stable even after nucleogenesis was over. This fraction was in favor of protons initially, primarily because the lower mass of the proton favored their production. As the universe expanded, it cooled. [[Free neutron]]s and protons are less stable than helium nuclei, and the protons and neutrons had a strong energetic reason to form helium-4. However, forming helium-4 requires the intermediate step of forming deuterium.
 
Through much of the few minutes after the big bang during which nucleosynthesis could have occurred, the temperature was high enough that the mean energy per particle was greater than the binding energy of weakly bound deuterium; therefore any deuterium that was formed was immediately destroyed. This situation is known as the '''deuterium bottleneck'''. The bottleneck delayed formation of any helium-4 until the universe became cool enough to form deuterium (at about a temperature equivalent to 0.1 MeV or 100 keV). At this point, there was a sudden burst of element formation (first deuterium, which immediately fused to helium). However, very shortly thereafter, at twenty minutes after the Big Bang, the universe became too cool for any further nuclear fusion and nucleosynthesis to occur. At this point, the elemental abundances were nearly fixed, with the only change as some of the [[radioactive]] products of BBN (such as [[tritium]]) decay.<ref>{{cite web | last = Weiss | first = Achim | title = Equilibrium and change: The physics behind Big Bang Nucleosynthesis | url = http://www.einstein-online.info/en/spotlights/BBN_phys/index.html | work = [http://www.einstein-online.info Einstein Online] | accessdate = 2007-02-24}}</ref> The deuterium bottleneck in the formation of helium, together with the lack of stable ways for helium to combine with hydrogen or with itself (there are no stable nuclei with mass numbers of five or eight) meant that insignificant carbon, or any elements heavier than carbon, formed in the Big Bang. These elements thus required formation in stars. At the same time, the failure of much nucleogenesis during the Big Bang ensured that there would be plenty of hydrogen in the later universe available to form long-lived stars, such as our Sun.
 
=== Abundance ===
Deuterium occurs in trace amounts naturally as deuterium [[gas]], written {{SimpleNuclide|Hydrogen|2}}<sub>2</sub> or D<sub>2</sub>, but most natural occurrence in the [[universe]] is bonded with a typical {{SimpleNuclide|Hydrogen|1}} atom, a gas called [[hydrogen deuteride]] (HD or {{SimpleNuclide|Hydrogen|1}}{{SimpleNuclide|Hydrogen|2}}).<ref>{{Cite journal|author=IUPAC Commission on Nomenclature of Inorganic Chemistry|title=Names for Muonium and Hydrogen Atoms and their Ions|journal=[[Pure and Applied Chemistry]]|year=2001|volume=73|pages=377–380|url=http://www.iupac.org/publications/pac/2001/pdf/7302x0377.pdf |format=PDF|doi=10.1351/pac200173020377|issue=2}}</ref>
 
The existence of deuterium on Earth, elsewhere in the [[solar system]] (as confirmed by planetary probes), and in the spectra of [[star]]s, is also an important datum in [[physical cosmology|cosmology]]. Gamma radiation from ordinary nuclear fusion dissociates deuterium into protons and neutrons, and there are no known natural processes other than the [[Big Bang nucleosynthesis]], which might have produced deuterium at anything close to the observed natural abundance of deuterium (deuterium is produced by the rare [[cluster decay]], and occasional absorption of naturally occurring neutrons by light hydrogen, but these are trivial sources). There is thought to be little deuterium in the interior of the Sun and other stars, as at temperatures there [[nuclear fusion reaction]]s that consume deuterium happen much faster than the [[proton-proton reaction]] that creates deuterium. However, deuterium persists in the outer solar atmosphere at roughly the same concentration as in Jupiter, and this has probably been unchanged since the origin of the Solar System. The natural abundance of deuterium seems to be a very similar fraction of hydrogen, wherever hydrogen is found, unless there are obvious processes at work that concentrate it.
 
The existence of deuterium at a low but constant primordial fraction in all hydrogen is another one of the arguments in favor of the [[Big Bang]] theory over the [[Steady State theory]] of the universe. The presently observed ratios of hydrogen to helium to deuterium in the universe are difficult to explain except with a Big Bang model. It is estimated that the abundances of deuterium have not evolved significantly since their production about {{val|13.8|ul=bya}}.<ref>{{cite web
|last =
|first = 
|title = Cosmic Detectives
|url=http://www.esa.int/Our_Activities/Space_Science/Cosmic_detectives
|authorlink =
|coauthors =
|work =
|publisher = The European Space Agency (ESA)
|date = 2 April 2013
|doi =
|accessdate = 2013-04-15}}
</ref> Measurements of Milky Way galactic deuterium from ultraviolet spectral analysis show a ratio of as much as 23 atoms of deuterium per million hydrogen atoms in undisturbed gas clouds, which is only 15% below the [[WMAP]] estimated primordial ratio of about 27 atoms per million from the Big Bang. This has been interpreted to mean that less deuterium has been destroyed in star formation in our galaxy than expected, or perhaps deuterium has been replenished by a large in-fall of primordial hydrogen from outside the galaxy.<ref>[http://www.nasa.gov/vision/universe/starsgalaxies/fuse_stars.html NASA page on FUSE satellite]</ref> In space a few hundred light years from the Sun, deuterium abundance is only 15 atoms per million, but this value is presumably influenced by differential adsorption of deuterium onto carbon dust grains in interstellar space.<ref>[http://fuse.pha.jhu.edu/wpb/sci_d2h_solved.html graph of deuterium with distance in our galactic neighborhood] See also "What is the Total Deuterium Abundance in the Local Galactic Disk?" Linsky, J. L., Draine, B. T., Moos, H. W., Jenkins, E. B., Wood, B. E., Oliviera, C., Blair, W. P., Friedman, S. D., Knauth, D., Lehner, N., Redfield, S., Shull, J. M., Sonneborn, G., Williger, G. M., 2006, The Astrophysical Journal, Vol. 647, page 1106.</ref>
 
