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en>Yobot: WP:CHECKWIKI error fixes using AWB (10093)

2014-05-05T11:11:02Z

WP:CHECKWIKI error fixes using AWB (10093)

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	In [[mathematics]], more specifically in the area of [[Abstract algebra\|modern algebra]] known as [[field theory (mathematics)\|field theory]], the '''primitive element theorem''' or '''Artin's theorem on primitive elements''' is ~~a result characterizing~~ the finite degree [[field extension]]s that possess a '''primitive element'''. More specifically, the primitive element theorem characterizes those finite degree extensions <math>E\supseteq F</math> such that there exists <math>\alpha\in E</math> with <math>E=F[\alpha]=F(\alpha)</math>.		Gabrielle Straub is what the person can call me although it's not the numerous feminine of names. Fish keeping is what I follow every week. Managing people is my day job now. My house is now with regard to South Carolina. Go to my web to find out more: http://prometeu.net<br><br>Feel free to surf to my web page ... [http://prometeu.net hack clash of clans]

	~~== Terminology ==~~
	~~Let <math>E\supseteq F</math> be an arbitrary field extension. An element <math>\alpha\in E</math> is said to be a ''primitive element'' for <math>E\supseteq F</math> when~~

	~~:<math>E=F(\alpha).</math>~~

	~~In this situation, the extension <math>E\supseteq F</math> is referred to as a ''[[simple extension]]''. Then every element ''x'' of ''E''~~ can ~~be written in the form~~

	~~:<math>x=f_{n-1}{\alpha}^{n-1}+\cdots+f_1{\alpha}+f_0</math> where <math>f_i\in F</math>~~

	~~for all ''i'', and <math>\alpha\in E</math> is fixed. That is, if <math>E\supseteq F</math> is separable of degree ''n'', there exists <math>\alpha\in E</math> such that the set~~

	~~:<math>\{1,\alpha,\cdots,{\alpha}^{n-1}\}</math>~~

	~~is a basis for ''E'' as a [[vector space]] over ''F''.~~

	For instance, the extensions <math>\mathbb{Q}(\sqrt{2})\supseteq \mathbb{Q}</math> and <math>\mathbb{Q}(x)\supseteq \mathbb{Q}</math> are simple extensions with primitive elements <math>\sqrt{2}</math> and ''x'', respectively (<math>\mathbb{Q}(x)</math> denotes the field of rational functions in the indeterminate ''x'' over <math>\mathbb{Q}</math>).

	~~== Existence statement ==~~

	The interpretation of the theorem changed with the formulation of the theory of [[Emil Artin]], around 1930. From the time of Galois, the role of primitive elements had been to represent a [[splitting field]] as generated by a single element. This (arbitrary) choice of such an element was bypassed in Artin's ~~treatment.<ref>Israel Kleiner, ''A History of Abstract Algebra'' (2007), p. 64.</ref> At~~ the ~~same time, considerations~~ of ~~construction of such an element receded: the theorem becomes an [[existence theorem]].~~

	~~The following theorem of Artin then takes the place of the classical ''primitive element theorem''.~~

	~~;Theorem~~

	Let <math>E\supseteq F</math> be a finite degree field extension. Then <math>E=F(\alpha)</math> for some element <math>\alpha\in E</math> if and only if there exist only finitely many intermediate fields ''K'' with <math>E\supseteq K\supseteq F</math>.

	~~A corollary to the theorem~~ is ~~then the primitive element theorem in the more traditional sense (where separability was usually tacitly assumed):~~

	~~;Corollary~~

	~~Let <math>E\supseteq F</math> be a finite degree [[separable extension]]. Then <math>E=F(\alpha)</math> for some <math>\alpha\in E</math>.~~

	~~The corollary applies to [[algebraic number field]]s, i.e. finite extensions of the rational numbers '''Q''', since '''Q''' has [[characteristic (algebra)\|characteristic]] 0 and therefore~~ every ~~extension over '''Q''' is separable~~.