The abundance of deuterium in the atmosphere of [[Jupiter]] has been directly measured (by the [[Galileo space probe]] as 26 atoms per million hydrogen atoms. ISO-SWS observations find 22 atoms per million hydrogen atoms in Jupiter.<ref>
{{Cite journal
|author=Lellouch, E
|year=2001
|title = The deuterium abundance in Jupiter and Saturn from ISO-SWS observations
|journal=[[Astronomy & Astrophysics]]
|volume=670|pages=610–622
|doi=10.1051/0004-6361:20010259
|last2=Bézard
|first2=B.
|last3=Fouchet
|first3=T.
|last4=Feuchtgruber
|first4=H.
|last5=Encrenaz
|first5=T.
|last6=De Graauw
|first6=T.
|bibcode=2001A&A...370..610L
|issue=2
}}</ref> and this abundance is thought to represent close to the primordial solar system ratio.<ref name="Hersant">{{cite journal|url=http://iopscience.iop.org/0004-637X/554/1/391/pdf/0004-637X_554_1_391.pdf|quote= see fig. 7. for a review of D/H ratios in various astronomical objects |doi=10.1086/321355|title=A Two‐dimensional Model for the Primordial Nebula Constrained by D/H Measurements in the Solar System: Implications for the Formation of Giant Planets|year=2001|last1=Hersant|first1=Franck|last2=Gautier|first2=Daniel|last3=Hure|first3=Jean‐Marc|journal=The Astrophysical Journal|volume=554|page=391|bibcode = 2001ApJ...554..391H }}</ref> This is about 17% of the terrestrial deuterium-to-hydrogen ratio of 156 deuterium atoms per million hydrogen atoms.
 
Cometary bodies such as Comet [[Hale Bopp]] and [[Halley's Comet]] have been measured to contain relatively more deuterium (about 200 atoms D per million hydrogens), ratios which are enriched with respect to the presumed protosolar nebula ratio, probably due to heating, and which are similar to the ratios found in Earth seawater. The recent measurement of deuterium amounts of 161 atoms D per million hydrogen in Comet [[103P/Hartley]] (a former [[Kuiper belt]] object), a ratio almost exactly that in Earth's oceans, emphasizes the theory that Earth's surface water may be largely comet-derived.<ref name="nature2"/><ref name="Hersant"/> <!--News reports of Hubble measurements of "6 atoms of D per 10,000" in Jupiter are wrong; the correct figure is 6 parts D per 100,000 by weight, which is 30 parts per million atom-fraction, close to the Galileo result of 26 parts per million, atom-fraction-->
 
Deuterium has also observed to be concentrated over the mean solar abundance in other terrestrial planets, in particular Mars and Venus.
 
===Concentrating natural abundance deuterium===
Deuterium is concentrated for industrial, scientific and military purposes as [[heavy water]] from ordinary water. The world's leading supplier of deuterium was [[Atomic Energy of Canada Limited]], in [[Canada]], until 1997, when the last heavy water plant was shut down. Canada uses heavy water as a [[neutron moderator]] for the operation of the [[CANDU reactor]] design.
 
==Properties==
 
===Physical properties===
 
The physical properties of deuterium compounds can exhibit significant [[kinetic isotope effect]]s and other physical and chemical property differences from the hydrogen analogs; for example, [[D2O|D<sub>2</sub>O]] is more [[Viscosity|viscous]] than [[H2O|H<sub>2</sub>O]].<ref>{{RubberBible86th}}</ref>
Chemically, deuterium behaves similarly to ordinary hydrogen, but there are differences in bond energy and length for compounds of heavy hydrogen isotopes which are larger than the isotopic differences in any other element. Bonds involving deuterium and [[tritium]] are somewhat stronger than the corresponding bonds in hydrogen, and these differences are enough to make significant changes in biological reactions.
 
Deuterium can replace the normal hydrogen in water molecules to form heavy water (D<sub>2</sub>O), which is about 10.6% denser than normal water (enough that ice made from it sinks in ordinary water). Heavy water is slightly toxic in [[eukaryotic]] animals, with 25% substitution of the body water causing cell division problems and sterility, and 50% substitution causing death by cytotoxic syndrome (bone marrow failure and gastrointestinal lining failure). [[Prokaryotic]] organisms, however, can survive and grow in pure heavy water (though they grow more slowly).<ref>{{Cite journal|pmid=10535697 |title=Pharmacological uses and perspectives of heavy water and deuterated compounds |author=D. J. Kushner, Alison Baker, and T. G. Dunstall |journal=Can. J. Physiol. Pharmacol. |volume=77 |issue=2 |pages=79–88 |year=1999 |doi=10.1139/cjpp-77-2-79}}</ref> Consumption of heavy water does not pose a [[heavy water#Toxicity|health threat]] to humans, it is estimated that a {{val|70|ul=kg}} person might drink 4.8 liters of heavy water without serious consequences.<ref>{{Cite book|url = http://books.google.com/?id=nQh7iGX1geIC&pg=PA111|isbn = 978-1-4020-1314-0|pages = 111–112| chapter = Physiological effect of heavy water|editor=Attila Vertes |year = 2003|publisher = Kluwer|location = Dordrecht|title = Elements and isotopes: formation, transformation, distribution}}</ref> Small doses of heavy water (a few grams in humans, containing an amount of deuterium comparable to that normally present in the body) are routinely used as harmless metabolic tracers in humans and animals.
 
===Quantum properties===
The deuteron has [[quantum spin|spin]] +1 ("triplet") and is thus a [[boson]]. The [[nuclear magnetic resonance|NMR]] frequency of deuterium is significantly different from common light hydrogen. [[Infrared spectroscopy]] also easily differentiates many deuterated compounds, due to the large difference in IR absorption frequency seen in the vibration of a chemical bond containing deuterium, versus light hydrogen. The two stable isotopes of hydrogen can also be distinguished by using [[mass spectrometry]].
 
The triplet deuteron nucleon is barely bound at E<sub>B</sub> = {{val|2.23|u=MeV}}, so all the higher energy states are not bound. The singlet deuteron is a virtual state, with a negative binding energy of {{val|p=~|60|u=keV}}. There is no such stable particle, but this virtual particle transiently exists during neutron-proton inelastic scattering, accounting for the unusually large neutron scattering cross-section of the proton.<ref>[http://mightylib.mit.edu/Course%20Materials/22.101/Fall%202004/Notes/Part3.pdf Neutron-Proton Scattering]. (PDF). mit.edu. Retrieved on 2011-11-23.</ref>
 
===Nuclear properties (the deuteron)===
 
====Deuteron mass and radius====
The nucleus of deuterium is called a '''deuteron'''. It has a mass of {{val|fmt=commas|2.013553212724|(78)|u=u}}<ref>[http://physics.nist.gov/cgi-bin/cuu/Value?mdu 2002 CODATA recommended value]. Physics.nist.gov. Retrieved on 2011-11-23.</ref>
The [[charge radius]] of the deuteron is {{val|fmt=commas|2.1402|(28)|ul=fm}}<ref>2006 CODATA recommended value {{CODATA2006}}</ref>
 
====Spin and energy====
 
Deuterium is one of only four stable [[nuclide]]s with an odd number of protons and odd number of neutrons. ({{SimpleNuclide|Hydrogen|2}}, {{SimpleNuclide|Lithium|6}}, {{SimpleNuclide|Boron|10}}, {{SimpleNuclide|Nitrogen|14}}; also, the long-lived radioactive nuclides {{SimpleNuclide|Potassium|40}}, {{SimpleNuclide|Vanadium|50}}, {{SimpleNuclide|Lanthanum|138}}, {{SimpleNuclide|Tantalum|180m}} occur naturally.) Most odd-odd nuclei are unstable with respect to [[beta decay]], because the decay products are even-even, and are therefore more strongly bound, due to [[Semi-empirical mass formula#Pairing term|nuclear pairing effects]]. Deuterium, however, benefits from having its proton and neutron coupled to a spin-1 state, which gives a stronger nuclear attraction; the corresponding spin-1 state does not exist in the two-neutron or two-proton system, due to the [[Pauli exclusion principle]] which would require one or the other identical particle with the same spin to have some other different quantum number, such as [[angular momentum operator|orbital angular momentum]]. But orbital angular momentum of either particle gives a lower [[binding energy]] for the system, primarily due to increasing distance of the particles in the steep gradient of the nuclear force. In both cases, this causes the [[diproton]] and [[dineutron]] nucleus to be [[unstable]].
 
The proton and neutron making up deuterium can be [[Dissociation (chemistry)|dissociated]] through [[neutral current]] interactions with [[neutrino]]s. The [[Cross section (physics)|cross section]] for this interaction is comparatively large, and deuterium was successfully used as a neutrino target in the [[Sudbury Neutrino Observatory]] experiment.
 
====Isospin singlet state of the deuteron====
Due to the similarity in mass and nuclear properties between the proton and neutron, they are sometimes considered as two symmetric types of the same object, a [[nucleon]]. While only the proton has an electric charge, this is often negligible due to the weakness of the [[electromagnetic interaction]] relative to the [[strong nuclear interaction]]. The symmetry relating the proton and neutron is known as [[isospin]] and denoted ''I'' (or sometimes ''T'').
 
Isospin is an [[SU(2)]] symmetry, like ordinary [[Spin (physics)|spin]], so is completely analogous to it. The proton and neutron form an [[spin doublet|isospin doublet]], with a [[Spin-½|"down" state]] (↓) being a neutron, and an [[Spin-½|"up" state]] (↑) being a proton.
 
A pair of nucleons can either be in an antisymmetric state of isospin called [[Singlet state|singlet]], or in a symmetric state called [[Spin triplet|triplet]]. In terms of the [[Spin-½|"down" state]] and [[Spin-½|"up" state]], the singlet is
:<math>\frac{1}{\sqrt{2}}\Big( |\uparrow \downarrow \rangle - |\downarrow \uparrow \rangle\Big).</math>
 
This is a nucleus with one proton and one neutron, i.e. a deuterium nucleus. The triplet is
:<math>
\left(
\begin{array}{ll}
|\uparrow\uparrow\rangle\\
\frac{1}{\sqrt{2}}( |\uparrow\downarrow\rangle + |\downarrow\uparrow\rangle )\\
|\downarrow\downarrow\rangle
\end{array}
\right)
</math>
and thus consists of three types of nuclei, which are supposed to be symmetric: a deuterium nucleus (actually a highly [[excited state]] of it), a nucleus with two protons, and a nucleus with two neutrons. The latter two nuclei are not stable or nearly stable, and therefore so is this type of deuterium (meaning that it is indeed a highly excited state of deuterium).
 