	~~==Counterexamples==~~

	~~For non-separable extensions, necessarily in [[characteristic p]] with ''p'' a prime number, then at least when the degree [''L'' : ''K'']~~ is ''p'', ''L'' / ''K'' has a primitive element, because there are no intermediate subfields. When [''L'' : ''K''] = ''p''<sup>2</sup>, there may not be a primitive element (and therefore there are infinitely many intermediate fields). ~~This happens, for example if ''K''~~ is

	~~:''F<sub>p</sub>''(''T'', ''U''),~~

	~~the field of rational functions in two indeterminates ''T'' and ''U'' over the [[finite field]]~~ with ''p'' elements, and ''L'' is obtained from ''K'' by adjoining a ''p''-th root of ''T'', and of ''U''. In fact one can see that for any α in ''L'', the element ''α''<sup>''p''</sup> lies in ''K'', but a primitive element must have degree ''p''<sup>2</sup> over ''K''.

	~~==Constructive results==~~

	Generally, the set of all primitive elements for a finite separable extension ''L'' / ''K'' is the complement of a finite collection of proper ''K''-subspaces of ''L'', namely the intermediate fields. This statement says nothing for the case of [[finite field]]s, for which there is a computational theory dedicated to ~~finding a generator of the [[multiplicative group]] of the field (a [[cyclic group]]), which is ''a fortiori'' a primitive element~~. ~~Where ''K'' is infinite, a [[pigeonhole principle]] proof technique considers the linear subspace generated by two elements and proves that there are only finitely many linear combinations~~

	~~:<math>\gamma = \alpha + c \beta\ </math>~~

	~~with ''c'' in ''K'', that fail~~ to generate the subfield containing both elements. This is almost immediate as a way of showing how Artin's result implies the classical result, and a bound for the number of exceptional ''c'' in terms of the number of intermediate fields results (this number being something that can be bounded itself by Galois theory and ''a priori''). Therefore in this case trial-and-error is a possible practical method to find ~~primitive elements. See the Example.~~

	~~== Example ==~~
	~~It is not, for example, immediately obvious that if one adjoins to the field <math>\mathbb{Q}</math> of [[rational number]]s roots of both [[polynomial]]s~~

	:~~<math>x^2 - 2\ </math>~~

	~~and~~

	:~~<math>x^2 - 3,\ <~~/~~math>~~

	~~say <math>\sqrt{2}<~~/~~math> and~~ <~~math~~>~~\sqrt{3}~~<~~/math~~> ~~respectively,~~ to get a field ''K'' = <math>\mathbb{Q}(\sqrt{2},\sqrt{3})</math> of [[Degree of a field extension\|degree]] 4 over <math>\mathbb{Q}</math>, that the extension is simple and there exists a primitive element γ in ''K'' so that ''K'' = <math>\mathbb{Q}(\gamma)</math>. One can in fact check that with

	~~:<math>\gamma = \sqrt{2} + \sqrt{3} </math>~~

	the powers γ<sup> ''i''</sup> for 0 ≤ ''i'' ≤ 3 can be written out as [[linear combination]]s of 1, <math>\sqrt{2}</math>, <math>\sqrt{3}</math>, and <math>\sqrt{2}\sqrt{3}=\sqrt{6}</math> with integer coefficients. Taking these as a [[system of linear equations]], or by factoring, one can solve for <math>\sqrt{2}</math> and <math>\sqrt{3}</math> over <math>\mathbb{Q}(\gamma)</math> (one gets, for instance, <math>\sqrt{2} = \scriptstyle\frac{\gamma^3-9\gamma}2</math>), which implies that this choice of γ is indeed a primitive element in this example. A simpler argument, assuming the knowledge of all the subfields as given by [[Galois theory]], is to note the independence of 1, <math>\sqrt{2}</math>, <math>\sqrt{3}</math>, and <math>\sqrt{2}\sqrt{3}</math> over the rationals; this shows that the subfield generated by γ cannot be that generated by <math>\sqrt{2}</math> or <math>\sqrt{3}</math>, nor in fact that generated by <math>\sqrt{2}\sqrt{3}</math>, exhausting all the subfields of degree 2. ~~Therefore it must be the whole field~~.

	~~== See also ==~~
	* [[Primitive element (finite field)]]
	* [http://www.mathreference.com/fld-sep,pet.~~html The primitive element theorem at mathreference.com]~~
	* [http://~~planetmath~~.~~org/ProofOfPrimitiveElementTheorem The primitive element theorem at planetmath.org]~~
	* [http://www.math.cornell.edu/~kbrown/6310/primitive.pdf The primitive element theorem on Ken Brown's website (pdf file)]

	~~==References==~~
	~~<references />~~

	~~==Notes==~~
	~~{{Reflist}}~~

	~~[[Category:Field theory]]~~
	~~[[Category:Theorems in abstract algebra]~~]

en>Kasterma: Added references, and removed the lack of references warning.