====Approximated wavefunction of the deuteron====
The deuteron wavefunction must be antisymmetric if the isospin representation is used (since a proton and a neutron are not identical particles, the wavefunction
need not be antisymmetric in general). Apart from their isospin, the two nucleons also have spin and spatial distributions of their wavefunction. The latter is symmetric if the deuteron is symmetric under [[Parity (physics)|parity]] (i.e. have an "even" or "positive" parity), and antisymmetric if the deuteron is antisymmetric under parity (i.e. have an "odd" or "negative" parity). The parity is fully determined by the total orbital angular momentum of the two nucleons: if it is even then the parity is even (positive), and if it is odd then the parity is odd (negative).
 
The deuteron, being an isospin singlet, is antisymmetric under nucleons exchange due to isospin, and therefore must be symmetric under the double exchange of their spin and location. Therefore it can be in either of the following two different states:
*Symmetric spin and symmetric under parity. In this case, the exchange of the two nucleons will multiply the deuterium wavefunction by (−1) from isospin exchange, (+1) from spin exchange and (+1) from parity (location exchange), for a total of (−1) as needed for antisymmetry.
*Antisymmetric spin and antisymmetric under parity. In this case, the exchange of the two nucleons will multiply the deuterium wavefunction by (−1) from isospin exchange, (−1) from spin exchange and (−1) from parity (location exchange), again for a total of (−1) as needed for antisymmetry.
 
In the first case the deuteron is a spin triplet, so that its total spin ''s'' is 1. It also has an even parity and therefore even orbital angular momentum ''l'' ; The lower its orbital angular momentum, the lower its energy. Therefore the lowest possible energy state has {{nowrap|''s'' {{=}} 1}}, {{nowrap|''l'' {{=}} 0}}.
 
In the second case the deuteron is a spin singlet, so that its total spin ''s'' is 0. It also has an odd parity and therefore odd orbital angular momentum ''l''. Therefore the lowest possible energy state has {{nowrap|''s'' {{=}} 0}}, {{nowrap|''l'' {{=}} 1}}.
 
Since {{nowrap|''s'' {{=}} 1}} gives a stronger nuclear attraction, the deuterium [[ground state]] is in the {{nowrap|''s'' {{=}}1}}, {{nowrap|''l'' {{=}} 0}} state.
 
The same considerations lead to the possible states of an isospin triplet having {{nowrap|''s'' {{=}} 0}}, {{nowrap|''l'' {{=}} even}} or {{nowrap|''s'' {{=}} 1}}, {{nowrap|''l'' {{=}} odd}}. Thus the state of lowest energy has {{nowrap|''s'' {{=}} 1}}, {{nowrap|''l'' {{=}} 1}}, higher than that of the isospin singlet.
 
The analysis just given is in fact only approximate, both because isospin is not an exact symmetry, and more importantly because the [[strong nuclear interaction]] between the two nucleons is related to [[angular momentum]] in [[spin-orbit interaction]] that mixes different ''s'' and ''l'' states. That is, ''s'' and ''l'' are not constant in time (they do not [[commutativity|commute]] with the [[Hamiltonian (quantum mechanics)|Hamiltonian]]), and over time a state such as {{nowrap|''s'' {{=}} 1}}, {{nowrap|''l'' {{=}} 0}} may become a state of {{nowrap|''s'' {{=}} 1}}, {{nowrap|''l'' {{=}} 2}}. Parity is still constant in time so these do not mix with odd ''l'' states (such as {{nowrap|''s'' {{=}} 0}}, {{nowrap|''l'' {{=}} 1}}). Therefore the [[quantum state]] of the deuterium is a [[Quantum superposition|superposition]] (a linear combination) of the {{nowrap|''s'' {{=}} 1}}, {{nowrap|''l'' {{=}} 0}} state and the {{nowrap|''s'' {{=}} 1}}, {{nowrap|''l'' {{=}} 2}} state, even though the first component is much bigger. Since the [[total angular momentum]] ''j'' is also a good [[quantum number]] (it is a constant in time), both components must have the same ''j'', and therefore {{nowrap|''j'' {{=}} 1}}. This is the total spin of the deuterium nucleus.
 
To summarize, the deuterium nucleus is antisymmetric in terms of isospin, and has spin 1 and even (+1) parity. The relative angular momentum of its nucleons ''l'' is not well defined, and the deuteron is a superposition of mostly {{nowrap|''l'' {{=}} 0}} with some {{nowrap|''l'' {{=}} 2}}.
 
====Magnetic and electric multipoles====
In order to find theoretically the deuterium [[magnetic dipole moment]] µ, one uses the formula for a [[nuclear magnetic moment]]
:<math>\mu =
{1\over (j+1)}\langle(l,s),j,m_j=j|\overrightarrow{\mu}\cdot \overrightarrow{j}|(l,s),j,m_j=j\rangle</math>
with
:<math>\overrightarrow{\mu} = g^{(l)}\overrightarrow{l} + g^{(s)}\overrightarrow{s} </math>
g<sup>(l)</sup> and g<sup>(s)</sup> are [[g-factor (physics)|g-factor]]s of the nucleons.
 
Since the proton and neutron have different values for g<sup>(l)</sup> and g<sup>(s)</sup>, one must separate their contributions. Each gets half of the deuterium orbital angular momentum <math>\overrightarrow{l}</math> and spin <math>\overrightarrow{s}</math>. One arrives at
 
:<math>\mu =
{1\over (j+1)}\langle(l,s),j,m_j=j|\left({1\over 2}\overrightarrow{l} {g^{(l)}}_p + {1\over 2}\overrightarrow{s} ({g^{(s)}}_p + {g^{(s)}}_n)\right)\cdot \overrightarrow{j}|(l,s),j,m_j=j\rangle</math>
where subscripts p and n stand for the proton and neutron, and {{nowrap|g<sup>(l)</sup><sub>n</sub> {{=}} 0}}.
 
By using the same identities as [[Nuclear magnetic moment#Calculating the magnetic moment|here]] and using the value {{nowrap|g<sup>(l)</sup><sub>p</sub> {{=}} {{val|1|ul=µN}}}}, we arrive at the following result, in nuclear magneton units
:<math>\mu =
{1\over 4 (j+1)}\left[({g^{(s)}}_p + {g^{(s)}}_n)\big(j(j+1) - l(l+1) + s(s+1)\big) + \big(j(j+1) + l(l+1) - s(s+1)\big)\right]</math>
 
For the {{nowrap|''s'' {{=}} 1}}, {{nowrap|''l'' {{=}} 0}} state ({{nowrap|''j'' {{=}} 1}}), we obtain
:<math>\mu = {1\over 2}({g^{(s)}}_p + {g^{(s)}}_n) = 0.879</math>
 
For the {{nowrap|''s'' {{=}} 1}}, {{nowrap|''l'' {{=}} 2}} state ({{nowrap|''j'' {{=}} 1}}), we obtain
:<math>\mu = -{1\over 4}({g^{(s)}}_p + {g^{(s)}}_n) + {3\over 4} = 0.310</math>
 
The measured value of the deuterium [[magnetic dipole moment]], is {{val|0.857|u=µN}}. This suggests that the state of the deuterium is indeed only approximately {{nowrap|''s'' {{=}} 1}}, {{nowrap|''l'' {{=}} 0}} state, and is actually a linear combination of (mostly) this state with {{nowrap|''s'' {{=}} 1}}, {{nowrap|''l'' {{=}} 2}} state.
 
The [[electric dipole]] is zero [[shell model|as usual]].
 
The measured electric [[quadrupole]] of the deuterium is {{val|0.2859|u=[[elementary charge|e]]·[[femtometer|fm]]<sup>2</sup>}}. While the order of magnitude is reasonable, since the deuterium radius is of order of 1 femtometer (see below) and its [[electric charge]] is e, the above model does not suffice for its computation. More specifically, the [[electric quadrupole]] does not get a contribution from the ''l'' =0 state (which is the dominant one) and does get a contribution from a term mixing the ''l'' =0 and the ''l'' =2 states, because the electric quadrupole [[operator (quantum mechanics)|operator]] does not [[commutator (quantum mechanics)|commute]] with [[angular momentum]].
The latter contribution is dominant in the absence of a pure {{nowrap|''l'' {{=}} 0}} contribution, but cannot be calculated without knowing the exact spatial form of the nucleons [[wavefunction]] inside the deuterium.
 
Higher magnetic and electric [[multipole moment]]s cannot be calculated by the above model, for similar reasons.
 
==Applications==
[[Image:Deuterium Ionized.JPG|thumb|right|350px|Ionized deuterium in a [[fusor]] reactor giving off its characteristic pinkish-red glow]]
[[Image:Deuterium lamp 1.png|thumb|right|350px|Emission spectrum of an ultraviolet [[deuterium arc lamp]]]]
Deuterium has a number of commercial and scientific uses. These include:
 
===Nuclear reactors===
Deuterium is used in [[Heavy water reactor|heavy water moderated fission reactors]], usually as liquid D<sub>2</sub>O, to slow neutrons without high neutron absorption of ordinary hydrogen.<ref>See [[neutron cross section#Typical cross sections]]</ref> This is a common commercial use for larger amounts of deuterium.
 
In [[research reactor]]s, liquid D<sub>2</sub> is used in [[cold source]]s to moderate neutrons to very low energies and wavelengths appropriate for [[neutron scattering|scattering experiments]].
 
Experimentally, deuterium is the most common nuclide used in [[nuclear fusion]] reactor designs, especially in combination with [[tritium]], because of the large reaction rate (or [[nuclear cross section]]) and high [[energy]] yield of the D–T reaction. There is an even higher-yield D–[[Helium-3|{{SimpleNuclide|Helium|3}}]] fusion reaction, though the [[breakeven]] point of D–{{SimpleNuclide|Helium|3}} is higher than that of most other fusion reactions; together with the scarcity of {{SimpleNuclide|Helium|3}}, this makes it implausible as a practical power source until at least D–T and D–D fusion reactions have been performed on a commercial scale. However, commercial nuclear fusion is not yet an accomplished technology.
 
===NMR spectroscopy===
{{See also|Proton NMR|Deuterium NMR}}
 
Deuterium is useful in hydrogen [[nuclear magnetic resonance spectroscopy]] ([[proton NMR]]). NMR ordinarily requires compounds of interest to be analyzed as dissolved in solution. Because of deuterium's nuclear spin properties which differ from the light hydrogen usually present in organic molecules, NMR spectra of hydrogen/protium are highly differentiable from that of deuterium, and in practice deuterium is not "seen" by an NMR instrument tuned to light-hydrogen. Deuterated solvents (including heavy water, but also compounds like deuterated chloroform, CDCl<sub>3</sub>) are therefore routinely used in NMR spectroscopy, in order to allow only the light-hydrogen spectra of the compound of interest to be measured, without solvent-signal interference.
 
Deuterium NMR spectra are especially informative in the solid state because of its relatively small quadrupole moment in comparison with those of bigger quadrupolar nuclei such as chlorine-35, for example.
 
===Tracing===
In [[chemistry]], [[biochemistry]] and [[environmental sciences]], deuterium is used as a non-radioactive, [[stable isotope|stable isotopic]] tracer, for example, in the [[doubly labeled water test]]. In [[chemical reaction]]s and [[metabolic pathway]]s, deuterium behaves somewhat similarly to ordinary hydrogen (with a few chemical differences, as noted). It can be distinguished from ordinary hydrogen most easily by its mass, using [[mass spectrometry]] or [[infrared spectrometry]]. Deuterium can be detected by [[femtosecond]] [[infrared]] spectroscopy, since the mass difference drastically affects the frequency of molecular vibrations; deuterium-carbon bond vibrations are found in locations free of other signals.
 