2013-04-28T11:19:44Z

Added references, and removed the lack of references warning.

← Older revision		Revision as of 13:19, 28 April 2013
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	I'~~m Sharron~~ (22) ~~from Puch~~, ~~Austria~~. <br>I'~~m learning French literature~~ at a ~~local university~~ and I'~~m just about~~ to ~~graduate~~.<br>~~I have~~ a ~~part time job~~ in a ~~backery~~.<br><br>~~Feel free~~ to ~~visit my web site~~ :: [http://~~bhbiniekcje~~.pl/~~oferta~~/~~uszczelnianie-scian-szczelinowych~~/ ~~najlepsze izolacje tarasów~~]		In [[mathematics]], more specifically in the area of [[Abstract algebra\|modern algebra]] known as [[field theory (mathematics)\|field theory]], the '''primitive element theorem''' or '''Artin's theorem on primitive elements''' is a result characterizing the finite degree [[field extension]]s that possess a '''primitive element'''. More specifically, the primitive element theorem characterizes those finite degree extensions <math>E\supseteq F</math> such that there exists <math>\alpha\in E</math> with <math>E=F[\alpha]=F(\alpha)</math>.

			== Terminology ==
			Let <math>E\supseteq F</math> be an arbitrary field extension. An element <math>\alpha\in E</math> is said to be a ''primitive element'' for <math>E\supseteq F</math> when

			:<math>E=F(\alpha).</math>

			In this situation, the extension <math>E\supseteq F</math> is referred to as a ''[[simple extension]]''. Then every element ''x'' of ''E'' can be written in the form

			:<math>x=f_{n-1}{\alpha}^{n-1}+\cdots+f_1{\alpha}+f_0</math> where <math>f_i\in F</math>

			for all ''i'', and <math>\alpha\in E</math> is fixed. That is, if <math>E\supseteq F</math> is separable of degree ''n'', there exists <math>\alpha\in E</math> such that the set

			:<math>\{1,\alpha,\cdots,{\alpha}^{n-1}\}</math>

			is a basis for ''E'' as a [[vector space]] over ''F''.

			For instance, the extensions <math>\mathbb{Q}(\sqrt{2})\supseteq \mathbb{Q}</math> and <math>\mathbb{Q}(x)\supseteq \mathbb{Q}</math> are simple extensions with primitive elements <math>\sqrt{2}</math> and ''x'', respectively (<math>\mathbb{Q}(x)</math> denotes the field of rational functions in the indeterminate ''x'' over <math>\mathbb{Q}</math>).

			== Existence statement ==

			The interpretation of the theorem changed with the formulation of the theory of [[Emil Artin]], around 1930. From the time of Galois, the role of primitive elements had been to represent a [[splitting field]] as generated by a single element. This (arbitrary) choice of such an element was bypassed in Artin's treatment.<ref>Israel Kleiner, ''A History of Abstract Algebra'' (2007), p. 64.</ref> At the same time, considerations of construction of such an element receded: the theorem becomes an [[existence theorem]].

			The following theorem of Artin then takes the place of the classical ''primitive element theorem''.

			;Theorem

			Let <math>E\supseteq F</math> be a finite degree field extension. Then <math>E=F(\alpha)</math> for some element <math>\alpha\in E</math> if and only if there exist only finitely many intermediate fields ''K'' with <math>E\supseteq K\supseteq F</math>.

			A corollary to the theorem is then the primitive element theorem in the more traditional sense (where separability was usually tacitly assumed):

			;Corollary

			Let <math>E\supseteq F</math> be a finite degree [[separable extension]]. Then <math>E=F(\alpha)</math> for some <math>\alpha\in E</math>.

			The corollary applies to [[algebraic number field]]s, i.e. finite extensions of the rational numbers '''Q''', since '''Q''' has [[characteristic (algebra)\|characteristic]] 0 and therefore every extension over '''Q''' is separable.

			==Counterexamples==

			For non-separable extensions, necessarily in [[characteristic p]] with ''p'' a prime number, then at least when the degree [''L'' : ''K''] is ''p'', ''L'' / ''K'' has a primitive element, because there are no intermediate subfields. When [''L'' : ''K''] = ''p''<sup>2</sup>, there may not be a primitive element (and therefore there are infinitely many intermediate fields). This happens, for example if ''K'' is

			:''F<sub>p</sub>''(''T'', ''U''),

			the field of rational functions in two indeterminates ''T'' and ''U'' over the [[finite field]] with ''p'' elements, and ''L'' is obtained from ''K'' by adjoining a ''p''-th root of ''T'', and of ''U''. In fact one can see that for any α in ''L'', the element ''α''<sup>''p''</sup> lies in ''K'', but a primitive element must have degree ''p''<sup>2</sup> over ''K''.