Measurements of small variations in the natural abundances of deuterium, along with those of the stable heavy oxygen isotopes <sup>17</sup>O and <sup>18</sup>O, are of importance in [[hydrology]], to trace the geographic origin of Earth's waters. The heavy isotopes of hydrogen and oxygen in rainwater (so-called [[meteoric water]]) are enriched as a function of the environmental temperature of the region in which the precipitation falls (and thus enrichment is related to mean latitude). The relative enrichment of the heavy isotopes in rainwater (as referenced to mean ocean water), when plotted against temperature falls predictably along a line called the [[global meteoric water line]] (GMWL). This plot allows samples of precipitation-originated water to be identified along with general information about the climate in which it originated. Evaporative and other processes in bodies of water, and also ground water processes, also differentially alter the ratios of heavy hydrogen and oxygen isotopes in fresh and salt waters, in characteristic and often regionally distinctive ways.<ref>{{cite web|url=http://web.archive.org/web/20070102124117/http://www.sahra.arizona.edu/programs/isotopes/oxygen.html |title=Oxygen – Isotopes and Hydrology |publisher=SAHRA |accessdate=2007-09-10}}</ref> The ratio of concentration of <sup>2</sup>H to <sup>1</sup>H is usually indicated with a delta as δ<sup>2</sup>H and the geographic patterns of these values are plotted in maps termed as isoscapes. Stable isotope are incorporated into plants and animals and an analysis of the ratios in a migrant bird or insect can help suggest a rough guide to their origins.<ref>{{cite book|title=Isoscapes: Understanding movement, pattern, and process on Earth through isotope mapping|first=Jason B. |last=West|publisher=Springer| year=2009}}</ref><ref>{{cite journal|last1=Hobson |first1=KA|last2=Van Wilgenburg |first2=SL|last3=Wassenaar |first3=LI|last4=Larson |first4=K |year=2012| title= Linking Hydrogen (δ2H) Isotopes in Feathers and Precipitation: Sources of Variance and Consequences for Assignment to Isoscapes. |journal=PLoS ONE |volume=7|issue=4| pages=e35137| doi=10.1371/journal.pone.0035137}}</ref>
 
===Contrast properties===
[[Neutron scattering]] techniques particularly profit from availability of deuterated samples: The H and D cross sections are very distinct and different in sign, which allows contrast variation in such experiments. Further, a nuisance problem of ordinary hydrogen is its large incoherent neutron cross section, which is nil for D. The substitution of deuterium atoms for hydrogen atoms thus reduces scattering noise.
 
Hydrogen is an important and major component in all materials of organic chemistry and life science, but it barely interacts with X-rays. As hydrogen (and deuterium) interact strongly with neutrons, neutron scattering techniques, together with a modern deuteration facility,<ref>{{cite web|url=http://nmi3.eu/about-nmi3/joint-research-activities/deuteration.html |title=NMI3 - Deuteration |publisher=NMI3 |accessdate=2012-01-23}}</ref> fills a niche in many studies of macromolecules in biology and many other areas.
 
===Nuclear weapons===
This is discussed below. It is notable that although most stars (including our Sun) generate energy over most of their lives by fusing hydrogen into heavier elements, such fusion of light hydrogen (protium) has never been successful in the conditions attainable on Earth. Thus, all artificial fusion, including the hydrogen fusion that occurs in so-called hydrogen bombs, requires heavy hydrogen (either tritium or deuterium, or both) in order for the process to work.
 
==History==
 
=== Suspicion of lighter element isotopes ===
The existence of nonradioactive isotopes of lighter elements had been suspected in studies of neon as early as 1913, and proven by mass spectrometry of light elements in 1920. The prevailing theory at the time, however, was that the isotopes were due to the existence of differing numbers of "nuclear electrons" in different atoms of an element. It was expected that hydrogen, with a measured average atomic mass very close to {{val|1|u=u}}, the known mass of the proton, always had a nucleus composed of a single proton (a known particle), and therefore could not contain any nuclear electrons without losing its charge entirely. Thus, hydrogen could have no heavy isotopes.
 
===Deuterium detected===
<!--Deuterium was predicted in 1926 by [[Walter Russell]], using his "spiral" periodic table{{Citation needed|date=August 2010}}, and independently by [[Charles Janet]] in 1928.<ref>{{cite journal | last1 =Stewart | first1 =Philip J. | title =Charles Janet: unrecognized genius of the periodic system | journal =Foundations of Chemistry | volume =12 | page =5 | year =2009 | doi =10.1007/s10698-008-9062-5}}</ref>-->
[[File:Urey.jpg|thumb|140px|Harold Urey]]
It was first detected spectroscopically in late 1931 by [[Harold Urey]], a chemist at [[Columbia University]]. Urey's collaborator, [[Ferdinand Brickwedde]], [[Distillation|distilled]] five [[liter]]s of [[cryogenics|cryogenically produced]] [[liquid hydrogen]] to {{val|1|ul=mL}} of liquid, using the low-temperature physics laboratory that had recently been established at the National Bureau of Standards in Washington, D.C. (now the [[National Institute of Standards and Technology]]). The technique had previously been used to isolate heavy isotopes of neon. The cryogenic boiloff technique concentrated the fraction of the mass-2 isotope of hydrogen to a degree that made its spectroscopic identification unambiguous.<ref>{{cite journal | last1 = Brickwedde | first1 = Ferdinand G. | title = Harold Urey and the discovery of deuterium | journal = Physics Today | volume = 35 | page = 34 | year = 1982 | doi = 10.1063/1.2915259|bibcode = 1982PhT....35i..34B | issue = 9 }}</ref><ref>{{cite journal | last1 =Urey | first1 =Harold | last2 =Brickwedde | first2 =F. | last3 =Murphy | first3 =G. | title =A Hydrogen Isotope of Mass 2 | journal =Physical Review | volume =39 | page =164 | year =1932 | doi =10.1103/PhysRev.39.164|bibcode = 1932PhRv...39..164U }}</ref>
 
===Naming of the isotope and Nobel Prize===
Urey created the names protium, deuterium, and tritium in an article published in 1934.  The name is based in part on advice from [[G. N. Lewis]] who had proposed the name "deutium".  The name is derived from the Greek deuteros (second), and the nucleus to be called "deuteron" or "deuton". Isotopes and new elements were traditionally given the name that their discoverer decided.  Some British chemists, like [[Ernest Rutherford]], wanted the isotope to be called "diplogen", from the Greek diploos (double), and the nucleus to be called diplon.<ref name="diplogen">Dan O'Leary "The deeds to deuterium" Nature Chemistry 4, 236 (2012). {{doi|10.1038/nchem.1273}}. {{Cite news|title = Science: Deuterium v. Diplogen|date = 19 February 1934|work = [[Time (magazine)|Time]]|url = http://www.time.com/time/magazine/article/0,9171,746988,00.html}}</ref>
 
The amount inferred for normal abundance of this heavy isotope of hydrogen was so small (only about 1 atom in 6400 hydrogen atoms in ocean water (156 deuteriums per million hydrogens) that it had not noticeably affected previous measurements of (average) hydrogen atomic mass. This explained why it hadn't been experimentally suspected before. Urey was able to concentrate water to show partial enrichment of deuterium. Lewis had prepared the first samples of pure heavy water in 1933.  The discovery of deuterium, coming before the discovery of the [[neutron]] in 1932, was an experimental shock to theory, but when the neutron was reported, making deuterium's existence more explainable, deuterium won Urey the [[Nobel Prize in chemistry]] in 1934.  Lewis was embittered by being passed over for this recognition given to his former student.<ref name="diplogen"/>
 
==="Heavy water" experiments in World War II===
{{Main|Heavy water}}
Shortly before the war, [[Hans von Halban]] and [[Lew Kowarski]] moved their research on neutron moderation from France to England, smuggling the entire global supply of heavy water (which had been made in Norway) across in twenty-six steel drums.<ref>{{cite web
|last =Sherriff
|first =Lucy
|title =Royal Society unearths top secret nuclear research
|work =The Register
|publisher =Situation Publishing Ltd.
|date =1 June 2007
|url =http://www.theregister.co.uk/2007/06/01/royal_soc_secret_physics/
|accessdate =2007-06-03}}</ref><ref>{{cite web
|title =The Battle for Heavy Water Three physicists' heroic exploits
|work =CERN Bulletin
|publisher =European Organization for Nuclear Research
|date =1 April 2002
|url =http://bulletin.cern.ch/eng/articles.php?bullno=14/2002&base=art
|accessdate =2007-06-03}}</ref>
 
During [[World War II]], [[Nazi Germany]] was known to be conducting experiments using heavy water as moderator for a [[nuclear reactor]] design. Such experiments were a source of concern because they might allow them to produce [[plutonium]] for an [[atomic bomb]]. Ultimately it led to the [[Western Allies|Allied]] operation called the "[[Norwegian heavy water sabotage]]", the purpose of which was to destroy the [[Vemork]] deuterium production/enrichment facility in [[Norway]]. At the time this was considered important to the potential progress of the war.
 
After World War II ended, the Allies discovered that Germany was not putting as much serious effort into the program as had been previously thought.{{Citation needed|date=March 2009}} The Germans had completed only a small, partly built experimental reactor (which had been hidden away). By the end of the war, the Germans did not even have a fifth of the amount of heavy water needed to run the reactor, partially due to the Norwegian heavy water sabotage operation.{{Citation needed|date=March 2009}} However, even had the Germans succeeded in getting a reactor operational (as the U.S. did with a graphite reactor in late 1942), they would still have been at least several years away from development of an [[atomic bomb]] with maximal effort. The engineering process, even with maximal effort and funding, required about two and a half years (from first critical reactor to bomb) in both the U.S. and [[U.S.S.R]], for example.
 
=== Deuterium in thermonuclear weapons ===
{{main|Teller-Ulam design|thermonuclear weapon}}
[[Image:Ivy Mike Sausage device.jpg|right|thumb|300px|A view of the ''Sausage'' device casing of the [[Ivy Mike]] [[hydrogen bomb]], with its instrumentation and cryogenic equipment attached. This bomb held a cryogenic Dewar flask containing room for as much as 160 kilograms of liquid deuterium. The bomb was 20 feet tall. Note the seated man at the right of the photo for the scale.]]
 
The 62-ton [[Ivy Mike]] device built by the United States and exploded on 1 November 1952, was the first fully successful "[[hydrogen bomb]]" or [[thermonuclear bomb]]. In this context, it was the first bomb in which most of the energy released came from [[nuclear reaction]] stages that followed the primary [[nuclear fission]] stage of the [[atomic bomb]]. The Ivy Mike bomb was a factory-like building, rather than a deliverable weapon. At its center, a very large cylindrical, insulated [[vacuum flask]] or [[cryostat]], held [[cryogenic]] liquid deuterium in a volume of about 1000 [[liter]]s (160 kilograms in mass, if this volume had been completely filled). Then, a conventional [[atomic bomb]] (the "primary") at one end of the bomb was used to create the conditions of extreme temperature and pressure that were needed to set off the [[thermonuclear reaction]].
 