			==Constructive results==

			Generally, the set of all primitive elements for a finite separable extension ''L'' / ''K'' is the complement of a finite collection of proper ''K''-subspaces of ''L'', namely the intermediate fields. This statement says nothing for the case of [[finite field]]s, for which there is a computational theory dedicated to finding a generator of the [[multiplicative group]] of the field (a [[cyclic group]]), which is ''a fortiori'' a primitive element. Where ''K'' is infinite, a [[pigeonhole principle]] proof technique considers the linear subspace generated by two elements and proves that there are only finitely many linear combinations

			:<math>\gamma = \alpha + c \beta\ </math>

			with ''c'' in ''K'', that fail to generate the subfield containing both elements. This is almost immediate as a way of showing how Artin's result implies the classical result, and a bound for the number of exceptional ''c'' in terms of the number of intermediate fields results (this number being something that can be bounded itself by Galois theory and ''a priori''). Therefore in this case trial-and-error is a possible practical method to find primitive elements. See the Example.

			== Example ==
			It is not, for example, immediately obvious that if one adjoins to the field <math>\mathbb{Q}</math> of [[rational number]]s roots of both [[polynomial]]s

			:<math>x^2 - 2\ </math>

			and

			:<math>x^2 - 3,\ </math>

			say <math>\sqrt{2}</math> and <math>\sqrt{3}</math> respectively, to get a field ''K'' = <math>\mathbb{Q}(\sqrt{2},\sqrt{3})</math> of [[Degree of a field extension\|degree]] 4 over <math>\mathbb{Q}</math>, that the extension is simple and there exists a primitive element γ in ''K'' so that ''K'' = <math>\mathbb{Q}(\gamma)</math>. One can in fact check that with

			:<math>\gamma = \sqrt{2} + \sqrt{3} </math>

			the powers γ<sup> ''i''</sup> for 0 ≤ ''i'' ≤ 3 can be written out as [[linear combination]]s of 1, <math>\sqrt{2}</math>, <math>\sqrt{3}</math>, and <math>\sqrt{2}\sqrt{3}=\sqrt{6}</math> with integer coefficients. Taking these as a [[system of linear equations]], or by factoring, one can solve for <math>\sqrt{2}</math> and <math>\sqrt{3}</math> over <math>\mathbb{Q}(\gamma)</math> (one gets, for instance, <math>\sqrt{2} = \scriptstyle\frac{\gamma^3-9\gamma}2</math>), which implies that this choice of γ is indeed a primitive element in this example. A simpler argument, assuming the knowledge of all the subfields as given by [[Galois theory]], is to note the independence of 1, <math>\sqrt{2}</math>, <math>\sqrt{3}</math>, and <math>\sqrt{2}\sqrt{3}</math> over the rationals; this shows that the subfield generated by γ cannot be that generated by <math>\sqrt{2}</math> or <math>\sqrt{3}</math>, nor in fact that generated by <math>\sqrt{2}\sqrt{3}</math>, exhausting all the subfields of degree 2. Therefore it must be the whole field.

			== See also ==
			* [[Primitive element (finite field)]]
			* [http://www.mathreference.com/fld-sep,pet.html The primitive element theorem at mathreference.com]
			* [http://planetmath.org/ProofOfPrimitiveElementTheorem The primitive element theorem at planetmath.org]
			* [http://www.math.cornell.edu/~kbrown/6310/primitive.pdf The primitive element theorem on Ken Brown's website (pdf file)]

			==References==
			<references />

			==Notes==
			{{Reflist}}

			[[Category:Field theory]]
			[[Category:Theorems in abstract algebra]]

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2010-06-06T19:44:09Z

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I'm Sharron (22) from Puch, Austria. <br>I'm learning French literature at a local university and I'm just about to graduate.<br>I have a part time job in a backery.<br><br>Feel free to visit my web site :: [http://bhbiniekcje.pl/oferta/uszczelnianie-scian-szczelinowych/ najlepsze izolacje tarasów]