Within a few years, so-called "dry" hydrogen bombs were developed that did not need cryogenic hydrogen. Released information suggests that all [[thermonuclear weapon]]s built since then contain [[chemical compound]]s of deuterium and lithium in their secondary stages. The material that contains the deuterium is mostly [[lithium deuteride]], with the lithium consisting of the isotope [[lithium-6]]. When the lithium-6 is bombarded with fast [[neutron]]s from the atomic bomb, [[tritium]] ([[hydrogen-3]]) is produced, and then the deuterium and the tritium quickly engage in [[thermonuclear fusion]], releasing abundant energy, [[helium-4]], and even more free neutrons.
 
== Data for elemental deuterium ==
Formula: D<sub>2</sub> or {{Nuclide2|Hydrogen|2|link=no}}<sub>2</sub>
 
*Density: {{val|0.180|u=kg/m<sup>3</sup>}} at [[Standard conditions for temperature and pressure|STP]] ({{val|0|u=degC}}, {{val|101.325|u=kPa}}).
*Atomic weight: {{val|fmt=commas|2.0141017926|u=u}}.
*Mean abundance in ocean water (from [[Vienna Standard Mean Ocean Water|VSMOW]]) 155.76 ± 0.1 ppm (a ratio of 1 part per approximately 6420 parts), that is, about {{val|0.015|s=%}} of the atoms in a sample (by number, not weight)
 
Data at approximately {{val|18|u=K}} for D<sub>2</sub> ([[triple point]]):
*Density:
**Liquid: {{val|162.4|u=kg/m<sup>3</sup>}}
**Gas: {{val|0.452|u=kg/m<sup>3</sup>}}
*Viscosity: {{val|12.6|u=[[pascal second|µPa·s]]}} at {{val|300|u=K}} (gas phase)
*Specific heat capacity at constant pressure ''c<sub>p</sub>'':
**Solid: {{val|fmt=commas|2950|u=J/(kg·K)}}
**Gas: {{val|fmt=commas|5200|u=J/(kg·K)}}
 
==Anti-deuterium==<!-- This section is linked from [[Antihydrogen]] -->
 
An '''antideuteron''' is the antiparticle of the nucleus of deuterium, consisting of an [[antiproton]] and an [[antineutron]]. The antideuteron was first produced in 1965 at the [[Proton Synchrotron]] at [[CERN]]<ref>{{Cite journal|author = Massam, T|year = 1965 |title = Experimental observation of antideuteron production |journal = Il Nuovo Cimento |volume = 39|pages = 10–14 |doi = 10.1007/BF02814251|last2 = Muller|first2 = Th.|last3 = Righini|first3 = B.|last4 = Schneegans|first4 = M.|last5 = Zichichi|first5 = A.|bibcode = 1965NCimS..39...10M }}</ref> and the [http://www.bnl.gov/bnlweb/facilities/AGS.asp Alternating Gradient Synchrotron] at [[Brookhaven National Laboratory]].<ref>{{Cite journal|author = Dorfan, D. E|date=June 1965|title = Observation of Antideuterons|journal = Phys. Rev. Lett.|volume = 14|issue = 24 |pages = 1003–1006| doi = 10.1103/PhysRevLett.14.1003|last2 = Eades|first2 = J.|last3 = Lederman|first3 = L. M.|last4 = Lee|first4 = W.|last5 = Ting|first5 = C. C.|bibcode=1965PhRvL..14.1003D}}</ref> A complete atom, with a [[positron]] orbiting the nucleus, would be called ''antideuterium'', but as of 2005 antideuterium has not yet been created. The proposed symbol for antideuterium is {{Element2|anti=yes|deuterium}}, that is, D with an overbar.<ref>{{Cite journal|doi = 10.1016/S0370-2693(97)00870-8|arxiv = astro-ph/9705110|title = The production of anti-matter in our galaxy|year = 1997|last1 = Chardonnet|first1 = P|journal = Physics Letters B|volume = 409|page = 313|bibcode = 1997PhLB..409..313C|last2 = Orloff|first2 = Jean|last3 = Salati|first3 = Pierre }}</ref>
 
==See also==
{{Isotope|element=hydrogen
|lighter=[[Hydrogen atom|hydrogen-1]]
|heavier=[[Tritium|hydrogen-3]]
|before=[[Dineutron|neutronium-2]]<br>[[Diproton|helium-2]]
|after=Stable
}}
*[[Isotopes of hydrogen]]
*[[Nuclear fusion]]
*[[Tokamak]]
*[[Tritium]]
*[[Heavy water]]
 
==References==
{{Reflist|2}}
 
==External links==
{{Wiktionary}}
*[http://atom.kaeri.re.kr/ Nuclear Data Evaluation Lab]
*{{Cite journal|url=http://www.newscientist.com/article.ns?id=dn7315 |title=Desktop nuclear fusion demonstrated with deuterium gas|journal=New Scientist|date=27 April 2005 |first=Justin|last=Mullins |accessdate=2007-09-10}}
*[http://alsos.wlu.edu/qsearch.aspx?browse=science/Deuterium Annotated bibliography for Deuterium from the Alsos Digital Library for Nuclear Issues]
*[http://space.com/scienceastronomy/060821_mystery_monday.html Missing Gas Found in Milky Way]. Space.com
 
[[Category:Isotopes of hydrogen]]
[[Category:Environmental isotopes]]
[[Category:Nuclear materials]]
[[Category:Neutron moderators]]
[[Category:Nuclear fusion fuels]]

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